HCF of 222, 642, 1062, Option : a. 6, b. 8, c. 4, d. 2

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Q. HCF of 222, 642, 1062, Option : a. 6, b. 8, c. 4, d. 2

Soln,

222, 642, 1062 → all divisible by 2
→ 111, 321, 531

111, 321, 531→ all divisible by 3
→ 37, 107, 177

No more common.

So, HCF = 2 × 3 = 6