What is Pi (Ī€) ? :: āĻĒāĻžāχ (Ī€) āĻ•āĻŋ ? Pi (Ī€) – Smart Notes


What is Pi (π) ? āĻĒāĻžāχ (π) āĻ•āĻŋ ?


Pi (π) is the ratio of a circle's circumference to its diameter.


Formula: π = Circumference / Diameter


āĻĒāĻžāχ (π) āĻšā§ˆāϛ⧇ āĻŦ⧃āĻ¤ā§āϤ⧰ āĻĒā§°āĻŋāϧāĻŋ (Circumference) āφ⧰⧁ āĻŦā§āϝāĻžāϏ (Diameter)-ā§° āĻ…āύ⧁āĻĒāĻžāϤāĨ¤


Value of Pi (π) [(āĻĒāĻžāχ (π)-ā§° āĻŽāĻž] : π ≈ 3.14159


Common Approximationπ ≈ 22/7


Note: 22/7 is only an approximation, not the exact value. (2/7 āĻ•ā§‡ā§ąāϞ āĻāϟāĻž āφāύ⧁āĻŽāĻžāύāĻŋāĻ• āĻŽāĻžāύ, āϏāĻ āĻŋāĻ• āĻŽāĻžāύ āύāĻšā§ŸāĨ¤)


Circumference Formulas (āĻĒā§°āĻŋāϧāĻŋā§° āϏ⧂āĻ¤ā§ā§°)


Using Diameter (d) [āĻŦā§āϝāĻžāϏ (d) āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻŋ] : C=  πd 


Using Radius (r) [āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ (r) āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻŋ] : C = 2πr


Note: If you unwrap the edge of a circle and straighten it, the length will be about 3.14 times its diameter. (āϝāĻĻāĻŋ āĻŦ⧃āĻ¤ā§āϤ⧰ āĻ•āĻžāώ (edge) āϖ⧁āϞāĻŋ āϏ⧋āϜāĻž āϕ⧰āĻž āĻšā§Ÿ, āϤ⧇āĻ¨ā§āϤ⧇ āĻ‡ā§ŸāĻžā§° āĻĻā§ˆā§°ā§āĻ˜ā§āϝ āĻŦā§āϝāĻžāϏ⧰ āĻĒā§ā§°āĻžā§Ÿ 3.14 āϗ⧁āĻŖ āĻš'āĻŦāĨ¤)


Example (āωāĻĻāĻžāĻšā§°āĻŖ)


A circle has a diameter of 10 cm.


A circle's circumference: C = π×10 ≈ 31.4 cm


Ans: 31.4 cm


Trick: Pi = 3.14 (22/7 = Approximate Value of Pi)


Remember:



  • Diameter × π = Circumference (āĻŦā§āϝāĻžāϏ × π = āĻĒā§°āĻŋāϧāĻŋ)

  • Radius × 2 × π = Circumference (āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ × 2 × π = āĻĒā§°āĻŋāϧāĻŋ)


MCQ (Board Exam Pattern) : Pi (π) & Circle MCQs (āĻĒāĻžāχ (π) āφ⧰⧁ āĻŦ⧃āĻ¤ā§āϤ MCQ)


1. What is the approximate value of π ? (π-ā§° āφāύ⧁āĻŽāĻžāύāĻŋāĻ• āĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 2.14 (b) 3.14 (c) 4.14 (d) 22.14


Ans / āωāĻ¤ā§āϤ⧰: (b) 3.14


Explanation: The value of π is approximately 3.14159. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: π-ā§° āĻŽāĻžāύ āĻĒā§ā§°āĻžā§Ÿ 3.14159, āϝāĻžāĻ• 3.14 āϧ⧰āĻž āĻšā§ŸāĨ¤


1. What is the approximate value of π ? (ā§§. π-ā§° āφāύ⧁āĻŽāĻžāύāĻŋāĻ• āĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 2.14 (b) 3.14 (c) 4.14 (d) 5.14


Ans / āωāĻ¤ā§āϤ⧰: (b) 3.14


Explanation: π ≈ 3.14159. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: π ≈ 3.14159āĨ¤


2. Which fraction is commonly used for π ? (⧍. π-ā§° āĻŦāĻžāĻŦ⧇ āϏāĻžāϧāĻžā§°āĻŖāϤ⧇ āϕ⧋āύāĻŸā§‹ āĻ­āĻ—ā§āύāĻžāĻ‚āĻļ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻž āĻšā§Ÿ ?)


(a) 21/7 (b) 20/7 (c) 22/7 (d) 25/7


Ans / āωāĻ¤ā§āϤ⧰: (c) 22/7


Explanation: 22/7 is a common approximation of π. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 22/7 āĻšā§ˆāϛ⧇ π-ā§° āĻāϟāĻž āϏāĻžāϧāĻžā§°āĻŖ āφāύ⧁āĻŽāĻžāύāĻŋāĻ• āĻŽāĻžāύāĨ¤


3. π is the ratio of: (ā§Š. π āĻ•āĻŋāĻšā§° āĻ…āύ⧁āĻĒāĻžāϤ ?)


(a) Radius to Diameter  (b) Circumference to Diameter
(c) Diameter to Radius  (d) Area to Radius


Ans / āωāĻ¤ā§āϤ⧰: (b) Circumference to Diameter


Explanation: π = Circumference ÷ Diameter. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: π = āĻĒā§°āĻŋāϧāĻŋ ÷ āĻŦā§āϝāĻžāϏāĨ¤


4. Which formula gives the circumference of a circle ? (ā§Ē. āϕ⧋āύāĻŸā§‹ āϏ⧂āĻ¤ā§ā§°ā§‡ āĻŦ⧃āĻ¤ā§āϤ⧰ āĻĒā§°āĻŋāϧāĻŋ āĻĻāĻŋā§Ÿā§‡ ?)


(a) πr² (b) 2πr (c) r² (d) d²


Ans / āωāĻ¤ā§āϤ⧰: (b) 2πr


Explanation: Circumference = 2πr. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻĒā§°āĻŋāϧāĻŋ = 2πrāĨ¤


5. If the diameter is 14 cm, the circumference is: (ā§Ģ. āĻŦā§āϝāĻžāϏ 14 cm āĻšāϞ⧇ āĻĒā§°āĻŋāϧāĻŋ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 22 cm (b) 44 cm (c) 28 cm (d) 88 cm


Ans / āωāĻ¤ā§āϤ⧰: (b) 44 cm


Explanation: C = πd = 22/7 × 14 = 44 cm. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: C = πd = 22/7 × 14 = 44 cmāĨ¤


Tough MCQs (āĻ•āĻ āĻŋāύ MCQ)


6. If the radius of a circle is doubled, the circumference becomes: (ā§Ŧ. āĻŦ⧃āĻ¤ā§āϤ⧰ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ āĻĻ⧁āϗ⧁āĻŖ āϕ⧰āĻŋāϞ⧇ āĻĒā§°āĻŋāϧāĻŋ āĻ•āĻŋ āĻš'āĻŦ ?)


(a) Half (b) Same (c) Double (d) Four times


Ans / āωāĻ¤ā§āϤ⧰: (c) Double


Explanation: C = 2πr. If r doubles, C also doubles. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: C = 2πrāĨ¤ r āĻĻ⧁āϗ⧁āĻŖ āĻšāϞ⧇ C-āĻ“ āĻĻ⧁āϗ⧁āĻŖ āĻšā§ŸāĨ¤


7. The diameter of a circle is 20 cm. What is its radius ? (ā§­. āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻŦā§āϝāĻžāϏ 20 cmāĨ¤ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 5 cm (b) 10 cm (c) 20 cm (d) 40 cm


Ans / āωāĻ¤ā§āϤ⧰: (b) 10 cm


Explanation: Radius = Diameter ÷ 2 = 10 cm. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ = āĻŦā§āϝāĻžāϏ ÷ 2 = 10 cmāĨ¤


8. Which of the following is NOT true about π ? (ā§Ž. π-ā§° āĻŦāĻŋāĻˇā§Ÿā§‡ āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ āĻļ⧁āĻĻā§āϧ āύāĻšā§Ÿ ?)


(a) π is irrational.  (b) π is approximately 3.14.
(c) π = 22/7 exactly.  (d) π is used in circle calculations.


Ans / āωāĻ¤ā§āϤ⧰: (c) π = 22/7 exactly.


Explanation: 22/7 is only an approximation. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 22/7 āĻ•ā§‡ā§ąāϞ āφāύ⧁āĻŽāĻžāύāĻŋāĻ• āĻŽāĻžāύ, āϏāĻ āĻŋāĻ• āĻŽāĻžāύ āύāĻšā§ŸāĨ¤


9. A wheel has a diameter of 70 cm. One complete revolution covers: (⧝. āĻāϟāĻž āϚāĻ•āĻžā§° āĻŦā§āϝāĻžāϏ 70 cmāĨ¤ āĻāϟāĻž āĻĒā§‚ā§°ā§āĻŖ āĻ˜ā§‚ā§°āĻŖāϤ āĻ•āĻŋāĻŽāĻžāύ āĻĻā§‚ā§°āĻ¤ā§āĻŦ āĻ…āϤāĻŋāĻ•ā§ā§°āĻŽ āϕ⧰āĻŋāĻŦ ?)


(a) 110 cm (b) 220 cm (c) 440 cm (d) 140 cm


Ans / āωāĻ¤ā§āϤ⧰: (b) 220 cm


Explanation: Circumference = πd = 22/7 × 70 = 220 cm. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻĒā§°āĻŋāϧāĻŋ = πd = 22/7 × 70 = 220 cmāĨ¤


10. If the circumference of a circle is 44 cm and π = 22/7, the radius is: (ā§§ā§Ļ. āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻĒā§°āĻŋāϧāĻŋ 44 cm āφ⧰⧁ π = 22/7 āĻšāϞ⧇ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 5 cm (b) 6 cm (c) 7 cm (d) 14 cm


Ans / āωāĻ¤ā§āϤ⧰: (c) 7 cm


Explanation:
C = 2πr
44 = 2 × 22/7 × r
44 = 44r/7
r = 7 cm


āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:
C = 2πr
44 = 2 × 22/7 × r
r = 7 cm


Board Exam Expected Question (āĻŦ'ā§°ā§āĻĄ āĻĒā§°ā§€āĻ•ā§āώāĻžāϤ āϏāĻŽā§āĻ­āĻžā§ąā§āϝ āĻĒā§ā§°āĻļā§āύ)


Q. The circumference of a circle is alwaysāĻŦ⧃āĻ¤ā§āϤ⧰ āĻĒā§°āĻŋāϧāĻŋ āϏāĻĻāĻžā§Ÿ āĻ•āĻŋāĻšā§° āϏāĻŽāĻžāύ ?


(a) π times the radius  (b) π times the diameter
(c) Radius + Diameter  (d) Diameter²


Ans / āωāĻ¤ā§āϤ⧰: (b) π times the diameter


Explanation: C = πd. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻĒā§°āĻŋāϧāĻŋ = π × āĻŦā§āϝāĻžāϏāĨ¤


11. The circumference of a circle is 88 cm. What is its diameter ? (π = 22/7) (ā§§ā§§. āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻĒā§°āĻŋāϧāĻŋ 88 cmāĨ¤ āĻŦā§āϝāĻžāϏ āĻ•āĻŋāĻŽāĻžāύ? (π = 22/7))


(a) 14 cm (b) 21 cm (c) 28 cm (d) 35 cm


Ans / āωāĻ¤ā§āϤ⧰: (c) 28 cm


Explanation: d = C ÷ π = 88 ÷ (22/7) = 28 cm.


12. Which statement is always true ? (⧧⧍. āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ āωāĻ•ā§āϤāĻŋ āϏāĻĻāĻžā§Ÿ āĻļ⧁āĻĻā§āϧ ?)


(a) π is a whole number  (b) π is a rational number
(c) π is an irrational number  (d) π is a natural number


Ans / āωāĻ¤ā§āϤ⧰: (c) π is an irrational number


Explanation: π cannot be written exactly as a fraction. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: π-ā§° āϏāĻ āĻŋāĻ• āĻŽāĻžāύ āϕ⧋āύ⧋ āĻ­āĻ—ā§āύāĻžāĻ‚āĻļā§°ā§‚āĻĒ⧇ āĻĒā§ā§°āĻ•āĻžāĻļ āϕ⧰āĻŋāĻŦ āĻ¨ā§‹ā§ąāĻžā§°āĻŋāĨ¤


13. If the radius becomes three times, the circumference becomes: (ā§§ā§Š. āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 3 āϗ⧁āĻŖ āϕ⧰āĻŋāϞ⧇ āĻĒā§°āĻŋāϧāĻŋ āĻ•āĻŋāĻŽāĻžāύ āϗ⧁āĻŖ āĻš'āĻŦ ?)


(a) 3 times (b) 6 times (c) 9 times (d) Same


Ans / āωāĻ¤ā§āϤ⧰: (a) 3 times


Explanation: Circumference is directly proportional to radius. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻĒā§°āĻŋāϧāĻŋ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ⧰ āϏ⧈āϤ⧇ āϏ⧰āϞ āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤāĻŋāĻ•āĨ¤


14. A circle has radius 14 cm. Its circumference is: (ā§§ā§Ē. āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 14 cmāĨ¤ āĻĒā§°āĻŋāϧāĻŋ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 44 cm (b) 88 cm (c) 176 cm (d) 616 cm


Ans / āωāĻ¤ā§āϤ⧰: (b) 88 cm


Explanation: C = 2πr = 2 × 22/7 × 14 = 88 cm.


15. Which formula is correct ? (ā§§ā§Ģ. āϕ⧋āύāĻŸā§‹ āϏ⧂āĻ¤ā§ā§° āĻļ⧁āĻĻā§āϧ ?)


(a) C = πr²  (b) C = 2πr  (c) C = r²  (d) C = d²


Ans / āωāĻ¤ā§āϤ⧰: (b) C = 2πr


Explanation: This is the standard formula for circumference. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻāχāĻŸā§‹ āĻŦ⧃āĻ¤ā§āϤ⧰ āĻĒā§°āĻŋāϧāĻŋā§° āĻŽāĻžāύāĻ• āϏ⧂āĻ¤ā§ā§°āĨ¤


16. If the diameter is increased by 50%, the circumference will: (ā§§ā§Ŧ. āĻŦā§āϝāĻžāϏ 50% āĻŦ⧃āĻĻā§āϧāĻŋ āϕ⧰āĻŋāϞ⧇ āĻĒā§°āĻŋāϧāĻŋ āĻ•āĻŋ āĻš'āĻŦ ?)


(a) Increase by 25%  (b) Increase by 50%  (c) Double  (d) Triple


Ans / āωāĻ¤ā§āϤ⧰: (b) Increase by 50%


Explanation: Circumference is directly proportional to diameter. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āĻĒā§°āĻŋāϧāĻŋ āĻŦā§āϝāĻžāϏ⧰ āϏ⧈āϤ⧇ āϏ⧰āϞ āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤāĻŋāĻ•āĨ¤













17. The value of π correct to two decimal places is: (ā§§ā§­. āĻĻ⧁āχ āĻĻāĻļāĻŽāĻŋāĻ• āĻ¸ā§āĻĨāĻžāύāϞ⧈ π-ā§° āĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 3.12 (b) 3.13 (c) 3.14 (d) 3.15


Ans / āωāĻ¤ā§āϤ⧰: (c) 3.14


Explanation: π = 3.14159... āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: π = 3.14159...


18. A circular track has a diameter of 140 m. One round equals: (ā§§ā§Ž. āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤāĻžāĻ•āĻžā§° āĻĒāĻĨā§° āĻŦā§āϝāĻžāϏ 140 māĨ¤ āĻāϟāĻž āĻĒā§‚ā§°ā§āĻŖ āϚāĻ•ā§āϕ⧰ āĻ•āĻŋāĻŽāĻžāύ ?)

(a) 220 m (b) 330 m (c) 440 m (d) 550 m


Ans / āωāĻ¤ā§āϤ⧰: (c) 440 m


Explanation: C = πd = 22/7 × 140 = 440 m.


19. Which of the following is closest to π ? (⧧⧝. āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ π-ā§° āφāϟāĻžāχāϤāĻ•ā§ˆ āĻ“āϚ⧰⧰ āĻŽāĻžāύ ?)

(a) 3.10 (b) 3.14 (c) 3.50 (d) 4.00


Ans / āωāĻ¤ā§āϤ⧰: (b) 3.14


Explanation: π ≈ 3.14159. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: π ≈ 3.14159āĨ¤


20. If circumference = 62.8 cm and π = 3.14, radius is: (⧍ā§Ļ. āϝāĻĻāĻŋ āĻĒā§°āĻŋāϧāĻŋ = 62.8 cm āφ⧰⧁ π = 3.14 āĻšā§Ÿ, āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ āĻ•āĻŋāĻŽāĻžāύ ?)

(a) 5 cm (b) 10 cm (c) 15 cm (d) 20 cm


Ans / āωāĻ¤ā§āϤ⧰: (b) 10 cm


Explanation : āĻŦā§āϝāĻžāĻ–ā§āϝāĻž
C = 2πr
62.8 = 2 × 3.14 × r
r = 10 cm


21. Which number is NOT an approximation of π ? (⧍⧧. āϤāϞ⧰ āϕ⧋āύāĻŸā§‹ π-ā§° āφāύ⧁āĻŽāĻžāύāĻŋāĻ• āĻŽāĻžāύ āύāĻšā§Ÿ ?)

(a) 3.14 (b) 22/7 (c) 3.1416 (d) 4.14


Ans / āωāĻ¤ā§āϤ⧰: (d) 4.14


Explanation: 4.14 is far from π. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 4.14 π-ā§° āĻĒā§°āĻž āĻŦāĻšā§ āĻĻā§‚ā§°āϤāĨ¤


22. Who first used the symbol π widely in mathematics ? (⧍⧍. āĻ—āĻŖāĻŋāϤāϤ π āϚāĻŋāĻšā§āύāĻŸā§‹ āĻŦāĻšā§āϞāĻ­āĻžā§ąā§‡ āĻĒā§ā§°āĻĨāĻŽā§‡ āϕ⧋āύ⧇ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻŋāĻ›āĻŋāϞ ?)

(a) Newton (b) Euler (c) Pythagoras (d) Euclid


Ans / āωāĻ¤ā§āϤ⧰: (b) Euler


Explanation: Leonhard Euler popularized the symbol π. āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: āϞāĻŋāĻ“āύāĻžā§°ā§āĻĄ āĻ…āχāϞāĻžā§°ā§‡ π āϚāĻŋāĻšā§āύāĻŸā§‹ āϜāύāĻĒā§ā§°āĻŋ⧟ āϕ⧰āĻŋāĻ›āĻŋāϞāĨ¤