HCF of 12, 18, 42, Option : A. 123 B. 60 C. 12 D. 6
Q. Find the HCF of 12, 18, and 42
Explanation: First write the prime factors of each number : 12 = 2² × 3, 18 = 2 × 3², and 42 = 2 × 3 × 7.
Now find the common prime factors present in all the numbers.The common factors are 2 and 3.
Multiply the common factors: 2 × 3 = 6
Therefore, the HCF of 12, 18, and 42 is 6.
Ans: D. 6
Ass : āĻĒā§ā§°āĻĨāĻŽā§ āĻĒā§ā§°āϤāĻŋāĻā§ āϏāĻāĻā§āϝāĻžā§° āĻŽā§āϞāĻŋāĻ āĻā§āĻŖāύā§āϝāĻŧāĻ āϞāĻŋāĻāĻž āĻšāϝāĻŧ: 12 = 2² × 3, 18 = 2 × 3², āĻā§°ā§ 42 = 2 × 3 × 7
āĻāϤāĻŋāϝāĻŧāĻž āϏāĻāϞ⧠āϏāĻāĻā§āϝāĻžāϤ āĻĨāĻāĻž āϏāĻžāϧāĻžā§°āĻŖ āĻŽā§āϞāĻŋāĻ āĻā§āĻŖāύā§āϝāĻŧāĻ āĻŦāĻŋāĻāĻžā§°āĻž āĻšāϝāĻŧāĨ¤ āϏāĻžāϧāĻžā§°āĻŖ āĻā§āĻŖāύā§āϝāĻŧāĻ āĻšā§āĻā§ 2 āĻā§°ā§ 3āĨ¤
āϏāĻžāϧāĻžā§°āĻŖ āĻā§āĻŖāύā§āϝāĻŧāĻāĻŦā§ā§° āĻā§āĻŖ āĻā§°āĻŋāϞā§: 2×3 = 6 āϏā§āϝāĻŧā§, 12, 18 āĻā§°ā§ 42 ā§° HCF āĻšā§āĻā§ 6āĨ¤
āĻāϤā§āϤ⧰: D. 6
12=22×3,18=2×32,42=2×3×7 HCF = 2 × 3 = 6
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Q. Find the LCM of 15, 24, 35, and 5
Explanation: First write each number in its prime factor form : 15 = 3 × 5, 24 = 2³ × 3, 35 = 5 × 7, and 54 = 2 × 3³.
Now take the highest powers of all the prime factors present in the numbers.
The highest power of 2 is 2³, the highest power of 3 is 3³, and the prime factors 5 and 7 are also included.
Multiply these highest powers together: LCM = 23×33×5×7 = 8 × 27 × 5 × 7 =
Therefore, the LCM of 15, 24, 35, and 54 is 7560.
LCM = 23×33×5×7=7560
Ass: āĻĒā§ā§°āĻĨāĻŽā§ āĻĒā§ā§°āϤāĻŋāĻā§ āϏāĻāĻā§āϝāĻžā§° āĻŽā§āϞāĻŋāĻ āĻā§āĻŖāύā§āϝāĻŧāĻ ā§°ā§āĻĒ āϞāĻŋāĻāĻž āĻšāϝāĻŧāĨ¤
15 = 3 × 5, 24 = 2³ × 3, 35 = 5 × 7, āĻā§°ā§ 54 = 2 × 3³āĨ¤
āĻāϤāĻŋāϝāĻŧāĻž āϏāĻāϞ⧠āϏāĻāĻā§āϝāĻžāϤ āĻĨāĻāĻž āĻŽā§āϞāĻŋāĻ āĻā§āĻŖāύā§āϝāĻŧāĻā§° āϏ⧰ā§āĻŦā§āĻā§āĻ āĻāĻžāϤ āϞā§ā§ąāĻž āĻšāϝāĻŧāĨ¤
2 ā§° āϏ⧰ā§āĻŦā§āĻā§āĻ āĻāĻžāϤ āĻšā§āĻā§ 2³, 3 ā§° āϏ⧰ā§āĻŦā§āĻā§āĻ āĻāĻžāϤ āĻšā§āĻā§ 3³, āĻā§°ā§ 5 āĻā§°ā§ 7 āĻ āĻ
āύā§āϤ⧰ā§āĻā§āĻā§āϤ āĻā§°āĻž āĻšāϝāĻŧāĨ¤
āĻāϤāĻŋāϝāĻŧāĻž āĻāĻ āϏ⧰ā§āĻŦā§āĻā§āĻ āĻāĻžāϤāĻŦā§ā§° āĻā§āĻŖ āĻā§°āĻž āĻšāϝāĻŧ: LCM = 2³ × 3³ × 5 × 7
āϏā§āϝāĻŧā§, 15, 24, 35 āĻā§°ā§ 54 ā§° LCM āĻšā§āĻā§ 7560āĨ¤
LCM = 7560