Trial Test 2 : Work : Speed : Distance : Time
Work : Speed : Distance : Time
Main Formulas
- Speed = Distance ÷ Time (v = d/t)
- Distance = Speed × Time ( d = v × t)
- Time = Distance ÷ Speed ( t = d/v)
- Time & Work Formula = M × D × H ∝ Work
Where:
- M = Men
- D = Days
- H = Hours
- Work = Total work done / Output
Main Rule
If the work is constant → M × D × H = Constant
i. Men & Days Relation
If hours/day are the same: M1⋅D1=M2⋅D2
- More men → work finishes faster
- Fewer men → work takes longer
ii. Men & Hours Relation
If the number of days is the same: M1⋅H1=M2⋅H2
iii. Days & Hours Relation
If the number of men is the same: D1⋅H1=D2⋅H2
1. A, B, and C can complete a work in 10, 12, and 15 days respectively. If all three work together, in how many days will the work be completed ?
Soln:
Work rates per day:
- A = 1/10 per day
- B = 1/12 per day
- C = 1/15 per day
Combined work per day:
= 1/10+1/12+1/15
= (6+5+4)/60
= 15/60
=1/4
Time taken together: Time = 1 divide ¼ = 4 days
Ans: 4 days
2. A can complete a work in 20 days and B can complete the same work in 30 days. How many days will they take if they work together?
Soln
Work rates per day:
- A = 1/20 per day
- B = 1/30 per day
Combined work per day:
1/20+1/30 = (3+2)/60 = 5/60 =1/12
Time taken together: Time =1 divided 1/12 = 12 days
Ans: 12 days
3: Ram can complete a work in 10 days and Shyam can complete the same work in 15 days. How many days will they take if they work together?
Soln.
Work rates per day:
- Ram = 1/10 per day
- Shyam = 1/15 per day
Combined work per day: 1/10 + 1/15 = (3 + 2)/30 = 5/30 = 1/6
Time taken together: Time = 1 divide 1/6 = 6 days
Ans: 6 days
4: A car runs at a speed of 16 km/h. How much time will it take to cover a distance of 96 km ?
Solution:
Time = Distance / Speed = 96/16 = 6 hours
Ans: 6 hours
5. A boat travels 12 km upstream (against the current) in 48 minutes. If the speed of the current is 2 km/h, what is the boat’s speed in still water ?
Solution :
- Convert time to hours: 48 minutes = 48/60 = 0.8 hours.
- Upstream speed = distance/time = 12/0.8 km/h.
→ Calculate: 12÷0.8 =12×10/8 = 12×1.25 = 15 km/h
- Let v = boat speed in still water. Upstream speed = v − current = v-2.
→ So, v−2 =15.
- Solve: v=15+2=17 km/h.
Ans: 17 km/h (boat’s speed in still water)
6. Ram, Shyam, and Mohan together can complete a work in 12 days. Ram and Mohan together can complete it in 60 days. How many days will Shyam alone take to complete the work ?
Soln
Work rates per day:
- Ram + Shyam + Mohan = 1/12 per day
- Ram + Mohan = 1/60 per day
Shyam’s 1-day work:
= (Ram + Shyam + Mohan) − (Ram + Mohan)
= 1/12-1/60 = 5-1/60 = 4/60 = 1/15
Time taken by Shyam alone:
Time = 1divide 1/15 = 15 days
Ans: 15 days
7. If a car travels 40 km in 2 hours and 60 km in the next 2 hours, Average Speed = ?
Then,
Total Distance = 40 + 60 = 100 km
Total Time = 2 + 2 = 4 hours
Average Speed = Total Distance / Total Time = 100/4 = 25 km/h
Average Speed = 25 km/h
Important Points :
- The average is always a middle value.
- A very large or very small number can change the average up or down.
- Think of average as equal sharing — dividing everything equally among all parts.
8. A man covers 80% of the distance between Delhi and Agra in 4 hours at a speed of 45 km/h. Find the total distance between Delhi and Agra.
Options: A) 210 km B) 180 km C) 240 km D) 225 km
Given:
- Speed = 45 km/h
- Time = 4 hours
Distance covered = 45 × 4 = 180 km
This 180 km is 80% of the total distance.
So, Total distance=180×100 / 80 = 225 km
Ans: D) 225 km
9: If 5 cats catch 5 mice in 5 days, then 100 cats will catch 100 mice in how many days ?
Options:
(a) 1 day (b) 5 days (c) 20 days (d) 100 days
Explanation:
5 cats → 5 mice in 5 days
So, 1 cat → 1 mouse in 5 days
Therefore, 100 cats → 100 mice in 5 days (since all work at the same rate).
Ans: (b) 5 days
10. Train A crosses a stationary train B in 50 seconds and a pole in 20 seconds, both at the same speed. If the length of train A is 240 meters, find the length of stationary train B.
Options: A. 260 meters B. 300 meters C. 360 meters D. Insufficient data
Given:
- Train A crosses a stationary train B in 50 seconds.
- Train A crosses a pole in 20 seconds.
- Length of Train A = 240 meters.
We have to find the length of Train B.
Find the speed of Train A
When Train A crosses a pole, only its own length is covered.
Speed of A = Distance / Time = 240/20 = 12 m/s
When Train A crosses Train B
Total distance covered = Length of A + Length of B
Time = 50 seconds
Distance = Speed × Time
240 + Length of B = 12 × 50
240 + Length of B = 600
Length of Train B
Length of B = 600 − 240 = 360 meters
Ans: C. 360 meters