Q. tan65°/cot25° = ?
Q. tan65°/cot25° = ?
Soln,
65β + 25β = 90β ⇒ complementary
So, cot25β = tan65β
Now just replace: tan65β/cot25β = tan65β/tan65β = 1
So: tan65β/β cot25β = tan65β/tan65β β=1
Ans:1β
Note: α + β = 90° , sin α /cos β = 1, tan α /cot β = 1, sec α /cosec β = 1
Final Key Trick
If angles add to 90° and appear as:
- sin / cos
- tan / cot
- sec / cosec
then value = 1