Q. (sin31°/cos59°)^2 + (cos29°/sin61°)^2 – 1 = ?
Q. (sin31°/cos59°)2 + (cos29°/sin61°)2 – 1 = ?
Soln,
Use complementary angles : 31° + 59° = 90° → Sin 31° = Cos 59°
Sin31°/ Cos 59° = 1
So, (Sin31° / Cos 59°)2 = 1
29° + 61° = 90° → Cos 29° = Sin 61°
Cos29°/Sin 61° = 1
So, (Cos29°/Sin 61°)2=1
Substitute: 1+1−1=1
Ans:1
Note: α + β = 90° , sin α /cos β = 1, tan α /cot β = 1, sec α /cosec β = 1
Final Key Trick
If angles add to 90° and appear as:
- sin / cos
- tan / cot
- sec / cosec
then value = 1
α