Math Tricks : Find the value Using common factor / BODMAS Rule etc : Math Short Tricks – Practice Sheet


Q1. Find the value : āĻŽāĻžāύ āωāϞāĻŋāϝāĻŧāĻžāĻ“āĻ•


237 × 199 − 199 × 236


Trick : āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ (Common Factor / āϏāĻžāϧāĻžā§°āĻŖ āϗ⧁āĻŖāĻ•)


= 237×199 − 199×236
= 199(237 − 236)
= 199 × 1
= 199


=Ans / āωāĻ¤ā§āϤ⧰: 199


Q2. Find the value : āĻŽāĻžāύ āωāϞāĻŋāϝāĻŧāĻžāĻ“āĻ•


1999 × 64 + 36 × 1999


Trick : āĻ•ā§ŒāĻļāϞ (Common Factor)


1999(64 + 36)
= 1999 × 100
= 199900


Ans / āωāĻ¤ā§āϤ⧰: 199900


Q3. Evaluate : āĻŽāĻžāύ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•


× 40 − 50


Trick | BODMAS Rule : (Bracket → Of → Divide → Multiply → Add → Subtract)


(30 + 20) = 50
40 + 50 = 90
90 ÷ 45 = 2
2 × 40 = 80
80 − 50 = 30


Ans - āωāĻ¤ā§āϤ⧰: 30


Q4. Geometry - āĻœā§āϝāĻžāĻŽāĻŋāϤāĻŋ


One side of a rectangle = 12 cm, diagonal = 13 cm. Find the perimeter. āĻāĻ–āύ āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§ā§°ā§° āĻāϟāĻž āĻŦāĻžāĻšā§ 12 cm āφ⧰⧁ āĻ•ā§°ā§āĻŖ 13 cmāĨ¤ āĻĒā§°āĻŋāϏ⧀āĻŽāĻž āĻ•āĻŋāĻŽāĻžāύ ?


Trick : Pythagoras Theorem (āĻĒāĻžāχāĻĨāĻžāĻ—ā§‹ā§°āĻžāĻ› āωāĻĒāĻĒāĻžāĻĻā§āϝ)


Other side : āĻ…āĻ¨ā§āϝ āĻŦāĻžāĻšā§
= √(13² − 12²)
= √(169 − 144)
= √25 = 5 cm


Perimeter / āĻĒā§°āĻŋāϏ⧀āĻŽāĻž
= 2(l + b)
= 2(12 + 5)
= 34 cm


Ans / āωāĻ¤ā§āϤ⧰: 34 cm


Q5. Ratio & Rectangle : āĻ…āύ⧁āĻĒāĻžāϤ āφ⧰⧁ āφāϝāĻŧāϤāĻ•ā§āώ⧇āĻ¤ā§ā§°


Length : Breadth = 9 : 5, Breadth is 10 m less than length. Find the perimeter.
āĻĻā§ˆā§°ā§āĻ˜ā§āϝ : āĻĒā§ā§°āĻ¸ā§āĻĨ = 9 : 5, āĻĒā§ā§°āĻ¸ā§āĻĨ āĻĻā§ˆā§°ā§āĻ˜ā§āϝāϤāĻ•ā§ˆ 10 m āĻ•āĻŽāĨ¤ āĻĒā§°āĻŋāϏ⧀āĻŽāĻž āĻ•āĻŋāĻŽāĻžāύ ?


Trick | Ratio Method (k-method / k āĻĒāĻĻā§āϧāϤāĻŋ)


Let : āϧ⧰⧋āρ
Length = 9k, Breadth = 5k


Given : āĻĻāĻŋāϝāĻŧāĻž āφāϛ⧇
9k − 5k = 10
4k = 10 ⇒ k = 2.5


Length : āĻĻā§ˆā§°ā§āĻ˜ā§āϝ = 9 × 2.5 = 22.5 m
Breadth : āĻĒā§ā§°āĻ¸ā§āĻĨ = 5 × 2.5 = 12.5 m


Perimeter / āĻĒā§°āĻŋāϏ⧀āĻŽāĻž
= 2(l + b)
= 2(22.5 + 12.5)
= 70 m


Ans / āωāĻ¤ā§āϤ⧰: 70 m


 Exam Smart Notes - āĻĒā§°ā§€āĻ•ā§āώāĻžā§° āϗ⧁⧰⧁āĻ¤ā§āĻŦāĻĒā§‚ā§°ā§āĻŖ āύ⧋āϟ



  • Common number āĻĻ⧇āĻ–āĻŋāϞ⧇ → common factor āϞāĻ“āĻ•

  • Bracket āĻĨāĻžāĻ•āĻŋāϞ⧇ → BODMAS āĻŽāĻžāύāĻ• āĻ…āύ⧁āϏ⧰āĻŖ āϕ⧰āĻ•

  • Rectangle + diagonal → Pythagoras āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻ•

  • Ratio question → k-method āφāϟāĻžāχāϤāĻ•ā§ˆ āϏāĻšāϜ


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1. Common Factor Method (Simplification)


Ex 1. Find the value of : āĻŽāĻžāύ āωāϞāĻŋāϝāĻŧāĻžāĻ“āĻ•
245 × 99 − 99 × 244


Trick: Take 99 common
= 99(245 − 244)
= 99 × 1
= 99


Ex 2. Find the value of : āĻŽāĻžāύ āωāϞāĻŋāϝāĻŧāĻžāĻ“āĻ• : 1500 × 32 + 68 × 1500


Trick: Take 1500 common
= 1500(32 + 68)
= 1500 × 100
= 150000


2. BODMAS Rule


Ex 1. Evaluate : āĻŽāĻžāύ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ• : {50 + (30 − 10)} ÷ 10 × 4 − 6


Soln:


(30 − 10) = 20
50 + 20 = 70
70 ÷ 10 = 7
7 × 4 = 28
28 − 6 = 22


Ex 2. Evaluate : āĻŽāĻžāύ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ• : {80 − (40 ÷ 5)} × 2 + 4


Soln:
40 ÷ 5 = 8
80 − 8 = 72
72 × 2 = 144
144 + 4 = 148


3. Algebra (Combine Like Terms)


Ex 1.  Add : āϝ⧋āĻ— āϕ⧰āĻ•
(5xy − 3yz + 4x)
(−2xy + 7yz − x)


Trick:
(5xy − 2xy) + (−3yz + 7yz) + (4x − x)
= 3xy + 4yz + 3x


Ex 2. Simplify 8a + 5b − 3a + 2b


Soln:
(8a − 3a) + (5b + 2b)
= 5a + 7b


4. Geometry (Rectangle + Diagonal)


Ex 1. One side = 9 cm, diagonal = 15 cm. Find perimeter. Q. āĻāϟāĻž āĻŦāĻžāĻšā§ 9 cm, āĻ•ā§°ā§āĻŖ 15 cmāĨ¤ āĻĒā§°āĻŋāϏ⧀āĻŽāĻž āĻ•āĻŋāĻŽāĻžāύ ?


Trick (Pythagoras):
Other side = √(15² − 9²) = √(225 − 81) = √144 = 12 cm
Perimeter = 2(9 + 12) = 42 cm


Ex 2. One side = 6 cm, diagonal = 10 cm. Find perimeter.  Q. āĻāϟāĻž āĻŦāĻžāĻšā§ 6 cm, āĻ•ā§°ā§āĻŖ 10 cmāĨ¤ āĻĒā§°āĻŋāϏ⧀āĻŽāĻž āĻ•āĻŋāĻŽāĻžāύ?


Soln:
Other side = √(100 − 36) = √64 = 8 cm
Perimeter = 2(6 + 8) = 28 cm


5. Ratio Method (k-method)


Ex 1. Length : Breadth = 5 : 3, difference = 8 m. Find perimeter. Q. āĻĻā§ˆā§°ā§āĻ˜ā§āϝ : āĻĒā§ā§°āĻ¸ā§āĻĨ = 5 : 3, āĻĒāĻžā§°ā§āĻĨāĻ•ā§āϝ 8 māĨ¤ āĻĒā§°āĻŋāϏ⧀āĻŽāĻž āĻ•āĻŋāĻŽāĻžāύ ?


Trick:
5k − 3k = 8 ⇒ 2k = 8 ⇒ k = 4
Length = 20 m, Breadth = 12 m
Perimeter = 2(20 + 12) = 64 m


Ex 2. Ratio = 4 : 1, difference = 6 m. Find perimeter. Q. āĻ…āύ⧁āĻĒāĻžāϤ = 4 : 1, āĻĒāĻžā§°ā§āĻĨāĻ•ā§āϝ 6 māĨ¤ āĻĒā§°āĻŋāϏ⧀āĻŽāĻž āĻ•āĻŋāĻŽāĻžāύ?


Soln:
4k − k = 6 ⇒ 3k = 6 ⇒ k = 2
Length = 8 m, Breadth = 2 m
Perimeter = 2(8 + 2) = 20 m


Exam Tip - āĻĒā§°ā§€āĻ•ā§āώāĻžā§° āϟāĻŋāĻĒ



  • Common number → factor out

  • Bracket → BODMAS

  • Same variables → like terms

  • Diagonal → Pythagoras

  • Ratio → k-method