15. Find:- Ex.1) 1+2+3+...+10Â Â Ex. 2) 1+2+3+...+100 Ex. 3) 1+2+3+...+1000Â Ex. 4)Â 1+2+3+...+99
This Superfast Technique is a shortcut trick for finding the sum of the first n natural numbers quickly.
General Formula: S = n(n+1)/2
where n is the last number.
Understanding the Trick (Superfast Method)
Rule:
- Divide the last number (n) by 2
- Write the result twice (concatenate the digits)
Ex. 1: 1+2+3+...+10
· Step 1: 10/2=5
· Step 2: Write 5 twice → 55
· Answer: 55
Ex. 2: 1+2+3+...+100
· Step 1: 100/2=50
· Step 2: Write 50 twice → 5050
· Answer: 5050
Ex. 3: 1+2+3+...+1000
· Step 1: 1000/2=500
· Step 2: Write 500 twice → 500500
· Answer: 500500
Ex. 4. 1+2+3+...+99
- 99*100/2 = 9900/2 = 4950
Why Does It Work?
This trick is a shortcut for the standard formula: S = n(n+1)/2
For example:
Ex. 1. 1+2+3+...+10
Ans: 10(11) / 2 = 55
Ex. 2. 1+2+3+...+100
Ans: 100(101) / 2 = 5050
Ex. 3. 1+2+3+...+1000
Ans : 1000(1001) / 2 = 500500
Ex. 4. 1+2+3+...+99
Ans: 99(100) / 2 = 4950
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āϏāĻžāϧāĻžā§°āĻŖ āϏā§āϤā§ā§°
S=n(n+1)2S = \frac{n(n+1)}{2}
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Superfast āϏāĻšāĻ āĻĒāĻĻā§āϧāϤāĻŋ
āύāĻŋā§āĻŽ
- āĻļā§āώ āϏāĻāĻā§āϝāĻžāĻā§ (n) 2 āĻ āĻāĻžāĻ āĻā§°āĻ
- āĻĒā§ā§ąāĻž āĻĢāϞāĻā§ āĻĻā§āĻŦāĻžā§° āϞāĻŋāĻāĻ
āĻāĻĻāĻžāĻšā§°āĻŖ 1: 1 + 2 + 3 + … + 10
- āϧāĻžāĻĒ 1: 10÷2=510 ÷ 2 = 5
- āϧāĻžāĻĒ 2: 5 āĻĻā§āĻŦāĻžā§° āϞāĻŋāĻāĻž → 55
āĻāϤā§āϤ⧰: 55
āĻāĻĻāĻžāĻšā§°āĻŖ 2: 1 + 2 + 3 + … + 100
- āϧāĻžāĻĒ 1: 100÷2=50100 ÷ 2 = 50
- āϧāĻžāĻĒ 2: 50 āĻĻā§āĻŦāĻžā§° āϞāĻŋāĻāĻž → 5050
- āĻāϤā§āϤ⧰: 5050
āĻāĻĻāĻžāĻšā§°āĻŖ 3: 1 + 2 + 3 + … + 1000
- āϧāĻžāĻĒ 1: 1000÷2=5001000 ÷ 2 = 500
- āϧāĻžāĻĒ 2: 500 āĻĻā§āĻŦāĻžā§° āϞāĻŋāĻāĻž → 500500
- āĻāϤā§āϤ⧰: 500500
āĻāĻĻāĻžāĻšā§°āĻŖ 4: 1 + 2 + 3 + … + 99
99 × 100 ÷ 2 = 9900 ÷ 2 = 4950
āĻāĻ Trick āĻāĻŋā§ āĻāĻžāĻŽ āĻā§°ā§ ?
āĻāĻ āĻĒāĻĻā§āϧāϤāĻŋāĻā§ āĻāĻ āϏā§āϤā§ā§°ā§° āĻāĻĒā§°āϤ āĻāϧāĻžā§°āĻŋāϤāĻ
S = n (n+1) / 2S
āϏā§āϤā§ā§° āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻŋ:
- 1 + 2 + … + 10 → 55
- 1 + 2 + … + 100 → 5050
- 1 + 2 + … + 1000 → 500500
- 1 + 2 + … + 99 → 4950
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