Find the Divisibility no.


Divisibility Rules - Click Here


Q. If 2³¹ is divided by 5, what will be the remainder ?


A) 1 B) 2 C) 3 D) 4


Soln:


Remainder pattern of powers of 2 when divided by 5: 2¹ → 2 , 2² → 4 , 2³ → 3 , 2⁴ → 1


Pattern = 2, 4, 3, 1 (repeats every 4 terms)


Now find where 2³¹ falls in the cycle: 31 ÷ 4 → remainder = 3


So 2³¹ is the 3rd term of the cycle.


3rd term is: 2, 4, 3, 1 → 3


Ans: 3


Divisibility Rules - Click Here


Q. 7^12 - 4^12 is divisible by ?


A) 34  B) 33  C) 36  D) 35


Soln:


For even powers: a^n−b^n is divisible by (a−b)


Here: 7−4 = 3


So the whole number is divisible by 3.


Now check which option is a multiple of 3:



  • A) 34 , D) 35 - No

  • 33 - (multiple of 3)

  • 36 - (multiple of 3)


But among these, 33 is the correct divisor for this type of expression.


Ans: 33


Divisibility Rules - Click Here


Q. 2¹βΆ – 1 is divisible by which number ?


Options: A) 11  B) 13  C) 19  D) 17


Calculate the value: 2^16 = 65536


    2^16−1 = 65535


Check divisibility


Try dividing by 17: 65535÷17=3855(exactly divisible)


So 17 is a factor.


Check others divisible by: 11, 13, 19



  • Not divisible by 11

  • Not divisible by 13

  • Not divisible by 19


Ans: 17


Divisibility Rules - Click Here


Q. (2⁡¹ + 2⁡² + 2⁡³ + 2⁡⁴ + 2⁡⁡) is divisible by ?


A) 127  B) 124  C) 58  D) 23


Soln:


= 2^51(1+2+4+8+16)


= 1+2+4+8+16 = 31


So the number = 2^51×31


Now check options:



  • 124 = 4 × 31 → Yes (we have 31 and plenty of 2’s)

  • Others do NOT contain 31.


Ans: 124


Divisibility Rules - Click Here


Q: The number 5769116 is divisible by which of the following ?


A) 1  B) 5  C) 12  D) 8


Soln:



  • Every number is divisible by 1

  • Last digit is 6, so not divisible by 5.

  • Digit sum = 35, not divisible by 3 → cannot be 12.

  • Last three digits 116 not divisible by 8.


Ans: A) 1


Divisibility Rules - Click Here


Q. 2918245 is divisible by which number ?


Options: A) 11 B) 12 C) 9 D) 3


Soln:


Divisibility by 11



  • Rule: Difference of sums of odd and even position digits divisible by 11.

  • Odd positions: 2+1+2+5 = 10

  • Even positions: 9+8+4 = 21

  • Difference = 10 − 21 = −11 → divisible by 11

  • Not divisible by B)12 , C) 9 , D) 3 Check on  Divisibility Rules


Ans: A) 11


Divisibility Rules - Click Here


Q. (67⁢⁷ + 67) ÷ 68 → Remainder ?


A) 1   B) 63  C) 66  D) 67


Soln:


Short Trick:



  • 67 is 1 less than 68
    67 = -1 (mod 68)

  • So: 67⁢⁷ + 67 = (-1)⁢⁷ + (-1)
    Odd power → (–1)

  • So: (-1) + (-1) = -2


Convert remainder: 68 - 2 = 66


Ans = 66Divisibility Rules - Click Here


Q. 3^25+3^26+3^27+3^28 is divisible by which number ?


Options: A) 11  B) 16  C) 25  D) 30


(The expression is clearly a power series of 3.)


Soln:


= 3^25(1+3+9+27)


= 3^25 × 40


Check factors



  • 40 = 2 × 2 × 2 × 5

  • 3²β΅ = 3’s powers


So complete number contains: 2, 3 , 5


That means it is divisible by: 2×3×5=30


Ans: 30


Divisibility Rules - Click Here