Physics 10th â āĻĒāĻĻāĻžā§°ā§āĻĨ āĻŦāĻŋāĻā§āĻāĻžāύ (āĻĻāĻļāĻŽ āĻļā§ā§°ā§āĻŖā§) â MCQ Set 3
Board Writing Tip:
- Definition → 2 clear lines
- Formula → Proper symbols
- Language → Simple & neat
Q1. What is Electric Current? Write its SI unit. āĻĒā§ā§°āĻļā§āύ: āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āϧāĻžā§°āĻž āĻāĻŋ? āĻāϝāĻŧāĻžā§° SI āĻāĻāĻ āϞāĻŋāĻāĻžāĨ¤
Answer : Electric current is the rate of flow of electric charge through a conductor.
SI unit: Ampere (A)
āĻāϤā§āϤ⧰ :
āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āϧāĻžā§°āĻž āĻŦā§āϞāĻŋāϞ⧠āĻāĻāĻ āϏāĻŽāϝāĻŧāϤ āĻĒā§°āĻŋāĻŦāĻžāĻšāĻā§° āĻŽāĻžāĻā§ā§°ā§ āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻšā§ā§ąāĻž āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āĻā§ąā§āĻļā§° āĻĒā§°āĻŋāĻŽāĻžāĻŖāĻ āĻŦā§āĻāĻžāϝāĻŧāĨ¤ SI āĻāĻāĻ: āĻāĻŽā§āĻĒāĻŋāϝāĻŧāĻžā§° (A)
Q2. State Ohm’s Law. āĻĒā§ā§°āĻļā§āύ: Ohm ā§° āύāĻŋāϝāĻŧāĻŽ āĻāϞā§āϞā§āĻ āĻā§°āĻžāĨ¤
Ans: Ohm’s Law states that at constant temperature, the current through a conductor is directly proportional to the potential difference across its ends.
āĻāϤā§āϤ⧰: Ohm ā§° āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŋ, āϤāĻžāĻĒāĻŽāĻžāϤā§āϰāĻž āϧā§ā§°ā§ā§ą āĻĨāĻžāĻāĻŋāϞā§, āĻĒā§°āĻŋāĻŦāĻžāĻšāĻā§° āĻŽāĻžāĻā§ā§°ā§ āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āϧāĻžā§°āĻž āϤāĻžā§° āĻĻā§āĻāĻž āĻĒā§ā§°āĻžāύā§āϤ⧰ āĻŽāĻžāĻā§° āĻŦāĻŋāĻā§ą āĻĒāĻžā§°ā§āĻĨāĻā§āϝ⧰ āϏā§āϤ⧠āϏāĻŽāĻžāύā§āĻĒāĻžāϤāĻŋāĻāĨ¤
Q3. Define Resistance. Write its SI unit. āĻĒā§ā§°āĻļā§āύ: āĻĒā§ā§°āϤāĻŋā§°ā§āϧ āĻāĻŋ? āĻāϝāĻŧāĻžā§° SI āĻāĻāĻ āϞāĻŋāĻāĻžāĨ¤
Answer : Resistance is the opposition offered by a conductor to the flow of electric current.
SI unit: Ohm (Ω). āĻāϤā§āϤ⧰ : āĻĒā§ā§°āϤāĻŋā§°ā§āϧ āĻŦā§āϞāĻŋāϞ⧠āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āϧāĻžā§°āĻžā§° āĻĒā§ā§°āĻŦāĻžāĻšāĻ āĻŦāĻžāϧāĻž āĻĻāĻŋāϝāĻŧāĻž āĻā§āĻŖāĻ āĻŦā§āĻāĻžāϝāĻŧāĨ¤
SI āĻāĻāĻ: āĻāĻšāĻŽ (Ω)
Q4. What is Joule’s Law of Heating ? āĻĒā§ā§°āĻļā§āύ: Joule ā§° āĻāώā§āĻŖāϤāĻžā§° āύāĻŋāϝāĻŧāĻŽ āĻāĻŋ ?
Answer: The heat produced in a conductor is directly proportional to the square of current, resistance, and time.
āĻāϤā§āϤ⧰: Joule ā§° āĻāώā§āĻŖāϤāĻžā§° āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŋ, āĻā§āĻĒāύā§āύ āϤāĻžāĻĒ āϧāĻžā§°āĻžā§° āĻŦā§°ā§āĻ, āĻĒā§ā§°āϤāĻŋā§°ā§āϧ āĻā§°ā§ āϏāĻŽāϝāĻŧā§° āϏā§āϤ⧠āϏāĻŽāĻžāύā§āĻĒāĻžāϤāĻŋāĻāĨ¤
H = I2Rt
Q5. What is a Fuse? Why is it used ? āĻĒā§ā§°āĻļā§āύ: Fuse āĻāĻŋ? āĻāϝāĻŧāĻžā§° āĻŦā§āĻ¯ā§ąāĻšāĻžā§°ā§° āĻāĻžā§°āĻŖ āĻāĻŋ ?
Ans: A fuse is a safety device that melts when excess current flows and protects electrical appliances.
āĻāϤā§āϤ⧰: Fuse āĻšā§āĻā§ āĻāĻāĻž āϏā§ā§°āĻā§āώāĻž āϝāύā§āϤā§ā§°āĨ¤ āĻ āϧāĻŋāĻ āϧāĻžā§°āĻž āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻš’āϞ⧠āĻ āĻāϞāĻŋ āĻĒā§°ā§ āĻā§°ā§ āĻŦāĻŋāĻĻā§āϝā§ā§ āϝāύā§āϤā§ā§°āϏāĻŽā§āĻšāĻ ā§°āĻā§āώāĻž āĻā§°ā§āĨ¤
Q6. What is a Magnetic Field ? āĻĒā§ā§°āĻļā§āύ: āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻā§āώā§āϤā§ā§° āĻāĻŋ ?
Ans: The region around a magnet where its magnetic force is experienced is called a magnetic field.
āĻāϤā§āϤ⧰: āĻā§āĻŽā§āĻŦāĻā§° āĻāĻžā§°āĻŋāĻāĻĢāĻžāϞ⧠āϝāĻŋ āĻ āĻā§āĻāϞāϤ āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻŦāϞ⧰ āĻĒā§ā§°āĻāĻžā§ą āĻ āύā§āĻā§ą āĻšāϝāĻŧ āϤāĻžāĻ āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻā§āώā§āϤā§ā§° āĻŦā§āϞā§āĨ¤
Q7. State Fleming’s Left-Hand Rule. āĻĒā§ā§°āĻļā§āύ: Fleming ā§° āĻŦāĻžāĻŽ-āĻšāĻžāϤ āύāĻŋāϝāĻŧāĻŽ āĻāϞā§āϞā§āĻ āĻā§°āĻžāĨ¤
Ans: If the thumb, forefinger and middle finger of the left hand are stretched mutually perpendicular, they represent motion, magnetic field and current respectively.
āĻāϤā§āϤ⧰: āĻŦāĻžāĻŽ āĻšāĻžāϤ⧰ āĻŦā§āĻĸāĻŧāĻž āĻāĻā§āϞāĻŋ, āϤ⧰ā§āĻāύ⧠āĻā§°ā§ āĻŽāϧā§āϝāĻŽāĻž āĻāĻā§āϞāĻŋāĻ āĻĒā§°āϏā§āĻĒā§°ā§ āϞāĻŽā§āĻŦ āĻā§°āĻŋ āϧ⧰āĻŋāϞ⧠āϏāĻŋāĻšāĻāϤ⧠āĻā§ā§°āĻŽā§ āĻāϤāĻŋ, āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻā§āώā§āϤā§ā§° āĻā§°ā§ āϧāĻžā§°āĻž āϏā§āĻāĻžāϝāĻŧāĨ¤
Q8. What is Refraction of Light ? āĻĒā§ā§°āĻļā§āύ: āĻĒā§āĻšā§°ā§° āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖ āĻāĻŋ ?
Ans: Refraction of light is the bending of light when it passes from one medium to another.
āĻāϤā§āϤ⧰: āĻāĻāĻž āĻŽāĻžāϧā§āϝāĻŽā§° āĻĒā§°āĻž āĻāύ āĻāĻāĻž āĻŽāĻžāϧā§āϝāĻŽāϞ⧠āĻĒā§āĻšā§° āϝāĻžāĻāĻāϤ⧠āĻĻāĻŋāĻļ āϏāϞāύāĻŋ āĻšā§ā§ąāĻžāĻā§ āĻĒā§āĻšā§°ā§° āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖ āĻŦā§āϞā§āĨ¤
Q9. Define the Power of a Lens. Write its unit. āĻĒā§ā§°āĻļā§āύ: āϞā§āύā§āϏ⧰ āĻā§āώāĻŽāϤāĻž āĻāĻŋ? āĻāϝāĻŧāĻžā§° āĻāĻāĻ āϞāĻŋāĻāĻžāĨ¤
Ans: Power of a lens is the ability of a lens to converge or diverge light. Unit: Dioptre (D)
āĻāϤā§āϤ⧰: āϞā§āύā§āϏ⧰ āĻā§āώāĻŽāϤāĻž āĻŦā§āϞāĻŋāϞ⧠āĻĒā§āĻšā§° āĻāĻāϤā§ā§° āĻŦāĻž āĻŦāĻŋāĻā§āĻāĻŋāύā§āύ āĻā§°āĻžā§° āĻā§āώāĻŽāϤāĻžāĻ āĻŦā§āĻāĻžāϝāĻŧāĨ¤
āĻāĻāĻ: āĻĄāĻžāĻāĻ
āĻĒā§āĻāĻžā§° (D)
Q10. Name one renewable source of energy from oceans. āĻĒā§ā§°āĻļā§āύ: āϏāĻžāĻā§°ā§° āĻĒā§°āĻž āĻĒā§ā§ąāĻž āĻāĻāĻž āύāĻŦā§āĻā§°āĻŖāϝā§āĻā§āϝ āĻļāĻā§āϤāĻŋā§° āĻā§āϏ⧰ āύāĻžāĻŽ āϞāĻŋāĻāĻžāĨ¤
Ans: Tidal Energy is a renewable source of energy from oceans.
āĻāϤā§āϤ⧰: āĻā§āϝāĻŧāĻžā§°-āĻāĻžāĻāĻž āĻļāĻā§āϤāĻŋ (Tidal Energy) āϏāĻžāĻā§°ā§° āĻĒā§°āĻž āĻĒā§ā§ąāĻž āĻāĻāĻž āύāĻŦā§āĻā§°āĻŖāϝā§āĻā§āϝ āĻļāĻā§āϤāĻŋā§° āĻā§āϏāĨ¤
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Q1. What is a Magnetic Field Line ? āĻĒā§ā§°āĻļā§āύ: āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻā§āώā§āϤā§ā§° ā§°ā§āĻāĻž āĻāĻŋ ?
Ans: A magnetic field line is an imaginary path along which a magnetic force acts around a magnet. Magnetic field lines originate from the North pole and end at the South pole.
āĻāϤā§āϤ⧰: āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻā§āώā§āϤā§ā§° ā§°ā§āĻāĻž āĻŦā§āϞāĻŋāϞ⧠āĻā§āĻŽā§āĻŦāĻā§° āĻāĻžā§°āĻŋāĻāĻĢāĻžāϞ⧠āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻŦāϞ āϝāĻŋ āĻāĻžāϞā§āĻĒāύāĻŋāĻ āĻĒāĻĨ āĻ āύā§āϏ⧰āĻŖ āĻā§°ā§ āϤāĻžāĻ āĻŦā§āĻāĻžāϝāĻŧāĨ¤ āĻāĻ ā§°ā§āĻāĻžāϏāĻŽā§āĻš āĻāϤā§āϤ⧰ āϧā§ā§°ā§ā§ąā§° āĻĒā§°āĻž āĻāϞāĻžāĻ āĻĻāĻā§āώāĻŋāĻŖ āϧā§ā§°ā§ā§ąāϤ āĻļā§āώ āĻšāϝāĻŧāĨ¤
Q2. State the Principle of a Galvanometer. āĻĒā§ā§°āĻļā§āύ: āĻā§āϝāĻžāϞāĻā§āύā§āĻŽāĻŋāĻāĻžā§°ā§° āύā§āϤāĻŋ āĻāϞā§āϞā§āĻ āĻā§°āĻžāĨ¤
Ans: A galvanometer works on the principle that a current-carrying conductor placed in a magnetic field experiences a force.
āĻāϤā§āϤ⧰: āĻā§āϝāĻžāϞāĻā§āύā§āĻŽāĻŋāĻāĻžā§° āĻāĻ āύā§āϤāĻŋāϤ āĻāĻžāĻŽ āĻā§°ā§ āϝ⧠āĻā§āĻŽā§āĻŦāĻā§āϝāĻŧ āĻā§āώā§āϤā§ā§°āϤ āϏā§āĻĨāĻžāĻĒāύ āĻā§°āĻž āϧāĻžā§°āĻžāĻŦāĻžāĻšā§ āĻĒā§°āĻŋāĻŦāĻžāĻšāĻā§ āĻāĻāĻž āĻŦāϞ āĻ āύā§āĻā§ą āĻā§°ā§āĨ¤
Q3. Write the Lens Formula. āĻĒā§ā§°āĻļā§āύ: āϞā§āύā§āϏ⧰ āϏā§āϤā§ā§° āϞāĻŋāĻāĻžāĨ¤
Ans: The lens formula is : āϞā§āύā§āϏ⧰ āϏā§āϤā§ā§° āĻš’āϞ -
1/f = 1/v + 1/u , f = focal length , v = image distance, u = object distance
āĻāϝāĻŧāĻžāϤ, f = āĻĢā§āĻāĻžāϞ āĻĻā§ā§°ā§āĻā§āϝ, v = āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ āĻĻā§ā§°āϤā§āĻŦ, u = āĻŦāϏā§āϤ⧠āĻĻā§ā§°āϤā§āĻŦ
Q4. What is an Electric Fuse? What is its function ? āĻĒā§ā§°āĻļā§āύ: āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āĻĢāĻŋāĻāĻ āĻāĻŋ? āĻāϝāĻŧāĻžā§° āĻāĻžā§°ā§āϝ āĻāĻŋ ?
Ans: An electric fuse is a safety device used to protect an electric circuit from overloading or short circuit. It works by melting and breaking the circuit when excessive current flows.
āĻāϤā§āϤ⧰: āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āĻĢāĻŋāĻāĻ āĻšā§āĻā§ āĻāĻāĻž āϏā§ā§°āĻā§āώāĻž āϝāύā§āϤā§ā§° āϝāĻŋ āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āĻĒā§°āĻŋāĻā§ā§°āĻŽāĻžāĻ āĻ āϧāĻŋāĻ āϧāĻžā§°āĻž āĻŦāĻž āĻļā§āĻŦā§°ā§āĻ āĻāĻžā§°ā§āĻāĻŋāĻā§° āĻĒā§°āĻž ā§°āĻā§āώāĻž āĻā§°ā§āĨ¤ āĻ āϧāĻŋāĻ āϧāĻžā§°āĻž āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻš’āϞ⧠āĻĢāĻŋāĻāĻ āĻāϞāĻŋ āĻĒā§°ā§ āĻā§°ā§ āĻĒā§°āĻŋāĻā§ā§°āĻŽāĻž āĻāĻžāĻāĻŋ āĻĻāĻŋāϝāĻŧā§āĨ¤
Board Writing Tip:
- Definition → 2 clear lines
- Formula → Proper symbols
- Language → Simple & neat
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Q1. Draw a ray diagram to show the image formed by a concave mirror when the object is placed beyond C.
āĻĒā§ā§°āĻļā§āύ: āĻŦāϏā§āϤā§āĻā§ C ā§° āĻŦāĻžāĻšāĻŋā§°āϤ ā§°āĻžāĻāĻŋāϞ⧠āĻ ā§ąāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§ āĻāĻ āύ āĻā§°āĻž āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋā§° ā§°ā§’ āĻĄāĻžāϝāĻŧāĻžāĻā§ā§°āĻžāĻŽ āĻāĻāĻāĻžāĨ¤
Ans: When the object is placed beyond the centre of curvature (C) of a concave mirror, the image is formed
- between F and C,
- real, inverted, and diminished.
āĻāϤā§āϤ⧰ : āϝā§āϤāĻŋāϝāĻŧāĻž āĻŦāϏā§āϤā§āĻā§ āĻ ā§ąāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§° āĻŦāĻā§ā§°āϤāĻžā§° āĻā§āύā§āĻĻā§ā§° (C) ā§° āĻŦāĻžāĻšāĻŋā§°āϤ ā§°āĻāĻž āĻšāϝāĻŧ, āϤā§āϤāĻŋāϝāĻŧāĻž āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ—
- F āĻā§°ā§ C ā§° āĻŽāĻžāĻāϤ āĻāĻ āĻŋāϤ āĻšāϝāĻŧ,
- āĻŦāĻžāϏā§āĻ¤ā§ą, āĻāϞā§āĻāĻž, āĻā§°ā§ āϏ⧰⧠āĻāĻāĻžā§°ā§° āĻšāϝāĻŧāĨ¤
Q2. Draw a labelled diagram of refraction of light through a rectangular glass slab. āĻĒā§ā§°āĻļā§āύ: āĻāϝāĻŧāϤāĻžāĻāĻžā§° āĻāĻžāĻāĻā§° āϏā§āϞā§āĻŦā§° āĻŽāĻžāĻā§ā§°ā§ āĻĒā§āĻšā§°ā§° āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖā§° āϞā§āĻŦā§āϞāϝā§āĻā§āϤ āĻāĻŋāϤā§ā§° āĻāĻāĻāĻžāĨ¤
Ans: A ray entering a rectangular glass slab bends towards the normal, and while emerging, bends away from the normal. The incident ray and emergent ray are parallel. āĻāϤā§āϤ⧰: āĻāĻžāĻāĻā§° āϏā§āϞā§āĻŦāϤ āĻĒā§ā§°ā§ąā§āĻļ āĻā§°āĻž āĻĒā§āĻšā§° āϞāĻŽā§āĻŦā§° āĻĢāĻžāϞ⧠āĻŦāĻžāĻāĻ āϞāϝāĻŧ, āĻā§°ā§ āĻāϞāĻžāĻ āĻāĻšā§āĻāϤ⧠āϞāĻŽā§āĻŦā§° āĻĒā§°āĻž āĻāĻāϤ⧰āĻŋ āϝāĻžāϝāĻŧāĨ¤ āĻĒāϤāĻŋāϤ ā§°āĻļā§āĻŽāĻŋ āĻā§°ā§ āύāĻŋā§°ā§āĻāϤ ā§°āĻļā§āĻŽāĻŋ āϏāĻŽāĻžāύā§āϤ⧰āĻžāϞ āĻšāϝāĻŧāĨ¤
Q3. Draw a ray diagram for image formation by a convex lens when the object is placed between F and 2F. āĻĒā§ā§°āĻļā§āύ: āĻŦāϏā§āϤā§āĻā§ F āĻā§°ā§ 2F ā§° āĻŽāĻžāĻāϤ ā§°āĻžāĻāĻŋāϞ⧠āĻāϤā§āϤāϞ āϞā§āύā§āϏ⧰ āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ āĻāĻ āύ⧰ āĻāĻŋāϤā§ā§° āĻāĻāĻāĻžāĨ¤
Ans: The image is formed beyond 2F, and it is real, inverted, and magnified. āĻāϤā§āϤ⧰ : āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ 2F ā§° āĻŦāĻžāĻšāĻŋā§°āϤ āĻāĻ āĻŋāϤ āĻšāϝāĻŧ āĻā§°ā§ āĻ āĻŦāĻžāϏā§āĻ¤ā§ą, āĻāϞā§āĻāĻž āĻā§°ā§ āĻĄāĻžāĻā§° āĻāĻāĻžā§°ā§° āĻšāϝāĻŧāĨ¤
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B. MCQs – Light Chapter
Q1. The focal length of a plane mirror is: āĻĒā§ā§°āĻļā§āύ: āϏāĻŽāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§° āĻĢā§āĻāĻžāϞ āĻĻā§ā§°ā§āĻā§āϝ āĻš’āϞ :
A. 10 cm B. 20 cm C. Infinite D. Zero
Ans: C. Infinite
Explanation: A plane mirror has an infinite radius of curvature, so its focal length is infinite. āĻŦā§āϝāĻžāĻā§āϝāĻž: āϏāĻŽāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§° āĻŦāĻā§ā§°āϤāĻžā§° āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ āĻ āϏā§āĻŽ, āϏā§āĻāĻŦāĻžāĻŦā§ āĻāϝāĻŧāĻžā§° āĻĢā§āĻāĻžāϞ āĻĻā§ā§°ā§āĻā§āϝ⧠āĻ āϏā§āĻŽāĨ¤
Q2. Which mirror is used as a shaving mirror ? āĻĒā§ā§°āĻļā§āύ: āĻĻāĻžāĻĄāĻŧāĻŋ āĻāĻāĻž āĻĻā§°ā§āĻĒāĻŖ āĻšāĻŋāĻāĻžāĻĒā§ āĻā§āύāĻā§ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻšāϝāĻŧ ?
A. Plane mirror B. Convex mirror C. Concave mirror D. Cylindrical mirror
Ans: C. Concave mirror
Explanation: A concave mirror forms a virtual, erect and magnified image when the object is close. āĻŦā§āϝāĻžāĻā§āϝāĻž: āĻ ā§ąāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§ āĻŦāϏā§āϤ⧠āĻāĻā§°āϤ āĻĨāĻžāĻāĻŋāϞ⧠āĻāĻžāϞā§āĻĒāύāĻŋāĻ, āϏā§āĻāĻž āĻā§°ā§ āĻĄāĻžāĻā§° āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ āĻāĻ āύ āĻā§°ā§āĨ¤
Q3. The bending of light when it enters a new medium is called: āĻĒā§ā§°āĻļā§āύ: āĻĒā§āĻšā§° āύāϤā§āύ āĻŽāĻžāϧā§āϝāĻŽāϤ āĻĒā§ā§°ā§ąā§āĻļ āĻā§°ā§āĻāϤ⧠āĻŦāĻžāĻāĻ āϞā§ā§ąāĻž āĻāĻāύāĻžāĻ āĻāĻŋ āĻŦā§āϞ⧠?
A. Reflection B. Dispersion C. Refraction D. Scattering
Ans: C. Refraction
Explanation: Change in direction of light due to change in medium is called refraction. āĻŦā§āϝāĻžāĻā§āϝāĻž: āĻŽāĻžāϧā§āϝāĻŽ āϏāϞāύāĻŋ āĻšā§ā§ąāĻžā§° āĻŦāĻžāĻŦā§ āĻĒā§āĻšā§°ā§° āĻĻāĻŋāĻļ āϏāϞāύāĻŋ āĻšā§ā§ąāĻžāĻā§ āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖ āĻŦā§āϞā§āĨ¤
Q4. Which lens always forms a virtual image ? āĻĒā§ā§°āĻļā§āύ: āĻā§āύāĻā§ āϞā§āύā§āϏ⧠āϏāĻĻāĻžāϝāĻŧ āĻāĻžāϞā§āĻĒāύāĻŋāĻ āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ āĻāĻ āύ āĻā§°ā§ ?
A. Convex lens B. Concave lens C. Cylindrical lens D. Bifocal lens
Ans: B. Concave lens
Explanation: A concave lens always forms a virtual, erect and diminished image. āĻŦā§āϝāĻžāĻā§āϝāĻž: āĻ ā§ąāϤāϞ āϞā§āύā§āϏ⧠āϏāĻĻāĻžāϝāĻŧ āĻāĻžāϞā§āĻĒāύāĻŋāĻ, āϏā§āĻāĻž āĻā§°ā§ āϏ⧰⧠āĻĒā§ā§°āϤāĻŋāĻā§āĻāĻŦāĻŋ āĻāĻ āύ āĻā§°ā§āĨ¤
Q5. The unit of power of a lens is: āĻĒā§ā§°āĻļā§āύ: āϞā§āύā§āϏ⧰ āĻā§āώāĻŽāϤāĻžā§° āĻāĻāĻ āĻāĻŋ ?
A. Metre B. Watt C. Dioptre D. Joule
Ans: C. Dioptre
Explanation: Power of lens is measured in Dioptre (D). āĻŦā§āϝāĻžāĻā§āϝāĻž: āϞā§āύā§āϏ⧰ āĻā§āώāĻŽāϤāĻž āĻĄāĻžāĻāĻ āĻĒā§āĻāĻžā§° (D) āϤ āĻā§āĻāĻž āĻšāϝāĻŧāĨ¤
Exam Final Tips (Light Chapter):
- Diagram → Neat + labelled
- MCQs → Concept-based
- Laws → Write in points