Letter Coding – Number Logic 1


















Q. If P = AF, K = AA, Z = BF, then H = ? & G = ?


Options / āĻŦāĻŋāĻ•āĻ˛ā§āĻĒāϏāĻŽā§‚āĻš: (A) H = H, G = G (B) H = G, G = H (C) H = AM, G = BH (D) H = AL, G = BC


Letter Pattern Breakdown



  • P = AF: P is the 16th letter, coded as A and F. (P āχāς⧰āĻžāĻœā§€ āĻŦā§°ā§āĻŖāĻŽāĻžāϞāĻžā§° ā§§ā§ŦāϤāĻŽ āφāĻ–ā§°, āχāϝāĻŧāĻžāĻ• AF āĻšāĻŋāϚāĻžāĻĒ⧇ āϕ⧋āĻĄ āϕ⧰āĻž āĻšā§ˆāϛ⧇āĨ¤)

  • K = AA: K is the 11th letter, coded as AA. (K āĻšā§ˆāϛ⧇ ā§§ā§§āϤāĻŽ āφāĻ–ā§°, āχāϝāĻŧāĻžāĻ• AA āĻšāĻŋāϚāĻžāĻĒ⧇ āϕ⧋āĻĄ āϕ⧰āĻž āĻšā§ˆāϛ⧇āĨ¤)

  • Z = BF: Z is the 26th letter, coded as BF. (Z āĻšā§ˆāϛ⧇ ⧍ā§ŦāϤāĻŽ āφāĻ–ā§°, āχāϝāĻŧāĻžāĻ• BF āĻšāĻŋāϚāĻžāĻĒ⧇ āϕ⧋āĻĄ āϕ⧰āĻž āĻšā§ˆāϛ⧇āĨ¤)

  • H and G: According to the given coding pattern, H = H and G = G. (āĻĻāĻŋāϝāĻŧāĻž āϕ⧋āĻĄāĻŋāĻ‚ āĻĒ⧇āϟāĻžā§°ā§āĻŖ āĻ…āύ⧁āϏ⧰āĻŋ H = H āφ⧰⧁ G = GāĨ¤)


Ans / āωāĻ¤ā§āϤ⧰: (A) H = H, G = G


Q. If LJP = 182, CJP = 38, then BJP = ?


Options: (A) 22  (B) 128  (C) 56  (D) 130


Trick


Find the alphabetical positions : āφāĻ–ā§°āĻŦā§‹ā§°ā§° āĻ¸ā§āĻĨāĻžāύ āϞāĻ“āĻ• -



  • L = 12, J = 10, P = 16

  • C = 3, J = 10, P = 16

  • B = 2, J = 10, P = 16


Rule: (First Letter × Third Letter) − Second Letter (āύāĻŋāϝāĻŧāĻŽ: (āĻĒā§ā§°āĻĨāĻŽ āφāĻ–ā§°ā§° āĻ¸ā§āĻĨāĻžāύ × āϤ⧃āϤ⧀āϝāĻŧ āφāĻ–ā§°ā§° āĻ¸ā§āĻĨāĻžāύ) − āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āφāĻ–ā§°ā§° āĻ¸ā§āĻĨāĻžāύ)



  • LJP = (12 × 16) − 10 = 192 − 10 = 182

  • CJP = (3 × 16) − 10 = 48 − 10 = 38

  • BJP = (2 × 16) − 10 = 32 − 10 = 22


Ans: (A) 22


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EJOTY Letter Position Trick (EJOTY āφāĻ–ā§°ā§° āĻ¸ā§āĻĨāĻžāύ⧰ āĻ•ā§ŒāĻļāϞ)


EJOTY is a simple trick to remember the alphabet positions that are multiples of 5. (EJOTY āĻšā§ˆāϛ⧇ āχāς⧰āĻžāĻœā§€ āĻŦā§°ā§āĻŖāĻŽāĻžāϞāĻžā§° ā§Ģ-ā§° āϗ⧁āĻŖāĻŋāϤāĻ• āĻ¸ā§āĻĨāĻžāύ āϏāĻšāĻœā§‡ āĻŽāύāϤ ā§°āĻžāĻ–āĻŋāĻŦāϞ⧈ āĻāϟāĻž āϏāĻšāϜ āĻ•ā§ŒāĻļāϞāĨ¤)


Easy Trick (āϏāĻšāϜ āĻ•ā§ŒāĻļāϞ)


E J O T Y = 5, 10, 15, 20, 25


Just remember the word "EJOTY" to recall these positions instantly. (āĻ•ā§‡ā§ąāϞ "EJOTY" āĻļāĻŦā§āĻĻāĻŸā§‹ āĻŽāύāϤ ā§°āĻžāĻ–āĻŋāϞ⧇āχ āĻāχ āĻ¸ā§āĻĨāĻžāύāϏāĻŽā§‚āĻš āϏāĻšāĻœā§‡ āĻŽāύāϤ āĻĨāĻžāĻ•āĻŋāĻŦāĨ¤)


Uses (āĻŦā§āĻ¯ā§ąāĻšāĻžā§°) : This trick is very useful in Coding-Decoding, Alphabet Series, Letter Position, Analogy, and other Reasoning questions. āĻāχ āĻ•ā§ŒāĻļāϞ Coding-Decoding, Alphabet Series, Letter Position, Analogy āφ⧰⧁ āĻ…āĻ¨ā§āϝāĻžāĻ¨ā§āϝ Reasoning āĻĒā§ā§°āĻļā§āύ āϏāĻŽāĻžāϧāĻžāύāϤ āĻ…āϤāĻŋ āωāĻĒāϝ⧋āĻ—ā§€


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Q. If A = 5, B = 29, C = 19, then H = ?


Options: (A) 636  (B) 737  (C) 635  (D) 735


Trick


Observe the pattern: āϧāĻžā§°āĻžāĻŸā§‹ āϞāĻ•ā§āĻˇā§āϝ āϕ⧰āĻ• -



  • A = 1 + 2² = 1 + 4 = 5

  • B = 2 + 3³ = 2 + 27 = 29

  • C = 3 + 4² = 3 + 16 = 19


The powers alternate as Square (²), Cube (³), Square (²), Cube (³)... [āχāϝāĻŧāĻžāϤ Square (²) āφ⧰⧁ Cube (³) āĻ•ā§ā§°āĻŽā§‡ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻž āĻšā§ˆāϛ⧇āĨ¤]


So for H (8th letter) : āĻāϤāĻŋāϝāĻŧāĻž H-ā§° āĻŦāĻžāĻŦ⧇ - H = 8 + 9³ = 8 + 729 = 737


Ans:āωāĻ¤ā§āϤ⧰ : (B) 737


Q. # : LHM :: OKP : %  Options: A) # = FDH, % = NHU  B) # = GCH, % = TPU C)  # = DCV, % = NHY  D)  # = UPS, % = RPV


Trick


In an analogy question: # : LHM :: OKP : %


Read it as: # → LHM is the same type of relation as OKP → %. (Pattern : +3, +3, +3)


So, check each option:



  • A) Pattern not same

  • B) GCH → LHM (+5, +5, +5) and OKP → TPU (+5, +5, +5)

  • C) Pattern not same

  • D) Pattern not same


Ans: B) # = GCH, % = TPU


Q. If MIKE = 2%#$ and KOAL = #@75, then AIM = ?


Options: A) 7%2  B) 2%5  C) @25  D) #2D


Trick


From MIKE = 2%#$ : M = 2, I = %, K = #, E = $


From KOAL = #@75: K = #, O = @, A = 7, L = 5


Now AIM = A = 7, I = %, M = 2 = 7%2


Ans: A) 7%2


Q. MAN = 16, COW = 4, DOG = ?


Option: A. 40  B. 12 C. 25  D. 24


TrickAlphabet value add → multiply the digits


A=1, B=2, C=3 ... Z=26


MAN: M + A + N = 13 + 1 + 14 = 28 = 2  8 = 16


COW: C + O + W = 3 + 15 + 23 = 41 = 4 × 1 = 4


Now, DOG: D + O + G = 4 + 15 + 7 = 26 = 2 × 6 = 12


Ans:(āωāĻ¤ā§āϤ⧰:) (b) 12


Q) C_BN_ _V_ _ HC_B_H  


Option: A. VHCBNVN B. HVCNBVN C. VCBHNVN D. VHBNCHV


Trick









  1. Divide into 3 equal parts: C_BN_ | _V__H | C_B_H

  2. Now look at the 1st part: C _ B N _

  3. Fill it to make a meaningful pattern: C V B N H


1st Part Pattern CVBNH


Now make the 2nd and 3rd parts follow the same pattern: 2nd Part → HVCBN, 3rd Part → CVBNH


So the missing letters are: V H C B N V N


CVBNHCVBNHCVBN


Ans: A. VHCBNVN


Q. Series: _ VDWY _ DWYV _ WY _ D _


Option: A. YVYVW  B. YVDVW  C YWDVW  D. YVDVY_



  • We need to fill the 5 blanks.

  • Observe the repeating pattern: YVDW → VDWY → DWYV → WYVD → YVDW

  • Now place the missing letters: _ VDWYY, _ DWYVV, _ WYD, _ DV, Last _W

  • So the missing letters are: Y V D V W

  • Ans: B. YVDVW


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Q. If 15 × 3 = 9, 11 × 2 = 4, then 23 × 5 = ? (āϝāĻĻāĻŋ 15 × 3 = 9, 11 × 2 = 4 āĻšāϝāĻŧ, āϤ⧇āĻ¨ā§āϤ⧇ 23 × 5 = ?)


Options / āĻŦāĻŋāĻ•āĻ˛ā§āĻĒāϏāĻŽā§‚āĻš: (A) 9 (B) 36 (C) 49 (D) 64


Solution / āϏāĻŽāĻžāϧāĻžāύ :


Observe the pattern carefully. (āϧāĻžā§°āĻžāĻŸā§‹ āĻ­āĻžāϞāĻĻ⧰⧇ āϞāĻ•ā§āĻˇā§āϝ āϕ⧰āĻ•āĨ¤)



  • 15 × 3 = 45 → 4 + 5 = 9

  • 11 × 2 = 22 → 2 + 2 = 4


Rule: Multiply the numbers, then add the digits of the product. (āύāĻŋāϝāĻŧāĻŽ: āϏāĻ‚āĻ–ā§āϝāĻž āĻĻ⧁āϟāĻž āϗ⧁āĻŖ āϕ⧰āĻŋ, āĻĢāϞāĻžāĻĢāϞ⧰ āĻ…āĻ‚āĻ•āϏāĻŽā§‚āĻš āϝ⧋āĻ— āϕ⧰āĻ•āĨ¤)


Now,



  • 23 × 5 = 115 → 1 + 1 + 5 = 7


Ans / āωāĻ¤ā§āϤ⧰: (A) 7


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EJOTY Letter Position Trick (EJOTY āφāĻ–ā§°ā§° āĻ¸ā§āĻĨāĻžāύ⧰ āĻ•ā§ŒāĻļāϞ) : Click Here


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Q. If MELODI = 22, MODI = 15, then MELONI = ? āϝāĻĻāĻŋ MELODI = 22, MODI = 15 āĻšāϝāĻŧ, āϤ⧇āĻ¨ā§āϤ⧇ MELONI = ?


Options / āĻŦāĻŋāĻ•āĻ˛ā§āĻĒāϏāĻŽā§‚āĻš: (A) 32 (B) 18 (C) 35 (D) 25


Solution / āϏāĻŽāĻžāϧāĻžāύ


Use the alphabet positions of the letters. (āφāĻ–ā§°āϏāĻŽā§‚āĻšā§° Alphabet Position āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āϕ⧰āĻ•āĨ¤)


MELODI = (M + E) − (L + O) − (D + I) = (13 + 5) − (12 + 15) − (4 + 9) = 18 − 27 − 13 = −22 → 22


MODI = (M + O) − (D + I) = (13 + 15) − (4 + 9) = 28 − 13 = 15


MELONI = (M + E) − (L + O) − (N + I) = (13 + 5) − (12 + 15) − (14 + 9) = 18 − 27 − 23 = −32 → 32


Rule/āύāĻŋāϝāĻŧāĻŽ: Ignore the negative (−) sign and take only the numerical value. (āĻ‹āĻŖāĻžāĻ¤ā§āĻŽāĻ• (−) āϚāĻŋāĻšā§āύāĻŸā§‹ āωāĻĒ⧇āĻ•ā§āώāĻž āϕ⧰āĻŋ āĻ•ā§‡ā§ąāϞ āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ā§° āĻŽāĻžāύ āĻ˛ā§‹ā§ąāĻž āĻšā§ˆāϛ⧇āĨ¤)


Ans / āωāĻ¤ā§āϤ⧰: (A) 32


Q. If A = 5, B = 0, C = 5, then M = ? & P = ?


Options / āĻŦāĻŋāĻ•āĻ˛ā§āĻĒāϏāĻŽā§‚āĻš: (A) 15 & 20  (B) 30 & 0  (C) 30 & 10  (D) 10 & 21


Solution


Multiply the letter position by 5, then multiply the digits of the result. (āφāĻ–ā§°ā§° āĻ¸ā§āĻĨāĻžāύāĻŽāĻžāύāĻ• ā§Ģ-āĻā§°ā§‡ āϗ⧁āĻŖ āϕ⧰āĻ•, āϤāĻžā§° āĻĒāĻŋāĻ›āϤ āĻĢāϞāĻžāĻĢāϞ⧰ āĻ…āĻ‚āĻ•āĻŦā§‹ā§°āĻ• āϗ⧁āĻŖ āϕ⧰āĻ•āĨ¤)



  • A = 1 × 5 = 5

  • B = 2 × 5 = 10 → 1 × 0 = 0

  • C = 3 × 5 = 15 → 1 × 5 = 5


Now,



  • M = 13 × 5 = 65 → 6 × 5 = 30

  • P = 16 × 5 = 80 → 8 × 0 = 0


Ans / āωāĻ¤ā§āϤ⧰: (B) 30 & 0













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