Expressions & Identities (Squares & Powers). What is Integer ? : āĻŦā§āϝāĻā§āϤāĻŋ āĻā§°ā§ āϏāĻŽā§āĻā§°āĻŖ (āĻŦā§°ā§āĻ āĻā§°ā§ āĻāĻžāϤ)āĨ¤ āĻĒā§ā§°ā§āĻŖ āϏāĻāĻā§āϝāĻž āĻāĻžāĻ āĻāϝāĻŧ ?
Reciprocal Power Identities & Half-Power Shortcut : āĻĒā§ā§°āϤāĻŋāϞā§āĻŽ āĻāĻžāϤ⧰ āϏāĻŽā§āĻā§°āĻŖāϏāĻŽā§āĻš & āĻ ā§°ā§āϧ-āĻāĻžāϤ⧰ āϏāĻšāĻ/āĻĻā§ā§°ā§āϤ āĻāĻĒāĻžāϝāĻŧ
Base Formula – A
If, a + 1/a = x
Then,
Square: a² + 1/a² = x² − 2
Fourth Power: aâ´ + 1/aâ´ = (x² − 2)² − 2
āϝāĻĻāĻŋ, a + 1/a = x āĻšāϝāĻŧ āϤā§āύā§āϤā§, āĻŦā§°ā§āĻ: a² + 1/a² = x² − 2
āĻāϤā§ā§°ā§āĻĨ āĻāĻžāϤ: aâ´ + 1/aâ´ = (x² − 2)² − 2
Base Formula – B
If, aâŋ + 1/aâŋ = k
Then, aâŋá² − 1/aâŋá² = √(k − 2)
āϝāĻĻāĻŋ, aâŋ + 1/aâŋ = k āĻšāϝāĻŧ
āϤā§āύā§āϤā§, aâŋá² − 1/aâŋá² = √(k − 2)
Quick Rules
Case 1
Given “+” → Required “+” : āĻĻāĻŋāϝāĻŧāĻž āĻāĻŋāĻšā§āύ “+” → āĻĒā§ā§°āϝāĻŧā§āĻāύā§āϝāĻŧ āĻāĻŋāĻšā§āύ “+”
Formula: √(k + 2) : āϏā§āϤā§ā§°: √(k + 2)
Memory Trick: Plus → Add 2 : āĻŽā§āĻŽ’ā§°āĻŋ āĻā§ā§°āĻŋāĻ: Plus āĻŽāĻžāύ⧠2 āϝā§āĻ āĻā§°āĻ
Case 2
Given “+” → Required “−” : āĻĻāĻŋāϝāĻŧāĻž āĻāĻŋāĻšā§āύ “+” → āĻĒā§ā§°āϝāĻŧā§āĻāύā§āϝāĻŧ āĻāĻŋāĻšā§āύ “−”
Formula: √(k − 2) : āϏā§āϤā§ā§°: √(k − 2)
Memory Trick: Minus → Subtract 2 : āĻŽā§āĻŽ’ā§°āĻŋ āĻā§ā§°āĻŋāĻ: Minus āĻŽāĻžāύ⧠2 āĻŦāĻŋāϝāĻŧā§āĻ āĻā§°āĻ
Case 3
Given “−” → Required “+” : āĻĻāĻŋāϝāĻŧāĻž āĻāĻŋāĻšā§āύ “−” → āĻĒā§ā§°āϝāĻŧā§āĻāύā§āϝāĻŧ āĻāĻŋāĻšā§āύ “+”
Formula: √(k + 2) : āϏā§āϤā§ā§°: √(k + 2)
Case 4
Given “−” → Required “−” : āĻĻāĻŋāϝāĻŧāĻž āĻāĻŋāĻšā§āύ “−” → āĻĒā§ā§°āϝāĻŧā§āĻāύā§āϝāĻŧ āĻāĻŋāĻšā§āύ “−”
Formula: √(k − 2) : āϏā§āϤā§ā§°: √(k − 2)
Super Shortcut Memory
Half power = √(k ± 2) : āĻ ā§°ā§āϧ āĻāĻžāϤ = √(k ± 2)
Q1. If a + 1/a = 4, find aâ´ + 1/aâ´
Options: 204, 196, 198, 194
Soln
a + 1/a = 4
1st square: a² + 1/a² = 4² − 2 = 16 − 2 = 14
Again square: aâ´ + 1/aâ´ = 14² − 2 = 196 − 2 = 194
Ans: 194
Note: First square → minus 2, Again square → minus 2
Q2. If x²âĩ + 1/x²âĩ = 627, find x¹²⋅âĩ − 1/x¹²⋅âĩ
Options: (a) 24 (b) 25 (c) 125 (d) 26
Soln: x¹²⋅âĩ − 1/x¹²⋅âĩ = √(627 − 2) = √625 = 25
Ans: 25
Trick: Half power → √(k − 2) when required sign is minus (−)
Q3. If x¹â° + 1/x¹â° = 194, find xâĩ + 1/xâĩ
Options: (a) 12 (b) 13 (c) 14 (d) 16
Soln:
xâĩ + 1/xâĩ = √(194 + 2) = √196 = 14
Ans: 14
Q4. Solve: (1/7)âģâ´ + (1/9)âģâ´ + (1/5)âģâ´
Trick: (1/a)âģâŋ = aâŋ
= 7â´ + 9â´ + 5â´
= 2401 + 6561 + 625
= 15760
Ans: 15760
Q5. What is Integer ?
Definition: An integer is a whole number which can be positive, negative, or zero, without any fractional or decimal part.
āϏāĻāĻā§āĻāĻž: Integer āĻŦā§āϞāĻŋāϞ⧠āϏā§āĻ āĻĒā§ā§°ā§āĻŖāϏāĻāĻā§āϝāĻžāĻ āĻŦā§āĻāĻžāϝāĻŧ āϝāĻŋ āϧāύāĻžāϤā§āĻŽāĻ, āĻāĻŖāĻžāϤā§āĻŽāĻ āĻŦāĻž āĻļā§āύā§āϝ āĻš’āĻŦ āĻĒāĻžā§°ā§ āĻā§°ā§ āĻāϝāĻŧāĻžāϤ āĻā§āύ⧠āĻāĻā§āύāĻžāĻāĻļ āĻŦāĻž āĻĻāĻļāĻŽāĻŋāĻ āĻ āĻāĻļ āύāĻžāĻĨāĻžāĻā§āĨ¤
Examples / āĻāĻĻāĻžāĻšā§°āĻŖ: …, −3, −2, −1, 0, 1, 2, 3 …
Note:
- 0 is an integer
- Fractions & decimals are not integers
Q6. If a − 1/a = 7, find aâĩ − 1/aâĩ
Options: (a) 18557 (b) 17147 (c) 14557 (d) 21107
Trick: If a − 1/a = x (x is integer), then aâŋ − 1/aâŋ must be divisible by x.
āϝāĻĻāĻŋ a − 1/a = x āĻšāϝāĻŧ, āϤā§āύā§āϤ⧠aâŋ − 1/aâŋ x ā§°ā§ āĻŦāĻŋāĻāĻžāĻā§āϝ āĻš’āĻŦ āϞāĻžāĻāĻŋāĻŦāĨ¤
Check option (a):
18557 ÷ 7 = 2651 (Integer)
Ans: Option (a) 18557