Magnetic Effects of Electric Current – Numerical Questions


1. Magnetic Field around a Straight Current-Carrying Conductor


A current of 5 A flows through a straight conductor. The magnetic field at a point is 2 × 10âģâĩ T. Find the distance from the conductor.


āĻāϟāĻž āϏ⧋āϜāĻž āϤāĻžā§°āϤ ā§Ģ A āϧāĻžā§°āĻž āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻšā§ˆāϛ⧇āĨ¤ āĻāϟāĻž āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°ā§° āĻŽāĻžāύ 2 × 10âģâĩ TāĨ¤ āϤāĻžā§°āϤ āĻĒā§°āĻž āĻĻā§‚ā§°āĻ¤ā§āĻŦ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Given / āĻĻāĻŋāϝāĻŧāĻž āĻšā§ˆāϛ⧇:
I = 5 A
B = 2 × 10âģâĩ T
μ₀ = 4π × 10âģ⁡ T m Aâģ¹


Formula / āϏ⧂āĻ¤ā§ā§°: B = (μ₀ I) / (2πr)


Calculation / āĻ—āĻŖāύāĻž:
2 × 10âģâĩ = (4π × 10âģ⁡ × 5) / (2πr)


2 × 10âģâĩ = (10 × 10âģ⁡) / r


r = 0.05 m


Ans / āωāĻ¤ā§āϤ⧰: Distance from conductor = 0.05 m = 5 cm


2. Force on a Current-Carrying Conductor


A conductor carrying 3 A current is placed in a magnetic field of 0.4 T. Length of the conductor is 0.5 m. Find the force. ā§Š A āϧāĻžā§°āĻž āĻŦāĻšāύ āϕ⧰āĻž āĻāϟāĻž āϤāĻžā§° 0.4 T āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°āϤ ā§°āĻ–āĻž āĻšā§ˆāϛ⧇āĨ¤ āϤāĻžā§°ā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ 0.5 māĨ¤ āĻŦāϞ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Given / āĻĻāĻŋāϝāĻŧāĻž āĻšā§ˆāϛ⧇: B = 0.4 T, I = 3 A, L = 0.5 m


Formula / āϏ⧂āĻ¤ā§ā§°: F = BIL


Calculation / āĻ—āĻŖāύāĻž:
F = 0.4 × 3 × 0.5
F = 0.6 N


Ans / āωāĻ¤ā§āϤ⧰: Force = 0.6 N


3. Electromagnet / Solenoid – Ampere Turns


A solenoid has 500 turns and carries a current of 2 A. Find total ampere-turns. āĻāϟāĻž āĻ›āϞ⧇āύāχāĻĄāϤ ā§Ģā§Ļā§ĻāϟāĻž āĻĒāĻžāĻ• āφāϛ⧇ āφ⧰⧁ ⧍ A āϧāĻžā§°āĻž āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āĻšā§ˆāϛ⧇āĨ¤ āĻāĻŽā§āĻĒāĻŋāϝāĻŧāĻžā§°-āĻĒāĻžāĻ• āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Given / āĻĻāĻŋāϝāĻŧāĻž āĻšā§ˆāϛ⧇: N = 500, I = 2 A


Formula / āϏ⧂āĻ¤ā§ā§°: Ampere-turns = N × I


Calculation / āĻ—āĻŖāύāĻž: Ampere-turns = 500 × 2 = 1000


Ans / āωāĻ¤ā§āϤ⧰: Ampere-turns = 1000


4. Electric Motor – Power Relation


A motor works at 12 V and draws a current of 2 A. Find power. āĻāϟāĻž āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āĻŽā§‹āĻŸā§°ā§‡ 12 V āĻŦāĻŋāĻ­ā§ąāϤ 2 A āϧāĻžā§°āĻž āϞāϝāĻŧāĨ¤ āĻ•ā§āώāĻŽāϤāĻž āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Given / āĻĻāĻŋāϝāĻŧāĻž āĻšā§ˆāϛ⧇: V = 12 V, I = 2 A


Formula / āϏ⧂āĻ¤ā§ā§°: P = VI


Calculation / āĻ—āĻŖāύāĻž: P = 12 × 2 = 24 W


Ans / āωāĻ¤ā§āϤ⧰: Power = 24 W


5. Force Direction – Fleming’s Left Hand Rule


A conductor carrying 4 A current is placed perpendicular to a magnetic field of 0.2 T. Length of conductor is 0.25 m. Find the force. ā§Ē A āϧāĻžā§°āĻž āĻŦāĻšāύ āϕ⧰āĻž āĻāϟāĻž āϤāĻžā§° 0.2 T āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°ā§° āϏ⧈āϤ⧇ āϞāĻŽā§āĻŦāĻ­āĻžā§ąā§‡ ā§°āĻ–āĻž āĻšā§ˆāϛ⧇āĨ¤ āϤāĻžā§°ā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ 0.25 māĨ¤ āĻŦāϞ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Given / āĻĻāĻŋāϝāĻŧāĻž āĻšā§ˆāϛ⧇: B = 0.2 T, I = 4 A, L = 0.25 m


Formula / āϏ⧂āĻ¤ā§ā§°: F = BIL


Calculation / āĻ—āĻŖāύāĻž:
F = 0.2 × 4 × 0.25
F = 0.2 N


Ans / āωāĻ¤ā§āϤ⧰: Force = 0.2 N (āĻĻāĻŋāĻļ Fleming’s Left Hand Rule āĻ…āύ⧁āϏāĻžā§°ā§‡ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻž āĻšāϝāĻŧ)


Exam Tips (Magnetic Effects Chapter)


• Always write formula first
• Use SI units only
• Remember: F = BIL, B = μ₀I / 2πr
• Fleming’s Left Hand Rule → Direction of force
• Score = Full marks


6. Magnetic Field in a Circular Coil (Concept Question)


If the current in a circular coil is doubled, what happens to the magnetic field?


āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤāĻžāĻ•āĻžā§° āĻ•āχāϞāϤ āĻĒā§ā§°āĻŦāĻžāĻšāĻŋāϤ āϧāĻžā§°āĻž āĻĻ⧁āϗ⧁āĻŖ āϕ⧰āĻŋāϞ⧇ āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°ā§° āĻ•āĻŋ āĻšāϝāĻŧ?


Concept / āϧāĻžā§°āĻŖāĻž: Magnetic field is directly proportional to current. āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° āϧāĻžā§°āĻžā§° āϏ⧈āϤ⧇ āϏ⧋āϜāĻžāϏ⧁āϜāĻŋ āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤāĻŋāĻ•āĨ¤


Formula / āϏ⧂āĻ¤ā§ā§°: B ∝ I


Conclusion / āϏāĻŋāĻĻā§āϧāĻžāĻ¨ā§āϤ: If current doubles, magnetic field also doubles.āϧāĻžā§°āĻž āĻĻ⧁āϗ⧁āĻŖ āĻš’āϞ⧇ āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°ā§‹ āĻĻ⧁āϗ⧁āĻŖ āĻšāϝāĻŧāĨ¤


7. Magnetic Field Produced by a Coil


A coil produces a magnetic field proportional to current. If 2 A current produces 0.02 T, find the magnetic field when current is 5 A.


āĻāϟāĻž āĻ•āχāϞ⧇ āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āϕ⧰āĻž āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§° āϧāĻžā§°āĻžā§° āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤāĻŋāĻ•āĨ¤ 2 A āϧāĻžā§°āĻžāϤ 0.02 T āĻ•ā§āώ⧇āĻ¤ā§ā§° āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āĻšāϝāĻŧāĨ¤ 5 A āϧāĻžā§°āĻžāϤ āĻ•ā§āώ⧇āĻ¤ā§ā§° āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Formula / āϏ⧂āĻ¤ā§ā§°: B₁ / B₂ = I₁ / I₂


Calculation / āĻ—āĻŖāύāĻž:
B₂ = (0.02 × 5) / 2
B₂ = 0.05 T


Ans / āωāĻ¤ā§āϤ⧰: Magnetic field = 0.05 T


8. Force on a Current Carrying Conductor


A conductor carrying 3 A current is placed in a magnetic field of 0.4 T. Length of conductor = 0.5 m. Find force.


3 A āϧāĻžā§°āĻž āĻŦāĻšāύ āϕ⧰āĻž āĻāϟāĻž āϤāĻžā§° 0.4 T āϚ⧁āĻŽā§āĻŦāϕ⧀āϝāĻŧ āĻ•ā§āώ⧇āĻ¤ā§ā§°āϤ ā§°āĻ–āĻž āĻšā§ˆāϛ⧇āĨ¤ āϤāĻžā§°ā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ = 0.5 māĨ¤ āĻŦāϞ āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Formula / āϏ⧂āĻ¤ā§ā§°: F = BIL


Calculation / āĻ—āĻŖāύāĻž:
F = 0.4 × 3 × 0.5
F = 0.6 N


Ans / āωāĻ¤ā§āϤ⧰: Force = 0.6 N


9. Electric Motor – Power Relation


A motor works at 12 V and draws 2 A current. Find power. āĻāϟāĻž āĻŽā§‹āĻŸā§°ā§‡ 12 V āĻŦāĻŋāĻ­ā§ąāϤ 2 A āϧāĻžā§°āĻž āϞāϝāĻŧāĨ¤ āĻ•ā§āώāĻŽāϤāĻž āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Formula / āϏ⧂āĻ¤ā§ā§°: P = VI


Calculation / āĻ—āĻŖāύāĻž:
P = 12 × 2
P = 24 W


Ans / āωāĻ¤ā§āϤ⧰: Power = 24 W


10. Domestic Circuit / Motor Question


A motor operates at 12 V and draws 2 A current. Find power. āĻāϟāĻž āĻŽā§‹āĻŸā§°ā§‡ 12 V āϤ 2 A āϧāĻžā§°āĻž āϞāϝāĻŧāĨ¤ āĻ•ā§āώāĻŽāϤāĻž āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤


Formula / āϏ⧂āĻ¤ā§ā§°: P = VI


Calculation / āĻ—āĻŖāύāĻž: P = 12 × 2 = 24 W


Ans / āωāĻ¤ā§āϤ⧰: Power = 24 W


Exam Tips (Very Important) / āĻĒā§°ā§€āĻ•ā§āώāĻžā§° āϟāĻŋāĻĒāĻ›


• Always write formula first (Sure marks)
• Remember formulas: F = BIL, B ∝ I, P = VI
• Use Right Hand Thumb Rule for magnetic field direction
• Motor & generator numericals are direct formula based
• Write units clearly (N, T, W)