The number 32043p88 is divisible by 4. What is the maximum value of p ?: Option: A.7 B.5 C.4 D.9



To determine divisibility by 4, we check the last two digits of the number. The last two digits of 32043p88 are 88.


A number is divisible by 4 if its last two digits are divisible by 4. Since 88 ÷ 4 = 22 and the remainder is 0, the number is divisible by 4 for any value of p. Therefore, p can be any digit from 0 to 9, and the maximum value of p is 9.


4 āĻĻā§āĻŦāĻžāϰāĻž āĻŦāĻŋāĻ­āĻžāĻœā§āϝāϤāĻž āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻŋāĻŦāϞ⧈ āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ā§° āĻļ⧇āώ⧰ āĻĻ⧁āϟāĻž āĻ…āĻ‚āĻ• āĻšā§‹ā§ąāĻž āĻšāϝāĻŧāĨ¤ 32043p88 āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ā§° āĻļ⧇āώ⧰ āĻĻ⧁āϟāĻž āĻ…āĻ‚āĻ• āĻšā§ˆāϛ⧇ 88āĨ¤


āϝāĻĻāĻŋ āĻļ⧇āώ⧰ āĻĻ⧁āϟāĻž āĻ…āĻ‚āĻ• 4 āĻĻā§āĻŦāĻžāϰāĻž āĻŦāĻŋāĻ­āĻžāĻœā§āϝ āĻšāϝāĻŧ, āϤ⧇āĻ¨ā§āϤ⧇ āϏāĻŽā§āĻĒā§‚ā§°ā§āĻŖ āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹āĻ“ 4 āĻĻā§āĻŦāĻžāϰāĻž āĻŦāĻŋāĻ­āĻžāĻœā§āϝ āĻšāϝāĻŧāĨ¤ āϝāĻŋāĻšā§‡āϤ⧁ 88 ÷ 4 = 22 āφ⧰⧁ āĻŦāĻžāϕ⧀ 0 āĻĨāĻžāϕ⧇, āϏ⧇āϝāĻŧ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ p-ā§° āϝāĻŋāϕ⧋āύ⧋ āĻŽāĻžāύ⧰ āĻŦāĻžāĻŦ⧇ 4 āĻĻā§āĻŦāĻžāϰāĻž āĻŦāĻŋāĻ­āĻžāĻœā§āϝāĨ¤ āĻ…āϤāĻāĻŦ, p-ā§° āĻŽāĻžāύ 0 ā§° āĻĒā§°āĻž 9 āϞ⧈ āϝāĻŋāϕ⧋āύ⧋ āϏāĻ‚āĻ–ā§āϝāĻž āĻš’āĻŦ āĻĒāĻžā§°ā§‡ āφ⧰⧁ āĻ¸ā§°ā§āĻŦāĻžāϧāĻŋāĻ• āĻŽāĻžāύ āĻšā§ˆāϛ⧇ 9āĨ¤


Ans / āωāĻ¤ā§āϤ⧰: (d) 9