The sum of the squares of three consecutive natural numbers is 194. What is the sum of the numbers ? : āĻāϕ⧇⧰āĻžāĻšā§‡ āĻĨāĻ•āĻž āϤāĻŋāύāĻŋāϟāĻž āĻ¸ā§āĻŦāĻžāĻ­āĻžā§ąāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻžā§° āĻŦā§°ā§āĻ—ā§° āϝ⧋āĻ—āĻĢāϞ 194āĨ¤ āϏ⧇āχ āϤāĻŋāύāĻŋāϟāĻž āϏāĻ‚āĻ–ā§āϝāĻžā§° āϝ⧋āĻ—āĻĢāϞ āĻ•āĻŋāĻŽāĻžāύ ??


Q. The sum of the squares of three consecutive natural numbers is 194. What is the sum of the numbers ? (āĻāϕ⧇⧰āĻžāĻšā§‡ āĻĨāĻ•āĻž āϤāĻŋāύāĻŋāϟāĻž āĻ¸ā§āĻŦāĻžāĻ­āĻžā§ąāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻžā§° āĻŦā§°ā§āĻ—ā§° āϝ⧋āĻ—āĻĢāϞ 194āĨ¤ āϏ⧇āχ āϤāĻŋāύāĻŋāϟāĻž āϏāĻ‚āĻ–ā§āϝāĻžā§° āϝ⧋āĻ—āĻĢāϞ āĻ•āĻŋāĻŽāĻžāύ?)


Options:
(a) 24 (b) 27 (c) 21 (d) 30


Solution:


Let the three consecutive natural numbers be (āϧ⧰āĻž āĻšāĻ“āĻ•, āĻāϕ⧇⧰āĻžāĻšā§‡ āĻĨāĻ•āĻž āϤāĻŋāύāĻŋāϟāĻž āĻ¸ā§āĻŦāĻžāĻ­āĻžā§ąāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž āĻšā§ˆāϛ⧇): x, (x+1), (x+2)


According to the question : āĻĒā§ā§°āĻļā§āύ āĻ…āύ⧁āϏ⧰āĻŋ:


x2 + (x+1)2 + (x+2)2 = 194


⇒ x2 + x2 + 2x + 1 + x2 + 4x + 4 = 194   
⇒ 3x2 + 6x + 5 = 194
⇒ 3x2+6x = 189
⇒ x2+2x−63 = 0


⇒ (x+9)(x−7) = 0
⇒ x = 7


Numbers = 7, 8, 9
Sum = 7 + 8 + 9 = 24


Ans: 24

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