WORK (āĻāĻžā§°ā§āϝ)
What is Work ? / āĻāĻžā§°ā§āϝ āĻāĻŋ ?
Work is done when : āĻāĻžā§°ā§āϝ āϤā§āϤāĻŋāϝāĻŧāĻžāĻ āĻšāϝāĻŧ āϝā§āϤāĻŋāϝāĻŧāĻž:
- A force is applied on an object : āĻā§āύ⧠āĻŦāϏā§āϤā§ā§° āĻāĻĒā§°āϤ āĻŦāϞ āĻĒā§ā§°āϝāĻŧā§āĻ āĻā§°āĻž āĻšāϝāĻŧ
- The object moves in the direction of the force : āĻŦāϏā§āϤā§āĻā§ āĻŦāϞ⧰ āĻĻāĻŋāĻļāϤ āϏ⧰ā§
Formula of Work / āĻāĻžā§°ā§āϝ⧰ āϏā§āϤā§ā§°
Work (W) = Force (F) × Displacement (s) : āĻāĻžā§°ā§āϝ (W) = āĻŦāϞ (F) × āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ (s)
Unit / āĻāĻāĻ: Joule (J)
1 Joule = 1 Newton × 1 meter : ā§§ āĻā§āϞ = ā§§ āύāĻŋāĻāĻāύ × ā§§ āĻŽāĻŋāĻāĻžā§°
Types of Work / āĻāĻžā§°ā§āϝ⧰ āĻĒā§ā§°āĻāĻžā§°
Positive Work / āϧāύāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝ
- Force and displacement are in the SAME direction : āĻŦāϞ āĻā§°ā§ āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āĻāĻā§ āĻĻāĻŋāĻļāϤ āĻĨāĻžāĻā§
- Example: Pushing a box : āĻāĻĻāĻžāĻšā§°āĻŖ: āĻŦāĻžāĻāĻ āĻ ā§āϞāĻž
Negative Work / āĻāĻŖāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝ
- Force and displacement are in OPPOSITE directions : āĻŦāϞ āĻā§°ā§ āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āĻŦāĻŋāĻĒā§°ā§āϤ āĻĻāĻŋāĻļāϤ āĻĨāĻžāĻā§
- Example: Friction : āĻāĻĻāĻžāĻšā§°āĻŖ: āĻā§°ā§āώāĻŖ āĻŦāϞ
Zero Work / āĻļā§āύā§āϝ āĻāĻžā§°ā§āϝ
- No displacement occurs : āĻā§āύ⧠āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āύāĻžāĻĨāĻžāĻā§
- Example: Holding a bag : āĻāĻĻāĻžāĻšā§°āĻŖ: āĻĨāϞā§ā§ąāĻž āϧ⧰āĻž (āĻŦā§āĻ āϧ⧰āĻŋ āĻĨāĻāĻž)
Important Points / āĻā§ā§°ā§āϤā§āĻŦāĻĒā§āϰā§āĻŖ āĻāĻĨāĻž
- Work is only done when displacement happens : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āύāĻš’āϞ⧠āĻāĻžā§°ā§āϝ āύāĻšāϝāĻŧ
- No movement → No work : āĻāϤāĻŋ āύāĻžāĻ → āĻāĻžā§°ā§āϝ āύāĻžāĻ
- Direction of force matters : āĻŦāϞ⧰ āĻĻāĻŋāĻļ āĻā§ā§°ā§āϤā§āĻŦāĻĒā§āϰā§āĻŖ
Remember / āĻŽāύāϤ ā§°āĻžāĻāĻŋāĻŦ
1 Joule = Work done when 1 N force moves an object 1 meter
ā§§ āĻā§āϞ = ā§§ āύāĻŋāĻāĻāύ āĻŦāϞ⧰⧠āĻŦāϏā§āϤ⧠⧧ āĻŽāĻŋāĻāĻžā§° āϏ⧰āĻžāϞ⧠āĻā§°āĻž āĻāĻžā§°ā§āϝ
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MCQs
Q1. What is work ? / āĻāĻžā§°ā§āϝ āĻāĻŋ ?
A) Only force B) Only movement C) Force × displacement D) Energy
Ans: C
Explanation: Work is defined as force multiplied by displacement. āĻāĻžā§°ā§āϝ = āĻŦāϞ × āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖāĨ¤
Q2. SI unit of work ? / āĻāĻžā§°ā§āϝ⧰ āĻāĻāĻ āĻāĻŋ ?
A) Watt B) Joule C) Newton D) Meter
Ans: B
Explanation: Work is measured in Joule (J). : āĻāĻžā§°ā§āϝ⧰ āĻāĻāĻ āĻšā§āĻā§ āĻā§āϞ (J)āĨ¤
Q3. 1 Joule = ? / ā§§ āĻā§āϞ = ?
A) 1 N × 1 m B) 1 kg × 1 m C) 1 N × 1 s D) 1 m/s
Ans: A
Explanation: 1 Joule = 1 Newton × 1 meter. : ā§§ āĻā§āϞ = ā§§ āύāĻŋāĻāĻāύ × ā§§ āĻŽāĻŋāĻāĻžā§°āĨ¤
Q4. When is work done ? / āĻā§āϤāĻŋāϝāĻŧāĻž āĻāĻžā§°ā§āϝ āĻšāϝāĻŧ ?
A) Only force B) Only displacement C) Both force & displacement D) None
Ans: C
Explanation: Work is done only when force and displacement both exist. : āĻŦāϞ āĻā§°ā§ āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āĻĻā§āϝāĻŧā§ āĻĨāĻžāĻāĻŋāϞā§āĻšā§ āĻāĻžā§°ā§āϝ āĻšāϝāĻŧāĨ¤
Q5. Positive work occurs when ? / āϧāύāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝ āĻā§āϤāĻŋāϝāĻŧāĻž āĻšāϝāĻŧ ?
A) Opposite direction B) Same direction C) No movement D) Zero force
Ans: B
Explanation: Same direction → positive work. : āĻāĻā§ āĻĻāĻŋāĻļ → āϧāύāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝāĨ¤
Q6. Negative work example / āĻāĻŖāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝ āĻāĻĻāĻžāĻšā§°āĻŖ
A) Lifting B) Friction C) Pushing D) Walking
Ans: B
Explanation: Friction acts opposite to motion → negative work. : āĻā§°ā§āώāĻŖ āĻŦāϞ āĻŦāĻŋāĻĒā§°ā§āϤ āĻĻāĻŋāĻļāϤ āĻĨāĻžāĻā§ → āĻāĻŖāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝāĨ¤
Q7. Zero work example / āĻļā§āύā§āϝ āĻāĻžā§°ā§āϝ āĻāĻĻāĻžāĻšā§°āĻŖ
A) Running B) Holding bag C) Lifting D) Throwing
Ans: B
Explanation: No displacement → zero work. : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āύāĻžāĻ → āĻļā§āύā§āϝ āĻāĻžā§°ā§āϝāĨ¤
Q8. If displacement = 0, work = ?
A) Max B) Zero C) Negative D) Positive
Ans: B
Explanation: Without movement, work = 0. : āĻāϤāĻŋ āύāĻžāĻĨāĻžāĻāĻŋāϞ⧠āĻāĻžā§°ā§āϝ = 0āĨ¤
Q9. Work depends on / āĻāĻžā§°ā§āϝ āύāĻŋā§°ā§āĻā§° āĻā§°ā§
A) Force B) Displacement C) Both D) Time
Ans: C
Explanation: Work depends on both force and displacement. : āĻāĻžā§°ā§āϝ āĻŦāϞ āĻā§°ā§ āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āĻĻā§āϝāĻŧā§ā§° āĻāĻĒā§°āϤ āύāĻŋā§°ā§āĻā§° āĻā§°ā§āĨ¤
Q10. Unit of force ? / āĻŦāϞ⧰ āĻāĻāĻ ?
A) Joule B) Watt C) Newton D) Meter
Ans: C
Explanation: Force is measured in Newton. āĻŦāϞ⧰ āĻāĻāĻ āύāĻŋāĻāĻāύāĨ¤
Q11. Work when angle = 90°?
A) Max B) Zero C) Negative D) Positive
Ans: B
Explanation: Force â displacement → no work done. ⧝ā§Ļ° āĻšāϞ⧠āĻāĻžā§°ā§āϝ āύāĻžāĻāĨ¤
Q12. Lifting a load upward / āĻāĻĒā§°āϞ⧠āϤā§āϞāĻŋ āĻĻāĻŋāϝāĻŧāĻž
A) Negative B) Positive C) Zero D) None
Ans: B
Explanation: Force and movement same direction → positive. : āĻāĻā§ āĻĻāĻŋāĻļ → āϧāύāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝāĨ¤
Q13. Work by gravity on falling object
A) Positive B) Negative C) Zero D) None
Ans: A
Explanation: Gravity and motion both downward → positive work. : āĻŽāĻšāĻžāĻāϰā§āώāĻŖ āĻā§°ā§ āĻāϤāĻŋ āĻāĻā§ āĻĻāĻŋāĻļāϤ → āϧāύāĻžāϤā§āĻŽāĻāĨ¤
Q14. Friction always does
A) Positive B) Negative C) Zero D) Both
Ans: B
Explanation: Friction opposes motion → negative work. āĻā§°ā§āώāĻŖ āĻŦāϞ āĻŦāĻŋāĻĒā§°ā§āϤ → āĻāĻŖāĻžāϤā§āĻŽāĻāĨ¤
Q15. Formula of work / āϏā§āϤā§ā§°
A) F/s B) F+s C) F×s D) s/F
Ans: C
Explanation: Work = Force × displacement. : āĻāĻžā§°ā§āϝ = āĻŦāϞ × āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖāĨ¤
Numerical Problems
Q1. F = 10 N, s = 5 m, W = ?
Soln: W = F × s = 10 × 5 = 50 J
Explanation: Work is force multiplied by displacement. : āĻāĻžā§°ā§āϝ = āĻŦāϞ × āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ = ā§Ģā§Ļ āĻā§āϞ
Q2. F = 20 N, s = 2 m, W = ?
Soln: W = 20 × 2 = 40 J
Explanation: Simple multiplication of force and distance. : āĻŦāϞ āĻā§°ā§ āĻĻā§ā§°āϤā§āĻŦā§° āĻā§āĻŖāĻĢāϞāĨ¤
Q3. F = 0 N, s = 10 m, W = ?
Soln: W = 0 × 10 = 0 J
Explanation No force → no work. : āĻŦāϞ āύāĻžāĻ → āĻāĻžā§°ā§āϝ āύāĻžāĻāĨ¤
Q4. F = 5 N, s = 0 m, W = ?
Soln: W = 5 × 0 = 0 J
Explanation: No displacement → no work. : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āύāĻžāĻ → āĻāĻžā§°ā§āϝ āύāĻžāĻāĨ¤
Q5. F = 15 N, s = 3 m, W = ?
Soln: W = 15 × 3 = 45 J
Explanation: Multiply force and displacement. : āĻŦāϞ × āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ = ā§Ēā§Ģ āĻā§āϞ
Q6. F = 25 N, s = 4 m, W = ?
Soln: W = 25 × 4 = 100 J
Explanation: Direct formula application. āϏā§āϤā§ā§° āĻĒā§ā§°āϝāĻŧā§āĻāĨ¤
Q7. F = 30 N, s = 10 m, W = ?
Soln: W = 30 × 10 = 300 J
Explanation: Large displacement gives more work. : āĻŦā§āĻāĻŋ āĻĻā§ā§°āϤā§āĻŦ → āĻŦā§āĻāĻŋ āĻāĻžā§°ā§āϝāĨ¤
Q8. F = 50 N, s = 2 m, W = ?
Soln: W = 50 × 2 = 100 J
Explanation: Force high → work increases. : āĻŦāϞ āĻŦā§āĻāĻŋ → āĻāĻžā§°ā§āϝ āĻŦā§āĻāĻŋāĨ¤
Q9. F = 10 N, s = 5 m (opposite direction), W = ?
Soln:
W = - (10 × 5) = -50 J
Explanation: Opposite direction → negative work. : āĻŦāĻŋāĻĒā§°ā§āϤ āĻĻāĻŋāĻļ → āĻāĻŖāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝāĨ¤
Q10. F = 100 N, s = 0 m, W = ?
Soln:
W = 100 × 0 = 0 J
Explanation: No movement → no work. : āĻāϤāĻŋ āύāĻžāĻ → āĻāĻžā§°ā§āϝ āύāĻžāĻāĨ¤
Quick Trick (Exam Ready)
- W = F × s
- If F = 0 or s = 0 → Work = 0 : F = 0 āĻŦāĻž s = 0 → āĻāĻžā§°ā§āϝ = 0
- Opposite direction → Negative : āĻŦāĻŋāĻĒā§°ā§āϤ āĻĻāĻŋāĻļ → āĻāĻŖāĻžāϤā§āĻŽāĻ
Assertion–Reason
Q1. A: Work is zero if displacement is zero, R: Work depends on displacement
Ans: Both true, R explains A
Explanation: Without displacement, no work. : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āĻŖ āύāĻžāĻĨāĻžāĻāĻŋāϞ⧠āĻāĻžā§°ā§āϝ āύāĻšāϝāĻŧāĨ¤
Q2. A: Friction does negative work, R: It acts opposite
Ans: Both true
Explanation: Opposite force → negative work. : āĻŦāĻŋāĻĒā§°ā§āϤ āĻŦāϞ → āĻāĻŖāĻžāϤā§āĻŽāĻ āĻāĻžā§°ā§āϝāĨ¤
Q3. A: Holding bag does work, R: Force is applied
Ans: A false, R true
Explanation: No movement → no work. āĻāϤāĻŋ āύāĻžāĻ → āĻāĻžā§°ā§āϝ āύāĻžāĻāĨ¤
Q4. A: Work depends on force , R: W = F × s
Ans: Both true