Find Area // Total Surface Area of a Cube // Area of the Minor Segment of a Circle


Find the Total Surface Area of a Cube (āϘāύāϕ⧰ āĻŽā§āĻ  āĻĒ⧃āĻˇā§āĻ ā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻž)


Question / āĻĒā§ā§°āĻļā§āύ: Find the total surface area of a cube of side 8 cm. (āĻŦāĻžāĻšā§ā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ ā§Ž āϛ⧇āĻŽāĻŋ āĻšā§‹ā§ąāĻž āĻāϟāĻž āϘāύāϕ⧰ āĻŽā§āĻ  āĻĒ⧃āĻˇā§āĻ ā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻžāĨ¤)


Solution / āϏāĻŽāĻžāϧāĻžāύ:


Total Surface Area = 6 × (Side)² [āĻŽā§āĻ  āĻĒ⧃āĻˇā§āĻ ā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ = 6 × (āĻŦāĻžāĻšā§)²]


= 6 × 8²
= 6 × 64
= 384 cm²


Ans / āωāĻ¤ā§āϤ⧰: 384 cm² (ā§Šā§Žā§Ē āĻŦā§°ā§āĻ— āϛ⧇āĻŽāĻŋ)


Area of the Minor Segment of a Circle (āĻŦ⧃āĻ¤ā§āϤ⧰ āϏ⧰⧁ āĻ–āĻŖā§āĻĄā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ)


Question / āĻĒā§ā§°āĻļā§āύ: In the diagram, XY is a chord of a circle of radius 5 cm. The chord subtends an angle of 96° at the centre. Calculate, correct to three significant figures, the area of the minor segment cut off by XY. (āϚāĻŋāĻ¤ā§ā§°āϤ, XY āĻšā§ˆāϛ⧇ ā§Ģ āϛ⧇āĻŽāĻŋ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧāϝ⧁āĻ•ā§āϤ āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻœā§āϝāĻžāĨ¤ āĻœā§āϝāĻžāĻ–āύ⧇ āϕ⧇āĻ¨ā§āĻĻā§ā§°āϤ ⧝ā§Ŧ° āϕ⧋āĻŖ āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āϕ⧰āĻŋāϛ⧇āĨ¤ āϤāĻŋāύāĻŋāϟāĻž āϗ⧁⧰⧁āĻ¤ā§āĻŦāĻĒā§‚ā§°ā§āĻŖ āĻ…āĻ‚āĻ• (3 s.f.) āϞ⧈ XY-āĻ āϏ⧃āĻˇā§āϟāĻŋ āϕ⧰āĻž āϏ⧰⧁ āĻ–āĻŖā§āĻĄā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻžāĨ¤)



Solution / āϏāĻŽāĻžāϧāĻžāύ


Area of Minor Segment = Area of Sector − Area of Triangle


(āϏ⧰⧁ āĻ–āĻŖā§āĻĄā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ = āĻ–āĻŖā§āĻĄā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ − āĻ¤ā§ā§°āĻŋāϭ⧁āϜ⧰ āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ)


Area of Sector = 96 / 360 × 22/ 7 × 52 = 20.9524 cm2


Area of Triangle = 1 / 2 × 5 × 5 × sin ⁥96∘= 12.4313 cm2


Area of Minor Segment = 20.9524 − 12.4313  =8.5211 cm2


 Area of Minor Segment = 8.52 cm2


Ans / āωāĻ¤ā§āϤ⧰: 8.52 cm² / 8.52 āĻŦā§°ā§āĻ— āϛ⧇āĻŽāĻŋ


Calculate the Length of the Arc (āϚāĻžāĻĒā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻž)


Question / āĻĒā§ā§°āĻļā§āύ: Calculate the length of the arc PQ of a circle with radius = 3.5 cm and central angle = 60°. (āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ ā§Š.ā§Ģ āϛ⧇āĻŽāĻŋ āφ⧰⧁ āϕ⧇āĻ¨ā§āĻĻā§ā§°ā§€āϝāĻŧ āϕ⧋āĻŖ ā§Ŧā§Ļ° āĻĨāĻ•āĻž āĻŦ⧃āĻ¤ā§āϤ⧰ PQ āϚāĻžāĻĒā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻžāĨ¤)












Solution / āϏāĻŽāĻžāϧāĻžāύ

Length of Arc (āϚāĻžāĻĒā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ) = θ / 360∘ × 2πr

= 60 / 360 × 2 × 22/7 × 3.5 = 1 / 6 × 22 = = 3.67 cm (approx.)


Ans / āωāĻ¤ā§āϤ⧰: Length of Arc (āϚāĻžāĻĒā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ) = 3.67 cm (āϛ⧇āĻŽāĻŋ) (approx.)