Physics 10th – āĻĒāĻĻāĻžā§°ā§āĻĨ āĻŦāĻŋāĻœā§āĻžāĻžāύ (āĻĻāĻļāĻŽ āĻļā§ā§°ā§‡āĻŖā§€) – MCQ Set 3


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  • Definition2 clear lines

  • FormulaProper symbols

  • LanguageSimple & neat


Q1. What is Electric Current? Write its SI unit. āĻĒā§ā§°āĻļā§āύ: āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āϧāĻžā§°āĻž āĻ•āĻŋ? āχāϝāĻŧāĻžā§° SI āĻāĻ•āĻ• āϞāĻŋāĻ–āĻžāĨ¤


Answer : Electric current is the rate of flow of electric charge through a conductor.
SI unit: Ampere (A)


āωāĻ¤ā§āϤ⧰ :
āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āϧāĻžā§°āĻž āĻŦ⧁āϞāĻŋāϞ⧇ āĻāĻ•āĻ• āϏāĻŽāϝāĻŧāϤ āĻĒā§°āĻŋāĻŦāĻžāĻšāϕ⧰ āĻŽāĻžāĻœā§‡ā§°ā§‡ āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻšā§‹ā§ąāĻž āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āĻ†ā§ąā§‡āĻļā§° āĻĒā§°āĻŋāĻŽāĻžāĻŖāĻ• āĻŦ⧁āϜāĻžāϝāĻŧāĨ¤ SI āĻāĻ•āĻ•: āĻāĻŽā§āĻĒāĻŋāϝāĻŧāĻžā§° (A)


Q2. State Ohm’s Law. āĻĒā§ā§°āĻļā§āύ: Ohm ā§° āύāĻŋāϝāĻŧāĻŽ āωāĻ˛ā§āϞ⧇āĻ– āϕ⧰āĻžāĨ¤


Ans: Ohm’s Law states that at constant temperature, the current through a conductor is directly proportional to the potential difference across its ends.


āωāĻ¤ā§āϤ⧰: Ohm ā§° āύāĻŋāϝāĻŧāĻŽ āĻ…āύ⧁āϏ⧰āĻŋ, āϤāĻžāĻĒāĻŽāĻžāĻ¤ā§āϰāĻž āĻ§ā§ā§°ā§ā§ą āĻĨāĻžāĻ•āĻŋāϞ⧇, āĻĒā§°āĻŋāĻŦāĻžāĻšāϕ⧰ āĻŽāĻžāĻœā§‡ā§°ā§‡ āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āϧāĻžā§°āĻž āϤāĻžā§° āĻĻ⧁āϟāĻž āĻĒā§ā§°āĻžāĻ¨ā§āϤ⧰ āĻŽāĻžāϜ⧰ āĻŦāĻŋāĻ­ā§ą āĻĒāĻžā§°ā§āĻĨāĻ•ā§āϝ⧰ āϏ⧈āϤ⧇ āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤāĻŋāĻ•āĨ¤




V = IR



Q3. Define Resistance. Write its SI unit. āĻĒā§ā§°āĻļā§āύ: āĻĒā§ā§°āϤāĻŋā§°ā§‹āϧ āĻ•āĻŋ? āχāϝāĻŧāĻžā§° SI āĻāĻ•āĻ• āϞāĻŋāĻ–āĻžāĨ¤


Answer : Resistance is the opposition offered by a conductor to the flow of electric current.
SI unit: Ohm (Ω). āωāĻ¤ā§āϤ⧰ : āĻĒā§ā§°āϤāĻŋā§°ā§‹āϧ āĻŦ⧁āϞāĻŋāϞ⧇ āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āϧāĻžā§°āĻžā§° āĻĒā§ā§°āĻŦāĻžāĻšāĻ• āĻŦāĻžāϧāĻž āĻĻāĻŋāϝāĻŧāĻž āϗ⧁āĻŖāĻ• āĻŦ⧁āϜāĻžāϝāĻŧāĨ¤
SI āĻāĻ•āĻ•: āĻ“āĻšāĻŽ (Ω)


Q4. What is Joule’s Law of Heating ? āĻĒā§ā§°āĻļā§āύ: Joule ā§° āωāĻˇā§āĻŖāϤāĻžā§° āύāĻŋāϝāĻŧāĻŽ āĻ•āĻŋ ?


Answer: The heat produced in a conductor is directly proportional to the square of current, resistance, and time.


āωāĻ¤ā§āϤ⧰: Joule ā§° āωāĻˇā§āĻŖāϤāĻžā§° āύāĻŋāϝāĻŧāĻŽ āĻ…āύ⧁āϏ⧰āĻŋ, āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āϤāĻžāĻĒ āϧāĻžā§°āĻžā§° āĻŦā§°ā§āĻ—, āĻĒā§ā§°āϤāĻŋā§°ā§‹āϧ āφ⧰⧁ āϏāĻŽāϝāĻŧā§° āϏ⧈āϤ⧇ āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤāĻŋāĻ•āĨ¤


H = I2Rt


Q5. What is a Fuse? Why is it used ? āĻĒā§ā§°āĻļā§āύ: Fuse āĻ•āĻŋ? āχāϝāĻŧāĻžā§° āĻŦā§āĻ¯ā§ąāĻšāĻžā§°ā§° āĻ•āĻžā§°āĻŖ āĻ•āĻŋ ?


Ans: A fuse is a safety device that melts when excess current flows and protects electrical appliances.


āωāĻ¤ā§āϤ⧰: Fuse āĻšā§ˆāϛ⧇ āĻāϟāĻž āϏ⧁⧰āĻ•ā§āώāĻž āϝāĻ¨ā§āĻ¤ā§ā§°āĨ¤ āĻ…āϧāĻŋāĻ• āϧāĻžā§°āĻž āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻš’āϞ⧇ āχ āĻ—āϞāĻŋ āĻĒ⧰⧇ āφ⧰⧁ āĻŦāĻŋāĻĻā§āĻ¯ā§ā§Ž āϝāĻ¨ā§āĻ¤ā§ā§°āϏāĻŽā§‚āĻšāĻ• ā§°āĻ•ā§āώāĻž āϕ⧰⧇āĨ¤


Q6. What is a Magnetic Field ? āĻĒā§ā§°āĻļā§āύ: āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° āĻ•āĻŋ ?


Ans: The region around a magnet where its magnetic force is experienced is called a magnetic field.


āωāĻ¤ā§āϤ⧰: āϚ⧁āĻŽā§āĻŦāϕ⧰ āϚāĻžā§°āĻŋāĻ“āĻĢāĻžāϞ⧇ āϝāĻŋ āĻ…āĻžā§āϚāϞāϤ āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻŦāϞ⧰ āĻĒā§ā§°āĻ­āĻžā§ą āĻ…āύ⧁āĻ­ā§ą āĻšāϝāĻŧ āϤāĻžāĻ• āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° āĻŦā§‹āϞ⧇āĨ¤


Q7. State Fleming’s Left-Hand Rule. āĻĒā§ā§°āĻļā§āύ: Fleming ā§° āĻŦāĻžāĻŽ-āĻšāĻžāϤ āύāĻŋāϝāĻŧāĻŽ āωāĻ˛ā§āϞ⧇āĻ– āϕ⧰āĻžāĨ¤


Ans: If the thumb, forefinger and middle finger of the left hand are stretched mutually perpendicular, they represent motion, magnetic field and current respectively.


āωāĻ¤ā§āϤ⧰: āĻŦāĻžāĻŽ āĻšāĻžāϤ⧰ āĻŦ⧁āĻĸāĻŧāĻž āφāϙ⧁āϞāĻŋ, āĻ¤ā§°ā§āϜāύ⧀ āφ⧰⧁ āĻŽāĻ§ā§āϝāĻŽāĻž āφāϙ⧁āϞāĻŋāĻ• āĻĒā§°āĻ¸ā§āĻĒ⧰⧇ āϞāĻŽā§āĻŦ āϕ⧰āĻŋ āϧ⧰āĻŋāϞ⧇ āϏāĻŋāĻšāρāϤ⧇ āĻ•ā§ā§°āĻŽā§‡ āĻ—āϤāĻŋ, āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° āφ⧰⧁ āϧāĻžā§°āĻž āϏ⧂āϚāĻžāϝāĻŧāĨ¤


Q8. What is Refraction of Light ? āĻĒā§ā§°āĻļā§āύ: āĻĒā§‹āĻšā§°ā§° āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖ āĻ•āĻŋ ?


Ans: Refraction of light is the bending of light when it passes from one medium to another.


āωāĻ¤ā§āϤ⧰: āĻāϟāĻž āĻŽāĻžāĻ§ā§āϝāĻŽā§° āĻĒā§°āĻž āφāύ āĻāϟāĻž āĻŽāĻžāĻ§ā§āϝāĻŽāϞ⧈ āĻĒā§‹āĻšā§° āϝāĻžāĻ“āρāϤ⧇ āĻĻāĻŋāĻļ āϏāϞāύāĻŋ āĻšā§‹ā§ąāĻžāϕ⧇ āĻĒā§‹āĻšā§°ā§° āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖ āĻŦā§‹āϞ⧇āĨ¤


Q9. Define the Power of a Lens. Write its unit. āĻĒā§ā§°āĻļā§āύ: āϞ⧇āĻ¨ā§āϏ⧰ āĻ•ā§āώāĻŽāϤāĻž āĻ•āĻŋ? āχāϝāĻŧāĻžā§° āĻāĻ•āĻ• āϞāĻŋāĻ–āĻžāĨ¤


Ans: Power of a lens is the ability of a lens to converge or diverge light. Unit: Dioptre (D)


āωāĻ¤ā§āϤ⧰: āϞ⧇āĻ¨ā§āϏ⧰ āĻ•ā§āώāĻŽāϤāĻž āĻŦ⧁āϞāĻŋāϞ⧇ āĻĒā§‹āĻšā§° āĻāĻ•āĻ¤ā§ā§° āĻŦāĻž āĻŦāĻŋāĻšā§āĻ›āĻŋāĻ¨ā§āύ āϕ⧰āĻžā§° āĻ•ā§āώāĻŽāϤāĻžāĻ• āĻŦ⧁āϜāĻžāϝāĻŧāĨ¤
āĻāĻ•āĻ•: āĻĄāĻžāχāĻ…āĻĒā§āϟāĻžā§° (D)


Q10. Name one renewable source of energy from oceans. āĻĒā§ā§°āĻļā§āύ: āϏāĻžāĻ—ā§°ā§° āĻĒā§°āĻž āĻĒā§‹ā§ąāĻž āĻāϟāĻž āύāĻŦā§€āϕ⧰āĻŖāϝ⧋āĻ—ā§āϝ āĻļāĻ•ā§āϤāĻŋā§° āĻ‰ā§ŽāϏ⧰ āύāĻžāĻŽ āϞāĻŋāĻ–āĻžāĨ¤


Ans: Tidal Energy is a renewable source of energy from oceans.


āωāĻ¤ā§āϤ⧰: āĻœā§‹āϝāĻŧāĻžā§°-āĻ­āĻžāϟāĻž āĻļāĻ•ā§āϤāĻŋ (Tidal Energy) āϏāĻžāĻ—ā§°ā§° āĻĒā§°āĻž āĻĒā§‹ā§ąāĻž āĻāϟāĻž āύāĻŦā§€āϕ⧰āĻŖāϝ⧋āĻ—ā§āϝ āĻļāĻ•ā§āϤāĻŋā§° āĻ‰ā§ŽāϏāĨ¤


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Q1. What is a Magnetic Field Line ? āĻĒā§ā§°āĻļā§āύ: āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° ⧰⧇āĻ–āĻž āĻ•āĻŋ ?


Ans: A magnetic field line is an imaginary path along which a magnetic force acts around a magnet. Magnetic field lines originate from the North pole and end at the South pole.


āωāĻ¤ā§āϤ⧰: āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° ⧰⧇āĻ–āĻž āĻŦ⧁āϞāĻŋāϞ⧇ āϚ⧁āĻŽā§āĻŦāϕ⧰ āϚāĻžā§°āĻŋāĻ“āĻĢāĻžāϞ⧇ āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻŦāϞ āϝāĻŋ āĻ•āĻžāĻ˛ā§āĻĒāύāĻŋāĻ• āĻĒāĻĨ āĻ…āύ⧁āϏ⧰āĻŖ āϕ⧰⧇ āϤāĻžāĻ• āĻŦ⧁āϜāĻžāϝāĻŧāĨ¤ āĻāχ ⧰⧇āĻ–āĻžāϏāĻŽā§‚āĻš āωāĻ¤ā§āϤ⧰ āĻ§ā§ā§°ā§ā§ąā§° āĻĒā§°āĻž āĻ“āϞāĻžāχ āĻĻāĻ•ā§āώāĻŋāĻŖ āĻ§ā§ā§°ā§ā§ąāϤ āĻļ⧇āώ āĻšāϝāĻŧāĨ¤


Q2. State the Principle of a Galvanometer. āĻĒā§ā§°āĻļā§āύ: āĻ—ā§āϝāĻžāϞāϭ⧇āύ⧋āĻŽāĻŋāϟāĻžā§°ā§° āύ⧀āϤāĻŋ āωāĻ˛ā§āϞ⧇āĻ– āϕ⧰āĻžāĨ¤


Ans: A galvanometer works on the principle that a current-carrying conductor placed in a magnetic field experiences a force.


āωāĻ¤ā§āϤ⧰: āĻ—ā§āϝāĻžāϞāϭ⧇āύ⧋āĻŽāĻŋāϟāĻžā§° āĻāχ āύ⧀āϤāĻŋāϤ āĻ•āĻžāĻŽ āϕ⧰⧇ āϝ⧇ āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°āϤ āĻ¸ā§āĻĨāĻžāĻĒāύ āϕ⧰āĻž āϧāĻžā§°āĻžāĻŦāĻžāĻšā§€ āĻĒā§°āĻŋāĻŦāĻžāĻšāϕ⧇ āĻāϟāĻž āĻŦāϞ āĻ…āύ⧁āĻ­ā§ą āϕ⧰⧇āĨ¤


Q3. Write the Lens Formula. āĻĒā§ā§°āĻļā§āύ: āϞ⧇āĻ¨ā§āϏ⧰ āϏ⧂āĻ¤ā§ā§° āϞāĻŋāĻ–āĻžāĨ¤


Ans: The lens formula is  : āϞ⧇āĻ¨ā§āϏ⧰ āϏ⧂āĻ¤ā§ā§° āĻš’āϞ -


1/f = 1/v + 1/u , f = focal length , v = image distance, u = object distance


āχāϝāĻŧāĻžāϤ, f = āĻĢā§‹āĻ•āĻžāϞ āĻĻā§ˆā§°ā§āĻ˜ā§āϝ, v = āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ āĻĻā§‚ā§°āĻ¤ā§āĻŦ, u = āĻŦāĻ¸ā§āϤ⧁ āĻĻā§‚ā§°āĻ¤ā§āĻŦ


Q4. What is an Electric Fuse? What is its function ? āĻĒā§ā§°āĻļā§āύ: āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āĻĢāĻŋāωāϜ āĻ•āĻŋ? āχāϝāĻŧāĻžā§° āĻ•āĻžā§°ā§āϝ āĻ•āĻŋ ?


Ans: An electric fuse is a safety device used to protect an electric circuit from overloading or short circuit. It works by melting and breaking the circuit when excessive current flows.


āωāĻ¤ā§āϤ⧰: āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āĻĢāĻŋāωāϜ āĻšā§ˆāϛ⧇ āĻāϟāĻž āϏ⧁⧰āĻ•ā§āώāĻž āϝāĻ¨ā§āĻ¤ā§ā§° āϝāĻŋ āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āĻĒā§°āĻŋāĻ•ā§ā§°āĻŽāĻžāĻ• āĻ…āϧāĻŋāĻ• āϧāĻžā§°āĻž āĻŦāĻž āĻļā§āĻŦā§°ā§āϟ āϚāĻžā§°ā§āĻ•āĻŋāϟ⧰ āĻĒā§°āĻž ā§°āĻ•ā§āώāĻž āϕ⧰⧇āĨ¤ āĻ…āϧāĻŋāĻ• āϧāĻžā§°āĻž āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻš’āϞ⧇ āĻĢāĻŋāωāϜ āĻ—āϞāĻŋ āĻĒ⧰⧇ āφ⧰⧁ āĻĒā§°āĻŋāĻ•ā§ā§°āĻŽāĻž āĻ­āĻžāĻ™āĻŋ āĻĻāĻŋāϝāĻŧ⧇āĨ¤


Board Writing Tip:



  • Definition2 clear lines

  • FormulaProper symbols

  • LanguageSimple & neat


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Q1. Draw a ray diagram to show the image formed by a concave mirror when the object is placed beyond C.


āĻĒā§ā§°āĻļā§āύ: āĻŦāĻ¸ā§āϤ⧁āĻŸā§‹ C ā§° āĻŦāĻžāĻšāĻŋā§°āϤ ā§°āĻžāĻ–āĻŋāϞ⧇ āĻ…ā§ąāϤāϞ āĻĻā§°ā§āĻĒāϪ⧇ āĻ—āĻ āύ āϕ⧰āĻž āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋā§° ⧰⧇’ āĻĄāĻžāϝāĻŧāĻžāĻ—ā§ā§°āĻžāĻŽ āφāρāĻ•āĻžāĨ¤


Ans: When the object is placed beyond the centre of curvature (C) of a concave mirror, the image is formed



  • between F and C,

  • real, inverted, and diminished.


āωāĻ¤ā§āϤ⧰ : āϝ⧇āϤāĻŋāϝāĻŧāĻž āĻŦāĻ¸ā§āϤ⧁āĻŸā§‹ āĻ…ā§ąāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§° āĻŦāĻ•ā§ā§°āϤāĻžā§° āϕ⧇āĻ¨ā§āĻĻā§ā§° (C) ā§° āĻŦāĻžāĻšāĻŋā§°āϤ ā§°āĻ–āĻž āĻšāϝāĻŧ, āϤ⧇āϤāĻŋāϝāĻŧāĻž āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ—



  • F āφ⧰⧁ C ā§° āĻŽāĻžāϜāϤ āĻ—āĻ āĻŋāϤ āĻšāϝāĻŧ,

  • āĻŦāĻžāĻ¸ā§āĻ¤ā§ą, āωāĻ˛ā§āϟāĻž, āφ⧰⧁ āϏ⧰⧁ āφāĻ•āĻžā§°ā§° āĻšāϝāĻŧāĨ¤


Q2. Draw a labelled diagram of refraction of light through a rectangular glass slab. āĻĒā§ā§°āĻļā§āύ: āφāϝāĻŧāϤāĻžāĻ•āĻžā§° āĻ•āĻžāρāϚ⧰ āĻ¸ā§āϞ⧇āĻŦā§° āĻŽāĻžāĻœā§‡ā§°ā§‡ āĻĒā§‹āĻšā§°ā§° āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖā§° āϞ⧇āĻŦ⧇āϞāϝ⧁āĻ•ā§āϤ āϚāĻŋāĻ¤ā§ā§° āφāρāĻ•āĻžāĨ¤


Ans: A ray entering a rectangular glass slab bends towards the normal, and while emerging, bends away from the normal. The incident ray and emergent ray are parallel. āωāĻ¤ā§āϤ⧰: āĻ•āĻžāρāϚ⧰ āĻ¸ā§āϞ⧇āĻŦāϤ āĻĒā§ā§°ā§ąā§‡āĻļ āϕ⧰āĻž āĻĒā§‹āĻšā§° āϞāĻŽā§āĻŦā§° āĻĢāĻžāϞ⧇ āĻŦāĻžāρāĻ• āϞāϝāĻŧ, āφ⧰⧁ āĻ“āϞāĻžāχ āφāĻšā§‹āρāϤ⧇ āϞāĻŽā§āĻŦā§° āĻĒā§°āĻž āφāρāϤ⧰āĻŋ āϝāĻžāϝāĻŧāĨ¤ āĻĒāϤāĻŋāϤ ā§°āĻļā§āĻŽāĻŋ āφ⧰⧁ āύāĻŋā§°ā§āĻ—āϤ ā§°āĻļā§āĻŽāĻŋ āϏāĻŽāĻžāĻ¨ā§āϤ⧰āĻžāϞ āĻšāϝāĻŧāĨ¤


Q3. Draw a ray diagram for image formation by a convex lens when the object is placed between F and 2F. āĻĒā§ā§°āĻļā§āύ: āĻŦāĻ¸ā§āϤ⧁āĻŸā§‹ F āφ⧰⧁ 2F ā§° āĻŽāĻžāϜāϤ ā§°āĻžāĻ–āĻŋāϞ⧇ āωāĻ¤ā§āϤāϞ āϞ⧇āĻ¨ā§āϏ⧰ āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ āĻ—āĻ āύ⧰ āϚāĻŋāĻ¤ā§ā§° āφāρāĻ•āĻžāĨ¤


Ans: The image is formed beyond 2F, and it is real, inverted, and magnified. āωāĻ¤ā§āϤ⧰ : āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ 2F ā§° āĻŦāĻžāĻšāĻŋā§°āϤ āĻ—āĻ āĻŋāϤ āĻšāϝāĻŧ āφ⧰⧁ āχ āĻŦāĻžāĻ¸ā§āĻ¤ā§ą, āωāĻ˛ā§āϟāĻž āφ⧰⧁ āĻĄāĻžāϙ⧰ āφāĻ•āĻžā§°ā§° āĻšāϝāĻŧāĨ¤


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B. MCQs – Light Chapter 


Q1. The focal length of a plane mirror is: āĻĒā§ā§°āĻļā§āύ: āϏāĻŽāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§° āĻĢā§‹āĻ•āĻžāϞ āĻĻā§ˆā§°ā§āĻ˜ā§āϝ āĻš’āϞ :


A. 10 cm  B. 20 cm  C. Infinite  D. Zero


Ans: C. Infinite


Explanation: A plane mirror has an infinite radius of curvature, so its focal length is infinite. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āϏāĻŽāϤāϞ āĻĻā§°ā§āĻĒāĻŖā§° āĻŦāĻ•ā§ā§°āϤāĻžā§° āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ āĻ…āϏ⧀āĻŽ, āϏ⧇āχāĻŦāĻžāĻŦ⧇ āχāϝāĻŧāĻžā§° āĻĢā§‹āĻ•āĻžāϞ āĻĻā§ˆā§°ā§āĻ˜ā§āϝ⧋ āĻ…āϏ⧀āĻŽāĨ¤


Q2. Which mirror is used as a shaving mirror ? āĻĒā§ā§°āĻļā§āύ: āĻĻāĻžāĻĄāĻŧāĻŋ āĻ•āϟāĻž āĻĻā§°ā§āĻĒāĻŖ āĻšāĻŋāϚāĻžāĻĒ⧇ āϕ⧋āύāĻŸā§‹ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻšāϝāĻŧ ?


A. Plane mirror  B. Convex mirror  C. Concave mirror  D. Cylindrical mirror


Ans: C. Concave mirror


Explanation: A concave mirror forms a virtual, erect and magnified image when the object is close. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻ…ā§ąāϤāϞ āĻĻā§°ā§āĻĒāϪ⧇ āĻŦāĻ¸ā§āϤ⧁ āĻ“āϚ⧰āϤ āĻĨāĻžāĻ•āĻŋāϞ⧇ āĻ•āĻžāĻ˛ā§āĻĒāύāĻŋāĻ•, āϏ⧋āϜāĻž āφ⧰⧁ āĻĄāĻžāϙ⧰ āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ āĻ—āĻ āύ āϕ⧰⧇āĨ¤


Q3. The bending of light when it enters a new medium is called: āĻĒā§ā§°āĻļā§āύ: āĻĒā§‹āĻšā§° āύāϤ⧁āύ āĻŽāĻžāĻ§ā§āϝāĻŽāϤ āĻĒā§ā§°ā§ąā§‡āĻļ āϕ⧰⧋āρāϤ⧇ āĻŦāĻžāρāĻ• āĻ˛ā§‹ā§ąāĻž āϘāϟāύāĻžāĻ• āĻ•āĻŋ āĻŦā§‹āϞ⧇ ?


A. Reflection  B. Dispersion  C. Refraction  D. Scattering


Ans: C. Refraction


Explanation: Change in direction of light due to change in medium is called refraction. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻŽāĻžāĻ§ā§āϝāĻŽ āϏāϞāύāĻŋ āĻšā§‹ā§ąāĻžā§° āĻŦāĻžāĻŦ⧇ āĻĒā§‹āĻšā§°ā§° āĻĻāĻŋāĻļ āϏāϞāύāĻŋ āĻšā§‹ā§ąāĻžāϕ⧇ āĻĒā§ā§°āϤāĻŋāϏ⧰āĻŖ āĻŦā§‹āϞ⧇āĨ¤


Q4. Which lens always forms a virtual image ? āĻĒā§ā§°āĻļā§āύ: āϕ⧋āύāĻŸā§‹ āϞ⧇āĻ¨ā§āϏ⧇ āϏāĻĻāĻžāϝāĻŧ āĻ•āĻžāĻ˛ā§āĻĒāύāĻŋāĻ• āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ āĻ—āĻ āύ āϕ⧰⧇ ?


A. Convex lens  B. Concave lens  C. Cylindrical lens  D. Bifocal lens


Ans: B. Concave lens


Explanation: A concave lens always forms a virtual, erect and diminished image. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻ…ā§ąāϤāϞ āϞ⧇āĻ¨ā§āϏ⧇ āϏāĻĻāĻžāϝāĻŧ āĻ•āĻžāĻ˛ā§āĻĒāύāĻŋāĻ•, āϏ⧋āϜāĻž āφ⧰⧁ āϏ⧰⧁ āĻĒā§ā§°āϤāĻŋāĻšā§āĻ›āĻŦāĻŋ āĻ—āĻ āύ āϕ⧰⧇āĨ¤


Q5. The unit of power of a lens is: āĻĒā§ā§°āĻļā§āύ: āϞ⧇āĻ¨ā§āϏ⧰ āĻ•ā§āώāĻŽāϤāĻžā§° āĻāĻ•āĻ• āĻ•āĻŋ ? 


A. Metre  B. Watt  C. Dioptre  D. Joule


Ans: C. Dioptre


Explanation: Power of lens is measured in Dioptre (D). āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āϞ⧇āĻ¨ā§āϏ⧰ āĻ•ā§āώāĻŽāϤāĻž āĻĄāĻžāχāĻ…āĻĒā§āϟāĻžā§° (D) āϤ āϜ⧁āĻ–āĻž āĻšāϝāĻŧāĨ¤


Exam Final Tips (Light Chapter):



  • Diagram → Neat + labelled

  • MCQs → Concept-based

  • Laws → Write in points