Chemestry 10th : ā§°āϏāĻžāϝāĻŧāύ āĻŦāĻŋāĻā§āĻāĻžāύ (āĻĻāĻļāĻŽ āĻļā§ā§°ā§āĻŖā§) â MCQ Set 2
HSLC Chemestry – Full Mock Test
Section–A : MCQs (1 × 20 = 20 marks)
Q1. What is the pH of pure water ? āĻŦāĻŋāĻļā§āĻĻā§āϧ āĻĒāĻžāύā§ā§° pH āĻŽāĻžāύ āĻāĻŋāĻŽāĻžāύ ?
A. 0 B. 5 C. 7 D. 14
Ans: C
Explanation: Pure water is neutral (pH = 7). āĻŦā§āϝāĻžāĻā§āϝāĻž: āĻŦāĻŋāĻļā§āĻĻā§āϧ āĻĒāĻžāύ⧠āύāĻŋā§°āĻĒā§āĻā§āώāĨ¤
Q2. Which acid is present in vinegar ? āĻāĻŋāύā§āĻāĻžā§°āϤ āĻā§āύāĻā§ āĻāĻŽā§āϞ āĻĨāĻžāĻā§ ?
A. Citric B. Lactic C. Acetic D. Oxalic
Ans: C
Explanation: Vinegar contains acetic acid.
Q3. Which metal is used for galvanization ? āĻā§āϝāĻžāϞāĻāĻžāύāĻžāĻāĻā§āĻāύāϤ āĻā§āύāĻā§ āϧāĻžāϤ⧠āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻž āĻšāϝāĻŧ ?
A. Copper B. Zinc C. Iron D. Aluminium
Ans: B
Explanation: Zinc coating prevents rusting.
Q4. What gas is released when acid reacts with metal ?
Q4. āĻāĻŽā§āϞ⧠āϧāĻžāϤā§ā§° āϏā§āϤ⧠āĻŦāĻŋāĻā§ā§°āĻŋāϝāĻŧāĻž āĻā§°āĻŋāϞ⧠āĻā§āύāĻā§ āĻā§āĻ āĻāϞāĻžāϝāĻŧ ?
A. COâ B. Oâ C. Hâ D. Nâ
Ans: C
Q5. Which element shows maximum catenation ? āĻā§āύāĻā§ āĻŽā§āϞ⧠āϏ⧰ā§āĻŦāĻžāϧāĻŋāĻ āĻā§āĻā§āύā§āĻāύ āĻĻā§āĻā§ā§ąāĻžāϝāĻŧ ?
A. Silicon B. Carbon C. Oxygen D. Nitrogen
Ans: B
Q6. The chemical formula of baking soda is - āĻŦā§āĻāĻŋāĻ āĻ’āĻĄāĻžā§° ā§°āĻžāϏāĻžāϝāĻŧāύāĻŋāĻ āϏāĻāĻā§āϤ -
A. NaâCOâ B. NaHCOâ C. CaCOâ D. NaOH
Ans: B
Q7. Which indicator turns pink in base ? āĻā§āύāĻā§ āϏā§āĻāĻā§ āĻā§āώāĻžā§°āϤ āĻā§āϞāĻĒā§āϝāĻŧāĻž ā§°āĻ āĻšāϝāĻŧ ?
A. Litmus B. Turmeric C. Phenolphthalein D. Methyl orange
Ans: C
Q8. Rusting of iron is an example of - āϞā§āĻšāĻžā§° āĻŽā§°āĻā§ āϧ⧰āĻž āĻāĻāĻž āĻāĻĻāĻžāĻšā§°āĻŖ -
A. Reduction B. Oxidation C. Neutralization D. Decomposition
Ans: B
Q9. Atomic number depends on number of -āĻĒāĻžā§°āĻŽāĻžāĻŖā§ąāĻŋāĻ āϏāĻāĻā§āϝāĻž āĻāĻŋāĻšā§° āĻāĻĒā§°āϤ āύāĻŋā§°ā§āĻā§° āĻā§°ā§ ?
A. Neutrons B. Electrons C. Protons D. Ions
Ans: C
Q10. Washing soda is - ā§ąāĻžāĻļāĻŋāĻ āĻ’āĻĄāĻž āĻšā§āĻā§ -
A. NaâCOâ B. NaâCOâ·10HâO C. NaHCOâ D. CaCOâ
Ans: B
Section–B : VSA (Very Short Answer) (1 × 10 = 10 marks)
Q21. Define an Indicator. āϏā§āĻāĻ āĻāĻŋ ?
Ans: An indicator is a substance that changes colour in acidic or basic solutions. āĻāϤā§āϤ⧰: āϏā§āĻāĻ āĻšā§āĻā§ āĻāύ⧠āĻāĻāĻž āĻĒāĻĻāĻžā§°ā§āĻĨ āϝāĻŋāϝāĻŧā§ āĻāĻŽā§āϞ āĻŦāĻž āĻā§āώāĻžā§° āĻĻā§ā§°āĻžā§ąāĻŖāϤ ā§°āĻ āϏāϞāύāĻŋ āĻā§°ā§āĨ¤
Q22. What is Oxidation ? āĻ āĻā§āϏāĻŋāĻĄā§āĻāύ āĻāĻŋ ?
Answer: Oxidation is the gain of oxygen or loss of hydrogen. āĻāϤā§āϤ⧰: āĻ āĻā§āϏāĻŋāĻĄā§āĻāύ āĻšā§āĻā§ āĻ āĻā§āϏāĻŋāĻā§āύ āϞāĻžāĻ āĻā§°āĻž āĻŦāĻž āĻšāĻžāĻāĻĄā§ā§°’āĻā§āύ āĻšā§ā§°ā§āĻā§ąāĻžāĨ¤
Q23. Write one use of baking soda. āĻŦā§āĻāĻŋāĻ āĻ’āĻĄāĻžā§° āĻāĻāĻž āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϞāĻŋāĻāĻžāĨ¤
Ans: Baking soda is used in fire extinguishers. āĻāϤā§āϤ⧰: āĻŦā§āĻāĻŋāĻ āĻ’āĻĄāĻž āĻ āĻā§āύāĻŋāύāĻŋā§°ā§āĻŦāĻžāĻĒāĻ āϝāύā§āϤā§ā§°āϤ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻž āĻšāϝāĻŧāĨ¤
Section–C : SA (Short Answer)
Q24. State two properties of acids. āĻāĻŽā§āϞ⧰ āĻĻā§āĻāĻž āĻā§āĻŖ āϞāĻŋāĻāĻžāĨ¤
Ans: 1. Acids are sour in taste. 2. Acids turn blue litmus red.
āĻāϤā§āϤ⧰: 1. āĻāĻŽā§āϞ āĻā§āĻāĻž āϏā§ā§ąāĻžāĻĻā§° āĻšāϝāĻŧāĨ¤ 2. āĻāĻŽā§āϞ⧠āύā§āϞāĻž āϞāĻŋāĻāĻŽāĻžāĻ āĻāĻžāĻāĻ ā§°āĻāĻž āĻā§°ā§āĨ¤
Q25. Why does carbon form a large number of compounds ? āĻāĻžā§°ā§āĻŦāύ⧠āĻāĻŋāϝāĻŧ āĻŦāĻšā§ āϏāĻāĻā§āϝāĻ āϝā§āĻ āĻāĻ āύ āĻā§°āĻŋāĻŦ āĻĒāĻžā§°ā§ ?
Ans: Carbon forms many compounds due to: 1. Catenation 2. Tetravalency
āĻāϤā§āϤ⧰: āĻāĻžā§°ā§āĻŦāύ⧠āĻŦāĻšā§ āϝā§āĻ āĻāĻ āύ āĻā§°ā§ āĻāĻžā§°āĻŖ - 1. āĻā§āĻā§āύā§āĻāύ 2. āĻāϤā§ā§°ā§āĻŽā§āϞāĻāϤāĻž
Section - D : LA (Long Answer)
Q26. Explain the Modern Periodic Law. āĻāϧā§āύāĻŋāĻ āĻĒā§°ā§āϝāĻžāϝāĻŧ āĻŦāĻŋāϧāĻŋ āĻŦā§āϝāĻžāĻā§āϝāĻž āĻā§°āĻžāĨ¤
Ans: The Modern Periodic Law states that the properties of elements are periodic functions of their atomic numbers. āĻāϧā§āύāĻŋāĻ āĻĒā§°ā§āϝāĻžāϝāĻŧ āĻŦāĻŋāϧāĻŋ āĻ āύā§āϏāĻžā§°ā§ āĻŽā§āϞāϏāĻŽā§āĻšā§° āĻā§āĻŖāϏāĻŽā§āĻš āϤā§āĻāĻāϞā§āĻā§° āĻĒāĻžā§°āĻŽāĻžāĻŖā§ąāĻŋāĻ āϏāĻāĻā§āϝāĻžā§° āĻĒā§āύ⧰āĻžāĻŦā§āϤā§āϤāĻŋāĻŽā§āϞāĻ āĻĢāϞāĨ¤
Q27. Explain rusting of iron with conditions. āĻļāϰā§āϤāϏāĻš āϞā§āĻšāĻžā§° āĻŽā§°āĻā§ āϧ⧰āĻž āĻŦā§āϝāĻžāĻā§āϝāĻž āĻā§°āĻžāĨ¤
Ans: Rusting of iron is a slow oxidation process.
The conditions required for rusting are: 1. Presence of oxygen 2. Presence of moisture (water)
āĻāϤā§āϤ⧰: āϞā§āĻšāĻžā§° āĻŽā§°āĻā§ āϧ⧰āĻž āĻāĻāĻž āϧā§ā§° āĻ āĻā§āϏāĻŋāĻĄā§āĻāύ āĻĒā§ā§°āĻā§ā§°āĻŋāϝāĻŧāĻžāĨ¤ āĻŽā§°āĻā§ āϧ⧰āĻŋāĻŦāϞ⧠āĻĒā§ā§°āϝāĻŧā§āĻāύā§āϝāĻŧ āĻļāϰā§āϤāϏāĻŽā§āĻš āĻšā§āĻā§ - 1. āĻ āĻā§āϏāĻŋāĻā§āύ⧰ āĻāĻĒāϏā§āĻĨāĻŋāϤāĻŋ 2. āĻāϰā§āĻĻā§ā§°āϤāĻž (āĻĒāĻžāύā§)ā§° āĻāĻĒāϏā§āĻĨāĻŋāϤāĻŋ
HSLC Writing Tip:
- VSA → ā§§ āϞāĻžāĻāύ
- SA → ⧍āĻāĻž āĻĒāĻāĻŖā§āĻ
- LA → āϏāĻāĻā§āĻāĻž + āĻĒāĻāĻŖā§āĻ
Q28. Calculate the pH of a neutral solution. āύāĻŋā§°āĻĒā§āĻā§āώ āĻĻā§ā§°āĻžā§ąāĻŖā§° pH āĻŽāĻžāύ āĻāĻŖāύāĻž āĻā§°āĻžāĨ¤
Soln: āϏāĻŽāĻžāϧāĻžāύ:
Neutral solution → pH = 7 : āύāĻŋā§°āĻĒā§āĻā§āώ āĻĻā§ā§°āĻžā§ąāĻŖā§° pH āĻŽāĻžāύ = ā§
Q29. Find the molecular mass of HâSOâ. HâSOâ ā§° āĻ āĻŖā§ āĻā§° āύāĻŋā§°ā§āĻŖāϝāĻŧ āĻā§°āĻžāĨ¤
Soln: āϏāĻŽāĻžāϧāĻžāύ:
H = 1 × 2 = 2
S = 32 × 1 = 32
O = 16 × 4 = 64
Molecular Mass = 2 + 32 + 64 = 98 u
HâSOâ ā§° āĻ āĻŖā§ āĻā§° = ā§¯ā§Ž u
Q30. How many moles are present in 44 g of COâ ? ā§Ēā§Ē āĻā§ā§°āĻžāĻŽ COâ āϤ āĻāĻŋāĻŽāĻžāύ āĻŽ’āϞ āĻĨāĻžāĻā§ ?
Soln: āϏāĻŽāĻžāϧāĻžāύ:
Molar mass of COâ = 44 g
Moles = mass / molar mass = 44 / 44 = 1 mole
āĻŽ’āϞ = ā§Ēā§Ē ÷ ā§Ēā§Ē = ā§§ āĻŽ’āϞ
Q31. Name the salt formed when HCl reacts with NaOH. HCl āĻā§°ā§ NaOH ā§° āĻŦāĻŋāĻā§ā§°āĻŋāϝāĻŧāĻžāϤ āĻāĻ āĻŋāϤ āĻ˛ā§ąāĻŖā§° āύāĻžāĻŽ āϞāĻŋāĻāĻžāĨ¤
Ans: Sodium chloride (NaCl) āĻāϤā§āϤ⧰: āĻ’āĻĄāĻŋāϝāĻŧāĻžāĻŽ āĻā§āϞ’ā§°āĻžāĻāĻĄ (NaCl)
Q32. What is corrosion ? āĻā§āώāϝāĻŧ (Corrosion) āĻāĻŋ ?
Ans: Corrosion is the slow destruction of metals due to chemical reaction with air and moisture. āĻāϤā§āϤ⧰: āĻā§āώāϝāĻŧ āĻšā§āĻā§ āĻŦāĻžāϝāĻŧā§ āĻā§°ā§ āĻāϰā§āĻĻā§ā§°āϤāĻžā§° āϏā§āϤ⧠⧰āĻžāϏāĻžāϝāĻŧāύāĻŋāĻ āĻŦāĻŋāĻā§ā§°āĻŋāϝāĻŧāĻžā§° āĻĢāϞāϤ āϧāĻžāϤ⧠āϧā§ā§°ā§ āϧā§ā§°ā§ āύāώā§āĻ āĻšā§ā§ąāĻž āĻĒā§ā§°āĻā§ā§°āĻŋāϝāĻŧāĻžāĨ¤
Q33. Name the gas released during electrolysis of water. āĻĒāĻžāύā§ā§° āĻāϞā§āĻā§āĻā§ā§°’āϞāĻžāĻāĻāĻŋāĻāϤ āĻā§āύāĻā§ āĻā§āĻ āĻāϞāĻžāϝāĻŧ ?
Ans: Hydrogen and Oxygen āĻāϤā§āϤ⧰ : āĻšāĻžāĻāĻĄā§ā§°’āĻā§āύ āĻā§°ā§ āĻ āĻā§āϏāĻŋāĻā§āύ
Q34. Write two differences between acids and bases. āĻāĻŽā§āϞ āĻā§°ā§ āĻā§āώāĻžā§°ā§° āĻŽāĻžāĻāϤ āĻĻā§āĻāĻž āĻĒāĻžā§°ā§āĻĨāĻā§āϝ āϞāĻŋāĻāĻžāĨ¤
Ans: 1. Acids release Hâē ions, bases release OHâģ ions. 2. Acids turn blue litmus red, bases turn red litmus blue.
āĻāϤā§āϤ⧰ : 1. āĻāĻŽā§āϞ⧠Hâē āĻāϝāĻŧāύ āĻā§°āĻŋ āĻĻāĻŋāϝāĻŧā§, āĻā§āώāĻžā§°ā§ OHâģ āĻāϝāĻŧāύ āĻā§°āĻŋ āĻĻāĻŋāϝāĻŧā§āĨ¤ 2. āĻāĻŽā§āϞ⧠āύā§āϞāĻž āϞāĻŋāĻāĻŽāĻžāĻ ā§°āĻāĻž āĻā§°ā§, āĻā§āώāĻžā§°ā§ ā§°āĻāĻž āϞāĻŋāĻāĻŽāĻžāĻ āύā§āϞāĻž āĻā§°ā§āĨ¤
Q35. What is bleaching powder ? Write one use. Q35. āĻŦā§āϞāĻŋāĻāĻŋāĻ āĻĒāĻžāĻāĻĄāĻžā§° āĻāĻŋ ? āĻāĻāĻž āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϞāĻŋāĻāĻžāĨ¤
Ans: Bleaching powder is calcium oxychloride (CaOClâ). It is used for disinfecting drinking water.
āĻāϤā§āϤ⧰: āĻŦā§āϞāĻŋāĻāĻŋāĻ āĻĒāĻžāĻāĻĄāĻžā§° āĻšā§āĻā§ āĻā§āϞāĻāĻŋāϝāĻŧāĻžāĻŽ āĻ āĻā§āϏāĻŋāĻā§āϞ’ā§°āĻžāĻāĻĄ (CaOClâ)āĨ¤ āĻ āĻĒāĻžāύ⧠āĻŦāĻŋāĻļā§āĻĻā§āϧ āĻā§°āĻŋāĻŦāϞ⧠āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻž āĻšāϝāĻŧāĨ¤
Section–D : Long Answer (āĻĻā§āĻāϞ āĻāϤā§āϤ⧰⧰ āĻĒā§ā§°āĻļā§āύ) (4 × 2)
Q36. Explain neutralization reaction with example. āĻāĻĻāĻžāĻšā§°āĻŖāϏāĻš āύāĻŋāĻāĻā§ā§°āĻžāϞāĻžāĻāĻā§āĻāύ āĻŦāĻŋāĻā§ā§°āĻŋāϝāĻŧāĻž āĻŦā§āϝāĻžāĻā§āϝāĻž āĻā§°āĻžāĨ¤
Ans: Neutralization reaction is a reaction between an acid and a base to form salt and water.
Ex: HCl + NaOH → NaCl + HâO
āĻāϤā§āϤ⧰: āĻāĻŽā§āϞ āĻā§°ā§ āĻā§āώāĻžā§°ā§° āĻŽāĻžāĻāϤ āĻšā§ā§ąāĻž āĻŦāĻŋāĻā§ā§°āĻŋāϝāĻŧāĻžāϤ āĻ˛ā§ąāĻŖ āĻā§°ā§ āĻĒāĻžāύ⧠āĻāĻ āĻŋāϤ āĻšāϞ⧠āϤāĻžāĻ āύāĻŋāĻāĻā§ā§°āĻžāϞāĻžāĻāĻā§āĻāύ āĻŦāĻŋāĻā§ā§°āĻŋāϝāĻŧāĻž āĻŦā§āϞā§āĨ¤
āĻāĻĻāĻžāĻšā§°āĻŖ: HCl + NaOH → NaCl + HâO
Q37. Explain Faraday’s First Law of Electrolysis. āĻĢāĻžā§°āĻžāĻĄā§ā§° āĻĒā§ā§°āĻĨāĻŽ āĻāϞā§āĻā§āĻā§ā§°’āϞāĻžāĻāĻāĻŋāĻ āĻŦāĻŋāϧāĻŋ āĻŦā§āϝāĻžāĻā§āϝāĻž āĻā§°āĻžāĨ¤
Ans: The mass of a substance deposited at an electrode is directly proportional to the quantity of electricity passed.
āĻāϤā§āϤ⧰: āĻāϞā§āĻā§āĻā§ā§°’āϞāĻžāĻāĻāĻŋāĻā§° āϏāĻŽāϝāĻŧāϤ āĻāϞā§āĻā§āĻā§ā§°’āĻĄāϤ āĻāĻŽāĻž āĻšā§ā§ąāĻž āĻĒāĻĻāĻžā§°ā§āĻĨā§° āĻā§° āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻŦāĻŋāĻĻā§āϝā§ā§ā§° āĻĒā§°āĻŋāĻŽāĻžāĻŖā§° āϏā§āϤ⧠āϏāĻŽāĻžāύā§āĻĒāĻžāϤāĻŋāĻāĨ¤