Distance (āĻĻā§ā§°āϤā§āĻŦ) & Displacement (āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰)
Distance (āĻĻā§ā§°āϤā§āĻŦ)
What is Distance ?
Distance is the total length of the path travelled. āĻĻā§ā§°āϤā§āĻŦ āĻŽāĻžāύ⧠āĻšā§āĻā§ āĻāϞāĻžā§° āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻĒāĻĨā§° āĻĻā§ā§°ā§āĻā§āϝāĨ¤
Key Points (āĻŽā§āϞ āĻŦāĻŋāώāϝāĻŧ)
- It is a scalar quantity : āĻ āĻāĻāĻž āϏā§āĻā§āϞāĻžā§° ā§°āĻžāĻļāĻŋ
- Has only magnitude (no direction) : āĻā§ā§ąāϞ āĻŽāĻžāύ āĻĨāĻžāĻā§ (āĻĻāĻŋāĻļ āύāĻžāĻ)
- Always positive : āϏāĻĻāĻžāϝāĻŧ āϧāύāĻžāϤā§āĻŽāĻ
Remember: Distance tells HOW MUCH you moved : Distance āĻŦā§āĻāĻžāϝāĻŧ āĻāĻĒā§āύāĻŋ āĻāĻŋāĻŽāĻžāύ āĻĻā§ā§° āĻ’āϞ
Displacement (āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰)
What is Displacement ?
Displacement is the shortest distance from initial to final position with direction. āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ āĻŽāĻžāύ⧠āĻā§°āĻŽā§āĻāĻŖāĻŋ āϏā§āĻĨāĻžāύ⧰ āĻĒā§°āĻž āĻļā§āώ āϏā§āĻĨāĻžāύāϞā§āĻā§ āϏ⧰ā§āĻŦāύāĻŋāĻŽā§āύ āĻĻā§ā§°āϤā§āĻŦ (āĻĻāĻŋāĻļāϏāĻš)āĨ¤
Key Points (āĻŽā§āϞ āĻŦāĻŋāώāϝāĻŧ)
- It is a vector quantity. āĻ āĻāĻāĻž āĻā§āĻā§āĻā§° ā§°āĻžāĻļāĻŋ
- Has magnitude + direction. āĻŽāĻžāύ āĻā§°ā§ āĻĻāĻŋāĻļ āĻĻā§āϝāĻŧā§āĻāĻž āĻĨāĻžāĻā§
- Can be positive, negative, or zero. āϧāύāĻžāϤā§āĻŽāĻ, āĻāĻŖāĻžāϤā§āĻŽāĻ āĻŦāĻž āĻļā§āύā§āϝ āĻš’āĻŦ āĻĒāĻžā§°ā§
Remember: Displacement tells WHERE you ended up. (Displacement āĻŦā§āĻāĻžāϝāĻŧ āĻāĻĒā§āύāĻŋ āĻ’āϤ āĻā§ āĻļā§āώ āĻā§°āĻŋāϞā§)
Formula / Concept
For displacement in 2D (Pythagoras Theorem): D = √x2 + Y2
Used when motion is in two directions (like East & North) : āĻĻā§āĻāĻž āĻĻāĻŋāĻļāϤ āĻāϤāĻŋ āĻĨāĻžāĻāĻŋāϞ⧠āĻāĻ āϏā§āϤā§āϰ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻšā§
Practice Question
Q: A student walks 3 m East and then 4 m North. Find: i. Distance, ii. Displacement
Soln (Ans)
Distance = 3 + 4 = 7 m : āĻĻā§ā§°āϤā§āĻŦ = ā§ āĻŽāĻŋ
Displacement = √(3² + 4²) = 5 m (North-East direction) : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ = ā§Ģ āĻŽāĻŋ (āĻāϤā§āϤ⧰-āĻĒā§āĻŦ āĻĻāĻŋāĻļāϤ)
Tip
- Distance = Total path : āĻĻā§ā§°āϤā§āĻŦ = āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻĒāĻĨ
- Displacement = Shortest path + Direction : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ = āϏ⧰ā§āĻŦāύāĻŋāĻŽā§āύ āĻĒāĻĨ + āĻĻāĻŋāĻļ
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Distance & Displacement – MCQs
1. What is distance ?
A. Shortest path B. Total path length C. Direction D. Speed
Ans: B. Total path length
Explanation: Distance is the complete path travelled, not the shortest path. āĻĻā§ā§°āϤā§āĻŦ āĻšā§āĻā§ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻāϞāĻž āĻĒāĻĨ, āϏ⧰ā§āĻŦāύāĻŋāĻŽā§āύ āĻĒāĻĨ āύāĻšāϝāĻŧāĨ¤
2. What is displacement ?
A. Total path B. Speed C. Shortest path with direction D. Time
Ans: C. Shortest path with direction
Explanation:Displacement is the shortest distance between start and end with direction. āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ āĻšā§āĻā§ āĻā§°āĻŽā§āĻāĻŖāĻŋ āĻā§°ā§ āĻļā§āώ āϏā§āĻĨāĻžāύ⧰ āĻŽāĻžāĻā§° āϏ⧰ā§āĻŦāύāĻŋāĻŽā§āύ āĻĻā§ā§°āϤā§āĻŦ (āĻĻāĻŋāĻļāϏāĻš)āĨ¤
3. Distance is a ______ quantity.
A. Vector B. Scalar C. Both D. None
Ans: B. Scalar
Explanation: Distance has only magnitude, no direction → scalar. āĻĻā§ā§°āϤā§āĻŦā§° āĻā§ā§ąāϞ āĻŽāĻžāύ āĻĨāĻžāĻā§, āĻĻāĻŋāĻļ āύāĻžāĻ → āϏā§āĻā§āϞāĻžā§°āĨ¤
4. Displacement is a ______ quantity.
A. Scalar B. Vector C. None D. Both
Ans: B. Vector
Explanation: Displacement has magnitude + direction → vector. āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰āϤ āĻŽāĻžāύ āĻā§°ā§ āĻĻāĻŋāĻļ āĻĻā§āϝāĻŧā§āĻāĻž āĻĨāĻžāĻā§ → āĻā§āĻā§āĻā§°āĨ¤
5. Distance always has ______.
A. Direction B. Magnitude only C. Both D. None
Ans: B. Magnitude only
Explanation: Distance only shows “how much,” not direction. āĻĻā§ā§°āϤā§āĻŦ āĻā§ā§ąāϞ “āĻāĻŋāĻŽāĻžāύ” āĻŦā§āĻāĻžāϝāĻŧ, āĻĻāĻŋāĻļ āύā§āĻĻā§āĻā§ā§ąāĻžāϝāĻŧāĨ¤
6. Displacement has ______.
A. Only magnitude B. Only direction C. Both D. None
Ans: C. Both
Explanation: It shows both amount and direction of movement. āĻ āĻāϤāĻŋā§° āĻĒā§°āĻŋāĻŽāĻžāĻŖ āĻā§°ā§ āĻĻāĻŋāĻļ āĻĻā§āϝāĻŧā§āĻāĻž āĻĻā§āĻā§ā§ąāĻžāϝāĻŧāĨ¤
7. Distance can be ______.
A. Negative B. Zero C. Always positive D. Both
Ans: C. Always positive
Explanation: Distance is never negative because it is length. āĻĻā§ā§°āϤā§āĻŦ āĻā§āϤāĻŋāϝāĻŧāĻžāĻ āĻāĻŖāĻžāϤā§āĻŽāĻ āύāĻšāϝāĻŧ, āĻ āĻĻā§ā§°ā§āĻā§āϝāĨ¤
8. Displacement can be ______.
A. Only positive B. Only negative C. Positive/negative/zero D. None
Ans: C. Positive/negative/zero
Explanation: Depends on direction; can be zero if start = end. āĻĻāĻŋāĻļ āĻ
āύā§āϏ⧰āĻŋ āϧāύāĻžāϤā§āĻŽāĻ/āĻāĻŖāĻžāϤā§āĻŽāĻ/āĻļā§āύā§āϝ āĻš’āĻŦ āĻĒāĻžā§°ā§āĨ¤
9. If a person returns to starting point, displacement is ______.
A. Zero B. Maximum C. Negative D. Positive
Ans: A. Zero
Explanation: Initial and final positions are same → displacement = 0. āĻā§°āĻŽā§āĻāĻŖāĻŋ āĻā§°ā§ āĻļā§āώ āĻāĻā§ → āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ = ā§ĻāĨ¤
10. If path is straight line, distance is ______ displacement.
A. Less than B. Equal to C. Greater than D. Zero
Ans: B. Equal to
Explanation: In straight motion, path = shortest path. āϏā§āĻāĻž āĻāϤāĻŋāϤ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻĒāĻĨ = āϏ⧰ā§āĻŦāύāĻŋāĻŽā§āύ āĻĒāĻĨāĨ¤
11. Unit of distance is ______.
A. kg B. m C. s D. N
Ans: B. m
Explanation: SI unit is meter. SI āĻāĻāĻ āĻŽāĻŋāĻāĻžā§°āĨ¤
12. Unit of displacement is ______.
A. m B. kg C. s D. A
Ans: A. m
Explanation: Same as distance → meter. āĻĻā§ā§°āϤā§āĻŦā§° āĻĻā§°ā§ āĻāĻā§ → āĻŽāĻŋāĻāĻžā§°āĨ¤
13. Distance depends on ______.
A. Direction B. Path C. Time D. Speed
Ans: B. Path
Explanation: Longer path = more distance. āĻĒāĻĨ āĻĻā§āĻāϞ āĻš’āϞ⧠āĻĻā§ā§°āϤā§āĻŦ āĻŦā§āĻāĻŋāĨ¤
14. Displacement depends on ______.
A. Path B. Initial & final position C. Speed D. Time
Ans: B. Initial & final position
Explanation: Only start and end matter. āĻā§ā§ąāϞ āĻā§°āĻŽā§āĻāĻŖāĻŋ āĻā§°ā§ āĻļā§āώ āϏā§āĻĨāĻžāύ āĻā§ā§°ā§āϤā§āĻŦāĻĒā§āϰā§āĻŖāĨ¤
15. Which can be zero ?
A. Distance B. Displacement C. Both D. None
Ans: B. Displacement
Explanation: Distance cannot be zero if movement happens, but displacement can. āĻāϞāĻžāĻāϞ āĻĨāĻžāĻāĻŋāϞ⧠āĻĻā§ā§°āϤā§āĻŦ ā§Ļ āύāĻšāϝāĻŧ, āĻāĻŋāύā§āϤ⧠āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ ā§Ļ āĻš’āĻŦ āĻĒāĻžā§°ā§āĨ¤
Numerical MCQs
16. 5 m east + 5 m west, distance = ?
A. 0 B. 5 m C. 10 m D. 2 m
Ans: C. 10 m
Explanation: Total path = 5 + 5 = 10 m. āĻŽā§āĻ āĻĒāĻĨ = ā§Ģ + ā§Ģ = ā§§ā§Ļ āĻŽāĻŋ
17. Same case, displacement = ?
A. 0 B. 10 m C. 5 m D. 2 m
Ans: A. 0
Explanation: Start = End → displacement = 0. āĻā§°āĻŽā§āĻāĻŖāĻŋ = āĻļā§āώ → āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ = ā§Ļ
18. 3 m east + 4 m north, displacement = ?
A. 7 m B. 5 m C. 6 m D. 8 m
Ans: B. 5 m
Explanation: Use Pythagoras → √(3² + 4²) = 5 m. āĻĒāĻžāĻāĻĨāĻžāĻā§ā§°āĻžāĻ → √(3² + 4²) = ā§Ģ āĻŽāĻŋ
19. Distance in above case = ?
A. 5 m B. 7 m C. 3 m D. 4 m
Ans: B. 7 m
Explanation: Total path = 3 + 4 = 7 m. āĻŽā§āĻ āĻĒāĻĨ = ā§ āĻŽāĻŋ
20. Straight 10 m walk, displacement = ?
A. 0 B. 10 m C. 5 m D. 20 m
Ans: B. 10 m
Explanation: Straight line → displacement = distance. āϏā§āĻāĻž āĻĒāĻĨ → āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ = āĻĻā§ā§°āϤā§āĻŦ
Must Remember : i. Distance = Total path travelled : āĻĻā§ā§°āϤā§āĻŦ = āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻĒāĻĨ, ii. Displacement = Shortest path + direction : āϏā§āĻĨāĻžāύāĻžāύā§āϤ⧰ = āϏ⧰ā§āĻŦāύāĻŋāĻŽā§āύ āĻĒāĻĨ + āĻĻāĻŋāĻļ