HSLC 2026 Model Question Paper
Subject: Science (Physics)
Chapter: Light – Reflection by Spherical Mirrors
Section A : Very Short Answer (1 × 5 = 5)
- Q: Which mirror always forms an erect image ?
Ans: Convex mirror
āĻĒā§ā§°āĻļā§āĻ¨: āĻ¸āĻĻāĻžāĻ¯āĻŧ āĻ¸ā§āĻāĻž āĻĒā§ā§°āĻ¤āĻŋāĻŦāĻŋāĻŽā§āĻŦ āĻāĻ āĻ¨ āĻā§°āĻž āĻĻā§°ā§āĻĒāĻŖ āĻā§āĻ¨āĻā§ ?
āĻāĻ¤ā§āĻ¤ā§°: āĻāĻ¤ā§āĻ¤āĻ˛ āĻĻā§°ā§āĻĒāĻŖ - Q: Write the SI unit of focal length.
Ans: metre (m)
āĻĒā§ā§°āĻļā§āĻ¨: āĻĢā§āĻāĻžāĻ˛ āĻĻā§ā§°ā§āĻā§āĻ¯ā§° SI āĻāĻāĻ āĻ˛āĻŋāĻāĻžāĨ¤
āĻāĻ¤ā§āĻ¤ā§°: āĻŽāĻŋāĻāĻžā§° (m) - Q: What is the sign of focal length of a concave mirror ?
Ans: Negative
āĻĒā§ā§°āĻļā§āĻ¨: āĻ ā§ąāĻ¤āĻ˛ āĻĻā§°ā§āĻĒāĻŖā§° āĻĢā§āĻāĻžāĻ˛ āĻĻā§ā§°ā§āĻā§āĻ¯ā§° āĻāĻŋāĻšā§āĻ¨ āĻāĻŋ ?
āĻāĻ¤ā§āĻ¤ā§°: āĻāĻŖāĻžāĻ¤ā§āĻŽāĻ - Q: Which mirror is used as rear-view mirror ?
Ans: Convex mirror
āĻĒā§ā§°āĻļā§āĻ¨: ā§°āĻŋāĻ¯āĻŧāĻžā§°-āĻāĻŋāĻ āĻŽāĻŋā§°ā§° āĻšāĻŋāĻāĻžāĻĒā§ āĻā§āĻ¨āĻā§ āĻĻā§°ā§āĻĒāĻŖ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻž āĻšāĻ¯āĻŧ ?
āĻāĻ¤ā§āĻ¤ā§°: āĻāĻ¤ā§āĻ¤āĻ˛ āĻĻā§°ā§āĻĒāĻŖ - Q: Write the relation between focal length and radius of curvature.
Ans: f=R2f = \dfrac{R}{2}
āĻĒā§ā§°āĻļā§āĻ¨: āĻĢā§āĻāĻžāĻ˛ āĻĻā§ā§°ā§āĻā§āĻ¯ āĻā§°ā§ āĻŦāĻā§ā§°āĻ¤āĻžā§° āĻŦā§āĻ¯āĻžāĻ¸āĻžā§°ā§āĻ§ā§° āĻŽāĻžāĻā§° āĻ¸āĻŽā§āĻĒā§°ā§āĻ āĻ˛āĻŋāĻāĻžāĨ¤
āĻāĻ¤ā§āĻ¤ā§°: f = R/2
Section B : Short Answer (2 × 5 = 10)
- Q: State two uses of concave mirror.
Ans: (i) Headlights of vehicles (ii) Shaving mirror
āĻĒā§ā§°āĻļā§āĻ¨: āĻ ā§ąāĻ¤āĻ˛ āĻĻā§°ā§āĻĒāĻŖā§° āĻĻā§āĻāĻž āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻ˛āĻŋāĻāĻžāĨ¤
āĻāĻ¤ā§āĻ¤ā§°: (i) āĻāĻžāĻĄāĻŧā§ā§° āĻšā§āĻĄāĻ˛āĻžāĻāĻ (ii) āĻļā§āĻāĻŋāĻ āĻŽāĻŋā§°ā§° - Q: An object is placed between pole and focus of a concave mirror. State the nature of image formed.
Ans: Virtual, erect, enlarged
āĻĒā§ā§°āĻļā§āĻ¨: āĻ ā§ąāĻ¤āĻ˛ āĻĻā§°ā§āĻĒāĻŖā§° āĻĒ’āĻ˛ āĻā§°ā§ āĻĢā§āĻāĻžāĻā§° āĻŽāĻžāĻāĻ¤ āĻŦāĻ¸ā§āĻ¤ā§ ā§°āĻžāĻāĻŋāĻ˛ā§ āĻĒā§ā§°āĻ¤āĻŋāĻŦāĻŋāĻŽā§āĻŦā§° āĻ¸ā§āĻŦāĻāĻžā§ą āĻ˛āĻŋāĻāĻžāĨ¤
āĻāĻ¤ā§āĻ¤ā§°: āĻāĻžā§°ā§āĻā§ā§ąā§āĻ˛, āĻ¸ā§āĻāĻž, āĻĄāĻžāĻā§° - Q: Write one difference between concave and convex mirror.
Ans: Concave mirror converges light; convex mirror diverges light.
āĻĒā§ā§°āĻļā§āĻ¨: āĻ ā§ąāĻ¤āĻ˛ āĻā§°ā§ āĻāĻ¤ā§āĻ¤āĻ˛ āĻĻā§°ā§āĻĒāĻŖā§° āĻāĻāĻž āĻĒāĻžā§°ā§āĻĨāĻā§āĻ¯ āĻ˛āĻŋāĻāĻžāĨ¤
āĻāĻ¤ā§āĻ¤ā§°: āĻ ā§ąāĻ¤āĻ˛ āĻāĻ˛ā§ āĻāĻāĻ¤ā§ā§° āĻā§°ā§; āĻāĻ¤ā§āĻ¤āĻ˛ āĻāĻ˛ā§ āĻāĻāĻŋāĻ¯āĻŧāĻžāĻ¯āĻŧāĨ¤ - Q: What is principal axis of a spherical mirror?
Ans: The straight line passing through the pole and centre of curvature.
āĻĒā§ā§°āĻļā§āĻ¨: āĻā§āĻ˛āĻžāĻāĻžā§° āĻĻā§°ā§āĻĒāĻŖā§° āĻĒā§ā§°āĻ§āĻžāĻ¨ āĻ āĻā§āĻˇ āĻāĻŋ?
āĻāĻ¤ā§āĻ¤ā§°: āĻĒ’āĻ˛ āĻā§°ā§ āĻŦāĻā§ā§°āĻ¤āĻžā§° āĻā§āĻ¨ā§āĻĻā§ā§°ā§° āĻŽāĻžāĻā§āĻĻāĻŋ āĻ¯ā§ā§ąāĻž āĻ¸ā§āĻāĻž ā§°ā§āĻāĻžāĨ¤
Q. Define Magnification of a Mirror
Ans: Magnification of a mirror is the ratio of the height of the image to the height of the object.
m = hi / ho = -
āĻĒā§ā§°āĻļā§āĻ¨: āĻĻā§°ā§āĻĒāĻŖā§° āĻŦāĻĸāĻŧāĻžā§ą āĻ¸āĻāĻā§āĻāĻž āĻĻāĻŋāĻ¯āĻŧāĻžāĨ¤
āĻāĻ¤ā§āĻ¤ā§°: āĻĻā§°ā§āĻĒāĻŖā§° āĻŦāĻĸāĻŧāĻžā§ą āĻšā§āĻā§ āĻĒā§ā§°āĻ¤āĻŋāĻŦāĻŋāĻŽā§āĻŦā§° āĻāĻā§āĻāĻ¤āĻž āĻā§°ā§ āĻŦāĻ¸ā§āĻ¤ā§ā§° āĻāĻā§āĻāĻ¤āĻžā§° āĻ āĻ¨ā§āĻĒāĻžāĻ¤āĨ¤
Section C : Numerical Problems (3 × 3 = 9)
- Q: Find the focal length of a spherical mirror whose radius of curvature is 40 cm. āĻĒā§ā§°āĻļā§āĻ¨: āĻŦāĻā§ā§°āĻ¤āĻžā§° āĻŦā§āĻ¯āĻžāĻ¸āĻžā§°ā§āĻ§ 40 cm āĻšāĻ˛ā§ āĻĢā§āĻāĻžāĻ˛ āĻĻā§ā§°ā§āĻā§āĻ¯ āĻāĻŋāĻŽāĻžāĻ¨ ?
Solution: f = R/2 = 40/2 = 20 cm Ans: 20 cm - Q: Find the magnification if object height is 3 cm and image height is –9 cm. āĻĒā§ā§°āĻļā§āĻ¨: āĻŦāĻ¸ā§āĻ¤ā§ā§° āĻāĻā§āĻāĻ¤āĻž 3 cm āĻā§°ā§ āĻĒā§ā§°āĻ¤āĻŋāĻŦāĻŋāĻŽā§āĻŦā§° āĻāĻā§āĻāĻ¤āĻž –9 cm āĻšāĻ˛ā§ āĻŦāĻĸāĻŧāĻžā§ą āĻāĻŋāĻŽāĻžāĻ¨ ?
Solution: m = hi / ho = −9/3 = −3 Ans: –3 - Q: Find the distance of an object from a concave mirror of focal length 10 cm so that its real image is four times the size of the object.
Given: f = −10 cm,â âm = −4
m = −v / u
⇒ −4 = −v/u ⇒ v = 4u
Mirror formula: 1/f = 1/v + 1/u ⇒1/−10 = 1/4u + 1/u = 5/4u
Ans: Distance of object = 12.5 cm
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