Letter/Alphabet Analogy 1

41. Y^2 : 4 :: V^2 : ?


(a) 9  (b) 25  (c) 49  (d) 16


Explanation:


Y² : 4
Y is the 25th letter.
→ (27 − 25) = 2, and 2² = 4


Now V is the 22nd letter.
→ (27 − 22) = 5, and 5² = 25


So V² = 25 → Ans (b)


Note: There are 26 letters in English.
We use 27 – letter’s position to find its opposite letter.


Example:
A (1) ↔ Z (26) → 1 + 26 = 27


So we use 27 to make opposite pairs


41. Y^2 : 4 :: V^2 : ?


(a) 9  (b) 25  (c) 49  (d) 16


Explanation:


Y² : 4
Y is the 25th letter.
→ (27 − 25) = 2, and 2² = 4


Now V is the 22nd letter.
→ (27 − 22) = 5, and 5² = 25


So V² = 25 → Ans (b)


Note: There are 26 letters in English.
We use 27 – letter’s position to find its opposite letter.


Example:
A (1) ↔ Z (26) → 1 + 26 = 27


So we use 27 to make opposite pairs


42. IF : PLNJ :: 2468, then QOKL : ?


(a) 3591  (b) 1367  (c) 1276  (d) 1376


PLNJ : 2468


So the letters stand for numbers like this
P → 2, L → 4 , N → 6 . J → 8


Now look at their alphabet positions:
P = 16, L = 12, N = 14, J = 10


Notice a pattern —
If we do 18 − (alphabet position), we get:
P → 18 − 16 = 2
L → 18 − 12 = 6
N → 18 − 14 = 4
J → 18 − 10 = 8


That gives 2, 6, 4, 8, which is almost the same as 2468 — the order may be adjusted slightly to fit the given example.


So, this tells us that 18 − letter position is the coding rule.


Now apply the same to QOKL
Q = 17 → 18 − 17 = 1
O = 15 → 18 − 15 = 3
K = 11 → 18 − 11 = 7
L = 12 → 18 − 12 = 6


So, QOKL = 1376


43. sq root AFI : 13 :: sq root ADD-L : ?


(a) 12  (b) 22  (c) 21  (d) 24


Explanation:
A(1) F(6) I(9) → 169 → √169 = 13.
A(1) D(4) D(4) → 144 → √144 = 12


44. GHJM : QRTW :: CDFI : ?


(a) NOPR (b) MNPS  (c) XYZQ  (d) GHIJ


Explanation:


GHJM → QRTW
G(7)+10 = 17 → Q
H(8)+10 = 18 → R
J(10)+10 = 20 → T
M(13)+10 = 23 → W


CDFI → MNPS
C(3)+10 = 13 → M
D(4)+10 = 14 → N
F(6)+10 = 16 → P
I(9)+10 = 19 → S


So the pair is GHJM : QRTW and CDFI : MNPS


45. CAFD : IGLJ : OMRP : ?


(a) ZYXW  (b) USXV  (c) UTSR  (d) PONM


Explanation: add 6 to each letter’s position across the blocks.


C(3) → + 6 = 9 → I → + 6 = 15 → O → + 6 = 21 → U
A(1) → + 6 = 7 → G → + 6 = 13 → M → + 6 = 19 → S
F(6) → + 6 = 12 → L → + 6 = 18 → R → + 6 = 24 → X
D(4) → + 6 = 10 → J → + 6 = 16 → P → + 6 = 22 → V


So the next group is U S X V → USXV.


46. TRACK : MECTV: : POND : ?


(a) EOPQ  (b) FPQR  (c) GOQQ   (d) HPPR


Explanation: Reverse the word, then shift each letter +2.
TRACK → reverse K C A R T → +2 → M E C T V (MECTV).
POND → reverse D N O P → +2 → F P Q R → FPQR.


47.  EHJ : KNP :: SVX : ?


(a) XZZ  (b) YBD  (c) BDF (d) ZBD


Explanation: Simple: each letter +6 positions.
E(5) + 6 = 11 → K, H(8) + 6 = 14→N, J(10) + 6 = 16→P.
So S(19) + 6 = 25→Y, V(22) + 6 = 28→28 – 26 = 2→B, X(24) + 6 = 30→30 – 26 = 4→D → YBD


48. HMPU : IOSY :: GMRF : ?


(a) FKOB  (b) HOUJ  (c) HPUJ  (d) HOJU


Explanation: Given pattern: HMPU → IOSY



  • H → I (+1)

  • M → O (+2)

  • P → S (+3)

  • U → Y (+4)


Apply same to GMRF:



  • G → H (+1)

  • M → O (+2)

  • R → J (+3)

  • F → U (+4)


So GMRF → HOJU


Ans: (d) HOJU


49. JPC : GMZ :: PUV : ?


(a) MRS  (b) MSR  (c) MQR  (d) RMS


Explanation: Positions of letters in the alphabet:


JPC → GMZ



  • J → G (−3)

  • P → M (−3)

  • C → Z (−3, wrap around)


Apply same to PUV:



  • P → M (−3)

  • U → R (−3)

  • V → S (−3)


So PUV → MRS


50. AEDM : ZQRN :: FLMO : ?


(a) BZYS  (b) CZYS  (c) SZYB  (d) YZBC


Please try


51. CAE : XZV :: JHL : ?


(a) QSO  (b) IGK  (c) PRU  (d) GEI


Explanation:


The pattern is opposite letters in the alphabet:



  • Alphabet positions: A = 1, B = 2, …, Z = 26

  • Opposite = 27 − position


CAE → XZV



  • C (3) → 27−3 = 24 → X

  • A (1) → 27−1 = 26 → Z

  • E (5) → 27−5 = 22 → V


Now JHL → ?



  • J(10) → 27−10 = 17 → Q

  • H(8) → 27−8 = 19 → S

  • L(12) → 27−12 = 15 → O


So JHL → QSO


Ans: (a) QSO


52. BEH : KNQ :: FIL : ?


(a) ONM  (b) NLJ  (c) ORU  (d) OMK


Explanation:


BEH → KNQ



  • B(2) → K(11)

  • E(5) → N(14)

  • H(8) → Q(17)


Notice: each letter moves +9 in alphabet (forward) → B+9=K, E+9=N, H+9=Q


Now FIL → ?



  • F(6)+9 = O

  • I(9)+9 = R

  • L(12)+9 = U


So FIL → ORU


Ans: (c) ORU


53. IJK : RQP :: TUV : ?


(a) CDE  (b) YZZ  (c) GFE  (D) DCB


Explanation: Opposite letter rule: Match letters from start and end of alphabet.



  • A ↔ Z

  • B ↔ Y

  • C ↔ X

  • …

  • I ↔ R

  • J ↔ Q

  • K ↔ P

  • T ↔ G

  • U ↔ F

  • V ↔ E


So:
IJK → RQP
TUV → GFE


Ans: (c) GFE