Letter Coding â Number Logic 1
Q. If P = AF, K = AA, Z = BF, then H = ? & G = ?
Options / āĻŦāĻŋāĻāϞā§āĻĒāϏāĻŽā§āĻš: (A) H = H, G = G (B) H = G, G = H (C) H = AM, G = BH (D) H = AL, G = BC
Letter Pattern Breakdown
- P = AF: P is the 16th letter, coded as A and F. (P āĻāĻā§°āĻžāĻā§ āĻŦā§°ā§āĻŖāĻŽāĻžāϞāĻžā§° ā§§ā§ŦāϤāĻŽ āĻāĻā§°, āĻāϝāĻŧāĻžāĻ AF āĻšāĻŋāĻāĻžāĻĒā§ āĻā§āĻĄ āĻā§°āĻž āĻšā§āĻā§āĨ¤)
- K = AA: K is the 11th letter, coded as AA. (K āĻšā§āĻā§ ā§§ā§§āϤāĻŽ āĻāĻā§°, āĻāϝāĻŧāĻžāĻ AA āĻšāĻŋāĻāĻžāĻĒā§ āĻā§āĻĄ āĻā§°āĻž āĻšā§āĻā§āĨ¤)
- Z = BF: Z is the 26th letter, coded as BF. (Z āĻšā§āĻ⧠⧍ā§ŦāϤāĻŽ āĻāĻā§°, āĻāϝāĻŧāĻžāĻ BF āĻšāĻŋāĻāĻžāĻĒā§ āĻā§āĻĄ āĻā§°āĻž āĻšā§āĻā§āĨ¤)
- H and G: According to the given coding pattern, H = H and G = G. (āĻĻāĻŋāϝāĻŧāĻž āĻā§āĻĄāĻŋāĻ āĻĒā§āĻāĻžā§°ā§āĻŖ āĻ āύā§āϏ⧰āĻŋ H = H āĻā§°ā§ G = GāĨ¤)
Ans / āĻāϤā§āϤ⧰: (A) H = H, G = G
Q. If LJP = 182, CJP = 38, then BJP = ?
Options: (A) 22 (B) 128 (C) 56 (D) 130
Trick
Find the alphabetical positions : āĻāĻā§°āĻŦā§ā§°ā§° āϏā§āĻĨāĻžāύ āϞāĻāĻ -
- L = 12, J = 10, P = 16
- C = 3, J = 10, P = 16
- B = 2, J = 10, P = 16
Rule: (First Letter × Third Letter) − Second Letter (āύāĻŋāϝāĻŧāĻŽ: (āĻĒā§ā§°āĻĨāĻŽ āĻāĻā§°ā§° āϏā§āĻĨāĻžāύ × āϤā§āϤā§āϝāĻŧ āĻāĻā§°ā§° āϏā§āĻĨāĻžāύ) − āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āĻāĻā§°ā§° āϏā§āĻĨāĻžāύ)
- LJP = (12 × 16) − 10 = 192 − 10 = 182
- CJP = (3 × 16) − 10 = 48 − 10 = 38
- BJP = (2 × 16) − 10 = 32 − 10 = 22
Ans: (A) 22
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EJOTY Letter Position Trick (EJOTY āĻāĻā§°ā§° āϏā§āĻĨāĻžāύ⧰ āĻā§āĻļāϞ)
EJOTY is a simple trick to remember the alphabet positions that are multiples of 5. (EJOTY āĻšā§āĻā§ āĻāĻā§°āĻžāĻā§ āĻŦā§°ā§āĻŖāĻŽāĻžāϞāĻžā§° ā§Ģ-ā§° āĻā§āĻŖāĻŋāϤāĻ āϏā§āĻĨāĻžāύ āϏāĻšāĻā§ āĻŽāύāϤ ā§°āĻžāĻāĻŋāĻŦāϞ⧠āĻāĻāĻž āϏāĻšāĻ āĻā§āĻļāϞāĨ¤)
Easy Trick (āϏāĻšāĻ āĻā§āĻļāϞ)
E J O T Y = 5, 10, 15, 20, 25
Just remember the word "EJOTY" to recall these positions instantly. (āĻā§ā§ąāϞ "EJOTY" āĻļāĻŦā§āĻĻāĻā§ āĻŽāύāϤ ā§°āĻžāĻāĻŋāϞā§āĻ āĻāĻ āϏā§āĻĨāĻžāύāϏāĻŽā§āĻš āϏāĻšāĻā§ āĻŽāύāϤ āĻĨāĻžāĻāĻŋāĻŦāĨ¤)
Uses (āĻŦā§āĻ¯ā§ąāĻšāĻžā§°) : This trick is very useful in Coding-Decoding, Alphabet Series, Letter Position, Analogy, and other Reasoning questions. āĻāĻ āĻā§āĻļāϞ Coding-Decoding, Alphabet Series, Letter Position, Analogy āĻā§°ā§ āĻ āύā§āϝāĻžāύā§āϝ Reasoning āĻĒā§ā§°āĻļā§āύ āϏāĻŽāĻžāϧāĻžāύāϤ āĻ āϤāĻŋ āĻāĻĒāϝā§āĻā§
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Q. If A = 5, B = 29, C = 19, then H = ?
Options: (A) 636 (B) 737 (C) 635 (D) 735
Trick
Observe the pattern: āϧāĻžā§°āĻžāĻā§ āϞāĻā§āώā§āϝ āĻā§°āĻ -
- A = 1 + 2² = 1 + 4 = 5
- B = 2 + 3³ = 2 + 27 = 29
- C = 3 + 4² = 3 + 16 = 19
The powers alternate as Square (²), Cube (³), Square (²), Cube (³)... [āĻāϝāĻŧāĻžāϤ Square (²) āĻā§°ā§ Cube (³) āĻā§ā§°āĻŽā§ āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻž āĻšā§āĻā§āĨ¤]
So for H (8th letter) : āĻāϤāĻŋāϝāĻŧāĻž H-ā§° āĻŦāĻžāĻŦā§ - H = 8 + 9³ = 8 + 729 = 737
Ans:āĻāϤā§āϤ⧰ : (B) 737
Q. # : LHM :: OKP : % Options: A) # = FDH, % = NHU B) # = GCH, % = TPU C) # = DCV, % = NHY D) # = UPS, % = RPV
Trick
In an analogy question: # : LHM :: OKP : %
Read it as: # → LHM is the same type of relation as OKP → %. (Pattern : +3, +3, +3)
So, check each option:
- A) Pattern not same
- B) GCH → LHM (+5, +5, +5) and OKP → TPU (+5, +5, +5)
- C) Pattern not same
- D) Pattern not same
Ans: B) # = GCH, % = TPU
Q. If MIKE = 2%#$ and KOAL = #@75, then AIM = ?
Options: A) 7%2 B) 2%5 C) @25 D) #2D
Trick
From MIKE = 2%#$ : M = 2, I = %, K = #, E = $
From KOAL = #@75: K = #, O = @, A = 7, L = 5
Now AIM = A = 7, I = %, M = 2 = 7%2
Ans: A) 7%2
Q. MAN = 16, COW = 4, DOG = ?
Option: A. 40 B. 12 C. 25 D. 24
Trick: Alphabet value add → multiply the digits
A=1, B=2, C=3 ... Z=26
MAN: M + A + N = 13 + 1 + 14 = 28 = 2 8 = 16
COW: C + O + W = 3 + 15 + 23 = 41 = 4 × 1 = 4
Now, DOG: D + O + G = 4 + 15 + 7 = 26 = 2 × 6 = 12
Ans:(āĻāϤā§āϤ⧰:) (b) 12
Q) C_BN_ _V_ _ HC_B_H
Option: A. VHCBNVN B. HVCNBVN C. VCBHNVN D. VHBNCHV
Trick
- Divide into 3 equal parts: C_BN_ | _V__H | C_B_H
- Now look at the 1st part: C _ B N _
- Fill it to make a meaningful pattern: C V B N H
1st Part Pattern = CVBNH
Now make the 2nd and 3rd parts follow the same pattern: 2nd Part → HVCBN, 3rd Part → CVBNH
So the missing letters are: V H C B N V N
CVBNHCVBNHCVBNH
Ans: A. VHCBNVN
Q. Series: _ VDWY _ DWYV _ WY _ D _
Option: A. YVYVW B. YVDVW C YWDVW D. YVDVY_
- We need to fill the 5 blanks.
- Observe the repeating pattern: YVDW → VDWY → DWYV → WYVD → YVDW
- Now place the missing letters: _ VDWY → Y, _ DWYV → V, _ WY → D, _ D → V, Last _ → W
- So the missing letters are: Y V D V W
- Ans: B. YVDVW
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Q. If 15 × 3 = 9, 11 × 2 = 4, then 23 × 5 = ? (āϝāĻĻāĻŋ 15 × 3 = 9, 11 × 2 = 4 āĻšāϝāĻŧ, āϤā§āύā§āϤ⧠23 × 5 = ?)
Options / āĻŦāĻŋāĻāϞā§āĻĒāϏāĻŽā§āĻš: (A) 9 (B) 36 (C) 49 (D) 64
Solution / āϏāĻŽāĻžāϧāĻžāύ :
Observe the pattern carefully. (āϧāĻžā§°āĻžāĻā§ āĻāĻžāϞāĻĻā§°ā§ āϞāĻā§āώā§āϝ āĻā§°āĻāĨ¤)
- 15 × 3 = 45 → 4 + 5 = 9
- 11 × 2 = 22 → 2 + 2 = 4
Rule: Multiply the numbers, then add the digits of the product. (āύāĻŋāϝāĻŧāĻŽ: āϏāĻāĻā§āϝāĻž āĻĻā§āĻāĻž āĻā§āĻŖ āĻā§°āĻŋ, āĻĢāϞāĻžāĻĢāϞ⧰ āĻ āĻāĻāϏāĻŽā§āĻš āϝā§āĻ āĻā§°āĻāĨ¤)
Now,
- 23 × 5 = 115 → 1 + 1 + 5 = 7
Ans / āĻāϤā§āϤ⧰: (A) 7
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EJOTY Letter Position Trick (EJOTY āĻāĻā§°ā§° āϏā§āĻĨāĻžāύ⧰ āĻā§āĻļāϞ) : Click Here
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Q. If MELODI = 22, MODI = 15, then MELONI = ? āϝāĻĻāĻŋ MELODI = 22, MODI = 15 āĻšāϝāĻŧ, āϤā§āύā§āϤ⧠MELONI = ?
Options / āĻŦāĻŋāĻāϞā§āĻĒāϏāĻŽā§āĻš: (A) 32 (B) 18 (C) 35 (D) 25
Solution / āϏāĻŽāĻžāϧāĻžāύ
Use the alphabet positions of the letters. (āĻāĻā§°āϏāĻŽā§āĻšā§° Alphabet Position āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻāĨ¤)
MELODI = (M + E) − (L + O) − (D + I) = (13 + 5) − (12 + 15) − (4 + 9) = 18 − 27 − 13 = −22 → 22
MODI = (M + O) − (D + I) = (13 + 15) − (4 + 9) = 28 − 13 = 15
MELONI = (M + E) − (L + O) − (N + I) = (13 + 5) − (12 + 15) − (14 + 9) = 18 − 27 − 23 = −32 → 32
Rule/āύāĻŋāϝāĻŧāĻŽ: Ignore the negative (−) sign and take only the numerical value. (āĻāĻŖāĻžāϤā§āĻŽāĻ (−) āĻāĻŋāĻšā§āύāĻā§ āĻāĻĒā§āĻā§āώāĻž āĻā§°āĻŋ āĻā§ā§ąāϞ āϏāĻāĻā§āϝāĻžāĻā§ā§° āĻŽāĻžāύ āϞā§ā§ąāĻž āĻšā§āĻā§āĨ¤)
Ans / āĻāϤā§āϤ⧰: (A) 32
Q. If A = 5, B = 0, C = 5, then M = ? & P = ?
Options / āĻŦāĻŋāĻāϞā§āĻĒāϏāĻŽā§āĻš: (A) 15 & 20 (B) 30 & 0 (C) 30 & 10 (D) 10 & 21
Solution
Multiply the letter position by 5, then multiply the digits of the result. (āĻāĻā§°ā§° āϏā§āĻĨāĻžāύāĻŽāĻžāύāĻ ā§Ģ-āĻā§°ā§ āĻā§āĻŖ āĻā§°āĻ, āϤāĻžā§° āĻĒāĻŋāĻāϤ āĻĢāϞāĻžāĻĢāϞ⧰ āĻ āĻāĻāĻŦā§ā§°āĻ āĻā§āĻŖ āĻā§°āĻāĨ¤)
- A = 1 × 5 = 5
- B = 2 × 5 = 10 → 1 × 0 = 0
- C = 3 × 5 = 15 → 1 × 5 = 5
Now,
- M = 13 × 5 = 65 → 6 × 5 = 30
- P = 16 × 5 = 80 → 8 × 0 = 0
Ans / āĻāϤā§āϤ⧰: (B) 30 & 0
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