Ratio & Proportion


Q. Find First , Mean , Third , Fourth Proportional.


1. First Proportional


Q. What is the first proportional of 12 and 8 ?


Formula: a2/b


Trick : : Square the 1st number and divide by 2nd


Soln


C = 122/8 = 144/8 = 18


Ans: 18


2. Mean Proportional


Q.What is the mean proportional of 18 and 50 ?


Formula: Mean = sqrt a×b


Trick : Multiply the numbers then take square root


Soln


sqrt 18×50 = 900 = 30


Ans: 30


3. Third Proportional


Q. What is the third proportional of 8 and 20 ?


Formula : If a : b = b : c


                                   c = b2/a


Trick: Square the 2nd number, divide by 1st


Soln


C = 202/8 = 400/8 = 50


Ans: 50


 4. Fourth Proportional


Q. What is the fourth proportional of 6, 16 and 9 ?


Formula: If a : b = c : d


                             D = b×c/a


Trick: Multiply 2nd × 3rd, divide by 1st


Soln


d = 16×9/6 = 144/6 = 24


Ans: 24


Q.The ratio of two quantities is 8 : 15. If the first quantity is 40, what is the second quantity ?


Options: (a) 120 (b) 75 (c) 45 (d) 15


Soln


Given ratio: First quantity : Second quantity = 8 : 15
Given: First quantity = 40


Write the ratio as: 40 : Second quantity = 8 : 15


This means: Second quantity = 40×15/8


Calculate: Second quantity = 600/8=75


Ans: (b) 75


Explanation: When the first quantity (8 parts) becomes 40, each part becomes 40 ÷ 8 = 5
So the second quantity (15 parts) = 15×5=75.


Q. The ratio of salary of A and B is 5:3 the difference between them is 40 so what is the salary of A ?


Given:


Ratio of salaries (A : B) = 5 : 3
Difference = ₹40


Assume each ratio value = Y


5Y − 3Y = 40


2Y = 40


Y = 40 ÷ 2 = 20


Now calculate salaries:


Salary of A = 5Y = 5 × 20 = ₹100


Salary of B = 3Y = 3 × 20 = ₹60


Ans: A’s salary = ₹100B’s salary = ₹60 Difference = 100 − 60 = ₹40


Q. If a2 + b2 = c2 prove that a6 + b6 + 3a2b2c2 = c6


Soln


1st : Start with the left-hand side (LHS) = a6+b6+3a2b2c2


Write powers in cube form: = (a2)3 + (b2)3 + 3a2b2c2


2nd : Use the identity: x3 + y3 + 3xy(x+y) = (x+y)3


Here, x = a2, y = b2


So, (a2)3 + (b2)3 + 3(a2)(b2)(a2+b2) = (a2+b2)3


3rd : Substitute the given value


We know: a2 + b2 = c2


So, (a2+b2)3 = (c2)3 = c6


Ans : a6 + b6 + 3a2b2c2 = c6