Solve Problem : Which one among the following is the greatest ? A) √201- √199  B) √101 - √99  C) √301 - √299  D) √401 - √399


Q. Which one among the following is the greatest ? A) √201- √199  B) √101 - √99  C) √301 - √299  D) √401 - √399


Soln


Trick: If the difference (gap) is the same, smaller numbers give a larger value. (Gap same āĻĨāĻžāĻ•āĻŋāϞ⧇, āϝāĻŋāĻŸā§‹ āĻœā§‹ā§°āĻž āϏāĻ‚āĻ–ā§āϝāĻž āϏ⧰⧁, āϏ⧇āχāĻŸā§‹ā§° āĻŽāĻžāύ āĻĄāĻžāϙ⧰āĨ¤)


Smaller n ⇒ smaller denominator ⇒ larger value.


Therefore, Option B is the greatest.


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MCQ


1. a17+b17 is divisible by which of the following ? (ā§§. a17+b17 āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ā§°ā§‡ āĻŦāĻŋāĻ­āĻžāĻœā§āϝ ?)


(a) a + b   (b) a − b   (c) a2 + b2    (d) None


Ans / āωāĻ¤ā§āϤ⧰: (a) a + b


Explanation / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 17 is an odd number. Therefore, a17+b17 is divisible by a+b.


2. a25 + b25 is divisible by which of the following ? (⧍. a25 + b25 āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ā§°ā§‡ āĻŦāĻŋāĻ­āĻžāĻœā§āϝ ?)


(a) a+b   (b) a−b   (c) ab   (d) None


Ans / āωāĻ¤ā§āϤ⧰: (a) a+b


Explanation / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 25 is odd. Hence, a25 + b25 is divisible by a + b.


3. a31 − b31 is divisible by which of the following ? (ā§Š. a31 − b31 āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ā§°ā§‡ āĻŦāĻŋāĻ­āĻžāĻœā§āϝ ?)


(a) a + b   (b) a − b   (c) a2 + b2   (d) None


Ans / āωāĻ¤ā§āϤ⧰: (b) a − b


Explanation / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: For any positive integer n, an - bn is always divisible by a − b.


4. a51 + b51 is divisible by which of the following ? (ā§Ē. a51 + b51 āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ā§°ā§‡ āĻŦāĻŋāĻ­āĻžāĻœā§āϝ ?)


(a) a + b   (b) a − b  (c) a2 - b2   (d) None


Ans / āωāĻ¤ā§āϤ⧰: (a) a + b


Explanation / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 51 is an odd number. So, a51 + b51 is divisible by a + b.


5. a99 − b99 is divisible by which of the following ? (ā§Ģ. a99 − b99 āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ā§°ā§‡ āĻŦāĻŋāĻ­āĻžāĻœā§āϝ ?)


(a) a + b  (b) a − b   (c) ab   (d) None


Ans / āωāĻ¤ā§āϤ⧰: (b) a − b


Explanation / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: an−bn is always divisible by a − b, regardless of whether is odd or even.


Quick Rule / āĻĻā§ā§°ā§āϤ āύāĻŋāϝāĻŧāĻŽ



  • an + bn → Divisible by (a+b) when nn is odd. (āĻŦāĻŋāĻœā§‹āĻĄāĻŧ āϘāĻžāϤ + āϝ⧋āĻ— ⇒ (a+b) ⧰⧇ āĻŦāĻŋāĻ­āĻžāĻœā§āϝāĨ¤)

  • an - bn → Always divisible by (a − b). (āĻŦāĻŋāϝāĻŧā§‹āĻ— āĻĨāĻžāĻ•āĻŋāϞ⧇ āϏāĻĻāĻžāϝāĻŧ (a−b)(a-b)-⧰⧇ āĻŦāĻŋāĻ­āĻžāĻœā§āϝāĨ¤)