Math Tricks : Find the value Using common factor / BODMAS Rule etc : Math Short Tricks â Practice Sheet
Q1. Find the value : āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻ
237 × 199 − 199 × 236
Trick : āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ (Common Factor / āϏāĻžāϧāĻžā§°āĻŖ āĻā§āĻŖāĻ)
= 237×199 − 199×236
= 199(237 − 236)
= 199 × 1
= 199
=Ans / āĻāϤā§āϤ⧰: 199
Q2. Find the value : āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻ
1999 × 64 + 36 × 1999
Trick : āĻā§āĻļāϞ (Common Factor)
1999(64 + 36)
= 1999 × 100
= 199900
Ans / āĻāϤā§āϤ⧰: 199900
Q3. Evaluate : āĻŽāĻžāύ āύāĻŋā§°ā§āĻŖāϝāĻŧ āĻā§°āĻ
× 40 − 50
Trick | BODMAS Rule : (Bracket → Of → Divide → Multiply → Add → Subtract)
(30 + 20) = 50
40 + 50 = 90
90 ÷ 45 = 2
2 × 40 = 80
80 − 50 = 30
Ans - āĻāϤā§āϤ⧰: 30
Q4. Geometry - āĻā§āϝāĻžāĻŽāĻŋāϤāĻŋ
One side of a rectangle = 12 cm, diagonal = 13 cm. Find the perimeter. āĻāĻāύ āĻāϝāĻŧāϤāĻā§āώā§āϤā§ā§°ā§° āĻāĻāĻž āĻŦāĻžāĻšā§ 12 cm āĻā§°ā§ āĻā§°ā§āĻŖ 13 cmāĨ¤ āĻĒā§°āĻŋāϏā§āĻŽāĻž āĻāĻŋāĻŽāĻžāύ ?
Trick : Pythagoras Theorem (āĻĒāĻžāĻāĻĨāĻžāĻā§ā§°āĻžāĻ āĻāĻĒāĻĒāĻžāĻĻā§āϝ)
Other side : āĻ
āύā§āϝ āĻŦāĻžāĻšā§
= √(13² − 12²)
= √(169 − 144)
= √25 = 5 cm
Perimeter / āĻĒā§°āĻŋāϏā§āĻŽāĻž
= 2(l + b)
= 2(12 + 5)
= 34 cm
Ans / āĻāϤā§āϤ⧰: 34 cm
Q5. Ratio & Rectangle : āĻ āύā§āĻĒāĻžāϤ āĻā§°ā§ āĻāϝāĻŧāϤāĻā§āώā§āϤā§ā§°
Length : Breadth = 9 : 5, Breadth is 10 m less than length. Find the perimeter.
āĻĻā§ā§°ā§āĻā§āϝ : āĻĒā§ā§°āϏā§āĻĨ = 9 : 5, āĻĒā§ā§°āϏā§āĻĨ āĻĻā§ā§°ā§āĻā§āϝāϤāĻā§ 10 m āĻāĻŽāĨ¤ āĻĒā§°āĻŋāϏā§āĻŽāĻž āĻāĻŋāĻŽāĻžāύ ?
Trick | Ratio Method (k-method / k āĻĒāĻĻā§āϧāϤāĻŋ)
Let : āϧ⧰ā§āĻ
Length = 9k, Breadth = 5k
Given : āĻĻāĻŋāϝāĻŧāĻž āĻāĻā§
9k − 5k = 10
4k = 10 ⇒ k = 2.5
Length : āĻĻā§ā§°ā§āĻā§āϝ = 9 × 2.5 = 22.5 m
Breadth : āĻĒā§ā§°āϏā§āĻĨ = 5 × 2.5 = 12.5 m
Perimeter / āĻĒā§°āĻŋāϏā§āĻŽāĻž
= 2(l + b)
= 2(22.5 + 12.5)
= 70 m
Ans / āĻāϤā§āϤ⧰: 70 m
Exam Smart Notes - āĻĒā§°ā§āĻā§āώāĻžā§° āĻā§ā§°ā§āϤā§āĻŦāĻĒā§ā§°ā§āĻŖ āύā§āĻ
- Common number āĻĻā§āĻāĻŋāϞ⧠→ common factor āϞāĻāĻ
- Bracket āĻĨāĻžāĻāĻŋāϞ⧠→ BODMAS āĻŽāĻžāύāĻ āĻ āύā§āϏ⧰āĻŖ āĻā§°āĻ
- Rectangle + diagonal → Pythagoras āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻ
- Ratio question → k-method āĻāĻāĻžāĻāϤāĻā§ āϏāĻšāĻ
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1. Common Factor Method (Simplification)
Ex 1. Find the value of : āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻ
245 × 99 − 99 × 244
Trick: Take 99 common
= 99(245 − 244)
= 99 × 1
= 99
Ex 2. Find the value of : āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻ : 1500 × 32 + 68 × 1500
Trick: Take 1500 common
= 1500(32 + 68)
= 1500 × 100
= 150000
2. BODMAS Rule
Ex 1. Evaluate : āĻŽāĻžāύ āύāĻŋā§°ā§āĻŖāϝāĻŧ āĻā§°āĻ : {50 + (30 − 10)} ÷ 10 × 4 − 6
Soln:
(30 − 10) = 20
50 + 20 = 70
70 ÷ 10 = 7
7 × 4 = 28
28 − 6 = 22
Ex 2. Evaluate : āĻŽāĻžāύ āύāĻŋā§°ā§āĻŖāϝāĻŧ āĻā§°āĻ : {80 − (40 ÷ 5)} × 2 + 4
Soln:
40 ÷ 5 = 8
80 − 8 = 72
72 × 2 = 144
144 + 4 = 148
3. Algebra (Combine Like Terms)
Ex 1. Add : āϝā§āĻ āĻā§°āĻ
(5xy − 3yz + 4x)
(−2xy + 7yz − x)
Trick:
(5xy − 2xy) + (−3yz + 7yz) + (4x − x)
= 3xy + 4yz + 3x
Ex 2. Simplify 8a + 5b − 3a + 2b
Soln:
(8a − 3a) + (5b + 2b)
= 5a + 7b
4. Geometry (Rectangle + Diagonal)
Ex 1. One side = 9 cm, diagonal = 15 cm. Find perimeter. Q. āĻāĻāĻž āĻŦāĻžāĻšā§ 9 cm, āĻā§°ā§āĻŖ 15 cmāĨ¤ āĻĒā§°āĻŋāϏā§āĻŽāĻž āĻāĻŋāĻŽāĻžāύ ?
Trick (Pythagoras):
Other side = √(15² − 9²) = √(225 − 81) = √144 = 12 cm
Perimeter = 2(9 + 12) = 42 cm
Ex 2. One side = 6 cm, diagonal = 10 cm. Find perimeter. Q. āĻāĻāĻž āĻŦāĻžāĻšā§ 6 cm, āĻā§°ā§āĻŖ 10 cmāĨ¤ āĻĒā§°āĻŋāϏā§āĻŽāĻž āĻāĻŋāĻŽāĻžāύ?
Soln:
Other side = √(100 − 36) = √64 = 8 cm
Perimeter = 2(6 + 8) = 28 cm
5. Ratio Method (k-method)
Ex 1. Length : Breadth = 5 : 3, difference = 8 m. Find perimeter. Q. āĻĻā§ā§°ā§āĻā§āϝ : āĻĒā§ā§°āϏā§āĻĨ = 5 : 3, āĻĒāĻžā§°ā§āĻĨāĻā§āϝ 8 māĨ¤ āĻĒā§°āĻŋāϏā§āĻŽāĻž āĻāĻŋāĻŽāĻžāύ ?
Trick:
5k − 3k = 8 ⇒ 2k = 8 ⇒ k = 4
Length = 20 m, Breadth = 12 m
Perimeter = 2(20 + 12) = 64 m
Ex 2. Ratio = 4 : 1, difference = 6 m. Find perimeter. Q. āĻ āύā§āĻĒāĻžāϤ = 4 : 1, āĻĒāĻžā§°ā§āĻĨāĻā§āϝ 6 māĨ¤ āĻĒā§°āĻŋāϏā§āĻŽāĻž āĻāĻŋāĻŽāĻžāύ?
Soln:
4k − k = 6 ⇒ 3k = 6 ⇒ k = 2
Length = 8 m, Breadth = 2 m
Perimeter = 2(8 + 2) = 20 m
Exam Tip - āĻĒā§°ā§āĻā§āώāĻžā§° āĻāĻŋāĻĒ
- Common number → factor out
- Bracket → BODMAS
- Same variables → like terms
- Diagonal → Pythagoras
- Ratio → k-method