Velocity (āĻŦ⧇āĻ—) & Acceleration (āĻ¤ā§āĻŦā§°āĻŖ) : Solved Problem






Q / āĻĒā§ā§°āĻļā§āύ: A scooter moves east at 5 m/s. After 5 seconds, its velocity becomes 15 m/s east. (āĻāĻ–āύ āĻ¸ā§āϕ⧁āϟāĻžā§° 5 m/s āĻĒā§‚āĻŦ āĻĻāĻŋāĻļ⧇ āĻ—āϤāĻŋ āϕ⧰⧇āĨ¤ 5 āϛ⧇āϕ⧇āĻŖā§āĻĄ āĻĒāĻŋāĻ›āϤ āχāϝāĻŧāĻžā§° āĻŦ⧇āĻ— 15 m/s āĻĒā§‚āĻŦ āĻĻāĻŋāĻļ⧇ āĻšāϝāĻŧāĨ¤)




Soln



Given / āĻĻāĻŋāϝāĻŧāĻž āφāϛ⧇

  • Initial Velocity (āĻĒā§ā§°āĻžā§°āĻŽā§āĻ­āĻŋāĻ• āĻŦ⧇āĻ—) = 5 m/s east

  • Final Velocity (āĻ…āĻ¨ā§āϤāĻŋāĻŽ āĻŦ⧇āĻ—) = 15 m/s east

  • Time Taken (āĻ˛ā§‹ā§ąāĻž āϏāĻŽāϝāĻŧ) = 5 s


1st: Find Change in Velocity (āĻŦ⧇āĻ—ā§° āĻĒā§°āĻŋāĻŦā§°ā§āϤāύ āωāϞāĻŋāϝāĻŧāĻžāĻ“āρ)

Change in Velocity = Final Velocity − Initial Velocity


= 15 − 5 = 10 m/s east (10 m/s āĻĒā§‚āĻŦ āĻĻāĻŋāĻļ⧇)


2nd: Calculate Acceleration (āĻ¤ā§āĻŦā§°āĻŖ āĻ—āĻŖāύāĻž āϕ⧰⧋āρ)

Acceleration = Change in Velocity ÷ Time


= 10 ÷ 5 = 2 m/s² east


Ans / āωāĻ¤ā§āϤ⧰: Acceleration = 2 m/s² east (āĻ¤ā§āĻŦā§°āĻŖ = 2 m/s² āĻĒā§‚āĻŦ āĻĻāĻŋāĻļ⧇)

 

Note: i. Velocity tells the motion now. (āĻŦ⧇āϗ⧇ āĻŦā§°ā§āϤāĻŽāĻžāύ⧰ āĻ—āϤāĻŋ āĻŦ⧁āϜāĻžāϝāĻŧāĨ¤)

ii. Acceleration tells how the motion changed. (āĻ¤ā§āĻŦā§°āϪ⧇ āĻ—āϤāĻŋ āϕ⧇āύ⧇āĻ•ā§ˆ āϏāϞāύāĻŋ āĻš'āϞ āϤāĻžāĻ• āĻŦ⧁āϜāĻžāϝāĻŧāĨ¤ )