Mechanical Advantage (MA) / āϝāĻžāύā§āϤā§ā§°āĻŋāĻ āϏā§āĻŦāĻŋāϧāĻž
Definition / āϏāĻāĻā§āĻāĻž
Mechanical Advantage (MA) shows how much a machine multiplies our effort. āϝāĻžāύā§āϤā§ā§°āĻŋāĻ āϏā§āĻŦāĻŋāϧāĻž (MA) āĻšā§āĻā§ āĻāĻāĻž āϝāύā§āϤā§ā§°ā§ āĻāĻŽāĻžā§° āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŋāĻŽāĻžāύāĻā§°āĻžāĻā§ āĻŦā§āĻĻā§āϧāĻŋ āĻā§°ā§ āϤāĻžāĻ āĻŦā§āĻāĻžāϝāĻŧāĨ¤
Formula / āϏā§āϤā§ā§° :- MA = Load / Effort : MA = āĻāĻžā§° / āĻĒā§ā§°āϝāĻŧāĻžāϏ
Meaning of MA Values / MAā§° āĻ ā§°ā§āĻĨ
MA > 1 : - Machine reduces effort (very useful) : āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŽ āϞāĻžāĻā§ (āĻŦā§āĻāĻŋ āĻāĻžā§° āϤā§āϞāĻŋāĻŦ āĻĒāĻžā§°ā§)
MA = 1 : - No gain, effort = load : āĻā§āύ⧠āϞāĻžāĻ āύāĻžāĻ (āĻĒā§ā§°āϝāĻŧāĻžāϏ = āĻāĻžā§°)
MA < 1 : - Effort increases (not useful) : āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻŦāĻžāĻĸāĻŧā§ (āĻāĻĒāĻāĻžā§°ā§ āύāĻšāϝāĻŧ)
Efficiency of Machine / āϝāύā§āϤā§ā§°ā§° āĻĻāĻā§āώāϤāĻž
Efficiency = (Output Work / Input Work) × 100 : āĻĻāĻā§āώāϤāĻž = (āĻāĻāĻāĻĒā§āĻ āĻāĻžā§°ā§āϝ / āĻāύāĻĒā§āĻ āĻāĻžā§°ā§āϝ) × 100
Important Points / āĻā§ā§°ā§āϤā§āĻŦāĻĒā§āϰā§āĻŖ āĻāĻĨāĻž
- Efficiency is always less than 100% : āĻĻāĻā§āώāϤāĻž āϏāĻĻāĻžāϝāĻŧ ā§§ā§Ļā§Ļ%āϤāĻā§ āĻāĻŽ
- Due to friction and heat loss : āĻā§°ā§āώāĻŖ āĻā§°ā§ āϤāĻžāĻĒā§° āĻŦāĻžāĻŦā§ āĻļāĻā§āϤāĻŋ āύāώā§āĻ āĻšāϝāĻŧ
- No machine is 100% efficient (real life) : āĻŦāĻžāϏā§āĻ¤ā§ą āĻā§ā§ąāύāϤ āĻā§āύ⧠āϝāύā§āϤā§ā§° ā§§ā§Ļā§Ļ% āĻĻāĻā§āώ āύāĻšāϝāĻŧ
Example (Must Remember)
Load = 800 N, Effort = 200 N
Soln
MA = 800 / 200 = 4
Explanation: Machine multiplies effort 4 times : āϝāύā§āϤā§ā§°ā§ āĻĒā§ā§°āϝāĻŧāĻžāϏ ā§Ē āĻā§āĻŖ āĻŦā§āĻĻā§āϧāĻŋ āĻā§°ā§
Tricks
MA = Load ÷ Effort : MA = āĻāĻžā§° ÷ āĻĒā§ā§°āϝāĻŧāĻžāϏ
More MA → less effort : MA āĻŦā§āĻāĻŋ → āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŽ
Efficiency < 100% always : āĻĻāĻā§āώāϤāĻž āϏāĻĻāĻžāϝāĻŧ < ā§§ā§Ļā§Ļ%
Ultra Short Revision : MA tells how much effort is reduced by a machine. : MAāϝāĻŧā§ āĻĻā§āĻā§ā§ąāĻžāϝāĻŧ āϝāύā§āϤā§ā§°ā§ āĻāĻŋāĻŽāĻžāύ āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŽ āĻā§°ā§āĨ¤
Example (Very Important)
Q. Input Effort = 200 N, Load = 800 N, Find MA
Soln: MA = Load / Effort = 800 / 200 = 4
Explanation: Machine multiplies effort 4 times. : āϝāύā§āϤā§ā§°ā§ āĻĒā§ā§°āϝāĻŧāĻžāϏ ā§Ē āĻā§āĻŖ āĻŦā§āĻĻā§āϧāĻŋ āĻā§°ā§āĨ¤
Practice Numericals
Q1. Load = 100 N, Effort = 50 N, MA = ?
MA = 100/50 = 2
Explanation: Effort is reduced. : āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŽ āĻšā§āĻā§āĨ¤
Q2. Load = 60 N, Effort = 60 N, MA = ?
MA = 1
Explanation: No change in effort. āĻĒā§ā§°āϝāĻŧāĻžāϏ āϏāϞāύāĻŋ āύāĻšāϝāĻŧāĨ¤
Q3. Load = 40 N, Effort = 80 N, MA = ?
MA = 0.5
Explanation: Effort increases → not useful. āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻŦāĻžāĻĸāĻŧā§ → āĻāĻĒāĻāĻžā§°ā§ āύāĻšāϝāĻŧāĨ¤
Q4. Input work = 200 J, Output work = 150 J, Efficiency = ?
Efficiency = (150/200) ×100 = 75%
Explanation: Some energy lost. āĻāĻŋāĻā§ āĻļāĻā§āϤāĻŋ āύāώā§āĻ āĻšā§āĻā§āĨ¤
Q5. Input work = 500 J, Output work = 400 J
Efficiency = 80%
Final Quick Revision
MA = Load / Effort : MA = āĻāĻžā§° / āĻĒā§ā§°āϝāĻŧāĻžāϏ
MA > 1 → good machine : MA > 1 → āĻāĻžāϞ āϝāύā§āϤā§ā§°
Efficiency < 100% always : āĻĻāĻā§āώāϤāĻž āϏāĻĻāĻžāϝāĻŧ < ā§§ā§Ļā§Ļ%
Hard Numericals (Exam Level)
Q1. Load = 1200 N, Effort = 300 N. Find MA and type of machine
Soln: MA = Load / Effort = 1200 / 300 = 4
Ans: MA = 4 (MA > 1)
Explanation: Machine reduces effort (very useful). : āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŽ āϞāĻžāĻā§, āĻāĻžāϞ āϝāύā§āϤā§ā§°āĨ¤
Q2. Input Work = 500 J, Output Work = 350 J, Find Efficiency
Soln: Efficiency = (350 / 500) × 100 = 70%
Explanation: 30% energy lost due to friction. : ā§Šā§Ļ% āĻļāĻā§āϤāĻŋ āĻā§°ā§āώāĻŖāϤ āύāώā§āĻ āĻšā§āĻā§āĨ¤
Q3. MA = 5, Effort = 100 N, Find Load
Soln:
MA = Load / Effort
Load = MA × Effort = 5 × 100 = 500 N
Explanation: Machine multiplies force 5 times. : āϝāύā§āϤā§ā§°ā§ āĻŦāϞ ā§Ģ āĻā§āĻŖ āĻŦā§āĻĻā§āϧāĻŋ āĻā§°ā§āĨ¤
Q4. Load = 600 N, MA = 3, Find Effort
Soln: Effort = Load / MA = 600 / 3 = 200 N
Explanation: Less effort needed due to machine. : āϝāύā§āϤā§ā§°ā§ āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāĻŽ āĻā§°ā§āĨ¤
Q5. Input Work = 800 J, Efficiency = 80%, Find Output Work
Soln: Output = (80/100) × 800 = 640 J
Explanation: 20% energy lost. ⧍ā§Ļ% āĻļāĻā§āϤāĻŋ āύāώā§āĻ āĻšā§āĻā§āĨ¤
Q6. Load = 200 N, Effort = 400 N, Find MA and comment
Soln: MA = 200 / 400 = 0.5
Explanation: MA < 1 → not useful machine. : MA < 1 → āĻāĻĒāĻāĻžā§°ā§ āύāĻšāϝāĻŧāĨ¤
Q7. Input Work = 1000 J, Output Work = 900 J, Find Efficiency
Soln: Efficiency = (900/1000) ×100 = 90%
Explanation: Very efficient machine. : āĻŦā§āĻāĻŋ āĻĻāĻā§āώ āϝāύā§āϤā§ā§°āĨ¤
Q8. MA = 2, Load = 400 N , Find Effort
Soln: Effort = 400 / 2 = 200 N
Explanation: Effort reduced by half. : āĻĒā§ā§°āϝāĻŧāĻžāϏ āĻāϧāĻž āĻš’āϞāĨ¤
Q9. Effort = 50 N, MA = 4, Find Load
Soln: Load = 4 × 50 = 200 N
Explanation: Machine multiplies effort 4 times. : āĻĒā§ā§°āϝāĻŧāĻžāϏ ā§Ē āĻā§āĻŖ āĻŦā§āĻĻā§āϧāĻŋ āĻā§°ā§āĨ¤
Q10. Input Work = 600 J, Output Work = 300 J, Find Efficiency
Soln: Efficiency = (300/600) ×100 = 50%
Explanation: Half energy lost. : āĻāϧāĻž āĻļāĻā§āϤāĻŋ āύāώā§āĻ āĻšā§āĻā§āĨ¤
Exam Tips (Very Important)
MA = Load / Effort : MA = āĻāĻžā§° / āĻĒā§ā§°āϝāĻŧāĻžāϏ
Efficiency = Output/Input ×100 : āĻĻāĻā§āώāϤāĻž = āĻāĻāĻāĻĒā§āĻ/āĻāύāĻĒā§āĻ ×100
Always check MA > 1 or < 1 : āϏāĻĻāĻžāϝāĻŧ MA āĻāĻžāĻāĻ