UP TET Practice Set
1. Number System / āϏāĻāĻā§āϝāĻž āĻĒāĻĻā§āϧāϤāĻŋ
Q. What is the place value of 5 in 345678 ? āĻĒā§ā§°āĻļā§āύ: 345678 āϏāĻāĻā§āϝāĻžāĻā§ā§° 5-ā§° āϏā§āĻĨāĻžāύāĻŽāĻžāύ āĻāĻŋāĻŽāĻžāύ ?
(a) 5 (b) 50 (c) 500 (d) 5000
Ans / āĻāϤā§āϤ⧰: (d) 5000
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž: In the number 345678, the digit 5 is in the thousands place.
Therefore, Place Value = 5 × 1000 = 5000
āĻŦā§āϝāĻžāĻā§āϝāĻž: 345678 āϏāĻāĻā§āϝāĻžāĻā§āϤ 5 āϏāĻāĻā§āϝāĻžāĻā§ āĻšāĻžāĻāĻžā§°ā§° āϏā§āĻĨāĻžāύāϤ āĻāĻā§āĨ¤
āϏā§āϝāĻŧā§āĻšā§, āϏā§āĻĨāĻžāύāĻŽāĻžāύ = 5 × 1000 = 5000
Place Value of 5 = 5000 / 5-ā§° āϏā§āĻĨāĻžāύāĻŽāĻžāύ = 5000.
===================================
4. Simplification / āϏāϰāϞā§āĻā§°āĻŖ
Q. What is the value of 48 ÷ 6 + 3 × 2 − 5 ? (āĻĒā§ā§°āĻļā§āύ: 48 ÷ 6 + 3 × 2 − 5-ā§° āĻŽāĻžāύ āĻāĻŋāĻŽāĻžāύ ?)
(a) 9 (b) 11 (c) 13 (d) 15
Ans / āĻāϤā§āϤ⧰: (c) 9
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž: Using the BODMAS rule: (BODMAS āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŋ āĻĒā§ā§°āĻĨāĻŽā§ āĻāĻžāĻ āĻā§°ā§ āĻā§āĻŖ āĻā§°āĻŋāĻŦ āϞāĻžāĻā§āĨ¤)
48 ÷ 6 + 3 × 2 − 5 = 8 + 6 − 5 = 14 − 5 = 9
Ans / āĻāϤā§āϤ⧰: (a) 9.
===================================================
7. Simple Interest / āϏ⧰āϞ āϏā§āϤ
Q. âš240 simple interest is earned on âš1500 in 2 years. What is the annual rate of interest ? (āĻĒā§ā§°āĻļā§āύ: âš1500 āĻāĻāĻžā§° āĻāĻĒā§°āϤ 2 āĻŦāĻā§°āϤ âš240 āϏ⧰āϞ āϏā§āϤ āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤ āĻŦāĻžā§°ā§āώāĻŋāĻ āϏā§āϤ⧰ āĻšāĻžā§° āĻāĻŋāĻŽāĻžāύ ?)
(a) 6% (b) 7% (c) 8% (d) 9%
Ans / āĻāϤā§āϤ⧰: (c) 8%
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
Formula of Simple Interest: SI = (P × R × T) / 100
Given: SI = âš240, P = âš1500, T = 2 years
240 = 1500 × R × 2 / 100
240 = 30R
R = 240/30 = 8
Therefore, Rate of Interest = 8% per annum.
Short Tricks: Rate = (1 Year's Interest ÷ Principal) × 100 = 120 ÷ 1500 × 100 = 8%
2 āĻŦāĻā§°āϤ āϏā§āϤ = âš240
⇒ 1 āĻŦāĻā§°āϤ āϏā§āϤ = âš120
Now,
120 / 1500 × 100
===================================================
10. Ratio and Proportion / āĻ āύā§āĻĒāĻžāϤ āĻā§°ā§ āϏāĻŽāĻžāύā§āĻĒāĻžāϤ
Q / āĻĒā§ā§°āĻļā§āύ: If a : b = 3 : 5 and b : c = 4 : 7 then what is a : c ? / āϝāĻĻāĻŋ a : b = 3 : 5 āĻā§°ā§ b : c = 4 : 7, āϤā§āύā§āϤ⧠a : c āĻāĻŋāĻŽāĻžāύ āĻš'āĻŦ ?
(a) 6:7 (b) 3:7 (c) 5:7 (d) 12:35
Ans / āĻāϤā§āϤ⧰: 12 : 35
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
Given / āĻĻāĻŋāϝāĻŧāĻž āĻāĻā§:
a : b = 3 : 5, b : c = 4 : 7
Therefore / āϏā§āϝāĻŧā§āĻšā§,
a : c = a : b × b : c = 3 / 5 × 4 / 7 = 12 / 35
So, a : c = 12 : 35.
āĻ ā§°ā§āĻĨāĻžā§, a : c = 12 : 35
Short Tricks:
"Top × Top : Bottom × Bottom" ("āĻāĻĒā§°ā§° āϏāĻāĻā§āϝāĻž āĻā§āĻŖ : āϤāϞ⧰ āϏāĻāĻā§āϝāĻž āĻā§āĻŖ")
Example:
= 3:5 and 4:7
= 12 : 35
Ans = 12 : 35
================================================
Fractions / āĻāĻā§āύāĻžāĻāĻļ
Q/ āĻĒā§ā§°āĻļā§āύ: What is the value of 3/4 + 2/5 ? āĻĒā§ā§°āĻļā§āύ: 3/4 + 2/5-ā§° āĻŽāĻžāύ āĻāĻŋāĻŽāĻžāύ ?
(a) 23/20 (b) 17/20 (c) 11/20 (d) 13/20
Ans / āĻāϤā§āϤ⧰: (a) 23/20
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
LCM of 4 and 5 = 20 (4 āĻā§°ā§ 5-ā§° LCM = 20)
3 / 4 = 15 / 20
2 / 5 = 8 / 20
Now add / āĻāϤāĻŋāϝāĻŧāĻž āϝā§āĻ āĻā§°āĻ: 15 / 20 + 8 / 20 = 23 / 20
Therefore (āϏā§āϝāĻŧā§āĻšā§,), 3/4 + 2/5 = 23/20
Ans / āĻāϤā§āϤ⧰: (a) 23/20.
==================================================
Percentage / āĻļāϤāĻā§°āĻž
Q / āĻĒā§ā§°āĻļā§āύ: What is 15% of 200 ? / 200-ā§° 15% āĻāĻŋāĻŽāĻžāύ ?
(a) 25 (b) 30 (c) 5 (d) 40
Ans / āĻāϤā§āϤ⧰: (b) 30
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
15% of 200 = 15/100 × 200 = 30
So (āĻ ā§°ā§āĻĨāĻžā§,), 15% of 200 = 30.
Ans / āĻāϤā§āϤ⧰: (b) 30.
Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ
15% = 10% + 5%
- 10% of 200 = 20
- 5% of 200 = 10
So, 20 + 10 = 30
Ans = 30
=========================================
Q. A can complete a work in 15 days and B can complete the same work in 20 days. In how many days will they complete the work together ? (A āĻ āĻā§āύ⧠āĻāĻāĻž āĻāĻžāĻŽ 15 āĻĻāĻŋāύāϤ āĻā§°ā§ B-āĻ āĻāĻā§ āĻāĻžāĻŽ 20 āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§°āĻŋāĻŦ āĻĒāĻžā§°ā§āĨ¤ āĻĻā§āϝāĻŧā§āĻāύ⧠āĻāĻā§āϞāĻā§ āĻāĻžāĻŽāĻā§ āĻāĻŋāĻŽāĻžāύ āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§°āĻŋāĻŦ ?)
(a) 8 days / āĻĻāĻŋāύ (b) 10 days / āĻĻāĻŋāύ (c) 12 days / āĻĻāĻŋāύ (d) 15 days / āĻĻāĻŋāύ
Ans / āĻāϤā§āϤ⧰: (c) 12 days / 12 āĻĻāĻŋāύ
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž: Together Time = Product ÷ Sum
Work done by A in 1 day / A-āĻ ā§§ āĻĻāĻŋāύāϤ āĻā§°āĻž āĻāĻžāĻŽ : 1/15
Work done by B in 1 day / B-āĻ ā§§ āĻĻāĻŋāύāϤ āĻā§°āĻž āĻāĻžāĻŽ : 1/20
Together in 1 day / āĻĻā§āϝāĻŧā§āĻāύ⧠⧧ āĻĻāĻŋāύāϤ āĻā§°āĻž āĻāĻžāĻŽ : 1 / 15 + 1 / 20
LCM of 15 and 20 = 60
= 4 / 60 + 3 / 60 = 7/60
Therefore, time taken together: 60/7 = 8.57 days
Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ
When two persons take a and b days:
Time together = a×b / a+b
= 15 × 20 / 15+20 = 300 / 35 = 60/7 ≈ 8.57 days
Ans = 8 days
============================================================
Q. The average marks of 40 students in a class is 45. Find the total marks. (āĻāĻāĻž āĻļā§ā§°ā§āĻŖā§ā§° 40 āĻāύ āĻļāĻŋāĻā§āώāĻžā§°ā§āĻĨā§ā§° āĻāĻĄāĻŧ āύāĻŽā§āĻŦā§° 45āĨ¤ āĻŽā§āĻ āύāĻŽā§āĻŦā§° āύāĻŋā§°ā§āĻŖāϝāĻŧ āĻā§°āĻāĨ¤)
(a) 1600 | (b) 1700 | (c) 1800 | (d) 1900
Ans / āĻāϤā§āϤ⧰: (c) 1800
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
Formula / āϏā§āϤā§ā§°: Average = Total Marks ÷ Number of Students (āĻāĻĄāĻŧ = āĻŽā§āĻ āύāĻŽā§āĻŦā§° ÷ āĻļāĻŋāĻā§āώāĻžā§°ā§āĻĨā§ā§° āϏāĻāĻā§āϝāĻž)
Therefore / āϏā§āϝāĻŧā§āĻšā§, Total Marks = Average × Number of Students (āĻŽā§āĻ āύāĻŽā§āĻŦā§° = āĻāĻĄāĻŧ × āĻļāĻŋāĻā§āώāĻžā§°ā§āĻĨā§ā§° āϏāĻāĻā§āϝāĻž)
=1800
Total Marks / āĻŽā§āĻ āύāĻŽā§āĻŦā§° = 1800
Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ
Average × Number = Total (āĻāĻĄāĻŧ × āϏāĻāĻā§āϝāĻž = āĻŽā§āĻ )
45 × 40 = 45 × 4 × 10 = 180 × 10 =
Ans = 1800
=========================================================
Q. What is the value of 2.75 × 0.4 ? (2.75 × 0.4-ā§° āĻŽāĻžāύ āĻāĻŋāĻŽāĻžāύ ?)
(a) 1.10 | (b) 1.00 | (c) 1.01 | (d) 1.20
Ans / āĻāϤā§āϤ⧰: (a) 1.10
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
2.75 × 0.4 = 275 /100 × 4 / 10 = 1100 / 1000 =
Therefore / āϏā§āϝāĻŧā§āĻšā§, 2.75 × 0.4 = 1.10
Ans / āĻāϤā§āϤ⧰: (a) 1.10
Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ
Ignore the decimal points first. / āĻĒā§ā§°āĻĨāĻŽā§ āĻĻāĻļāĻŽāĻŋāĻ āĻāĻŋāĻšā§āύ āĻāĻĒā§āĻā§āώāĻž āĻā§°āĻāĨ¤
275 × 4 = 1100
Now count decimal places: i. 2.75 → 2 decimal places, ii. 0.4 → 1 decimal place
Total = 3 decimal places
1100 → 1.100
Ans = 1.10
Tip
Multiply first, place decimal later. (āĻāĻāϤ⧠āĻā§āĻŖ āĻā§°āĻ, āĻĒāĻŋāĻāϤ āĻĻāĻļāĻŽāĻŋāĻ āĻŦāĻšā§ā§ąāĻžāĻāĻāĨ¤)
275 × 4 = 1100
3 decimal places ⇒ 1.100 = 1.10
Ans / āĻāϤā§āϤ⧰: (a) 1.10.
==================================================================
Q. An article is sold for âš800 at a loss of 20%. What is its Cost Price (CP) ? (āĻā§āύ⧠āĻŦāϏā§āϤ⧠âš800 āĻāĻāĻžāϤ āĻŦāĻŋāĻā§ā§°ā§ āĻā§°āĻŋāϞ⧠20% āĻā§āώāϤāĻŋ āĻšāϝāĻŧāĨ¤ āĻāϝāĻŧāĻžā§° āĻā§ā§°āϝāĻŧ āĻŽā§āϞā§āϝ (CP) āĻāĻŋāĻŽāĻžāύ ?)
(a) âš960 | (b) âš1000 | (c) âš1020 | (d) âš1120
Ans / āĻāϤā§āϤ⧰: (b) âš1000
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
Loss = 20%
So, Selling Price (SP) = 80% of Cost Price (CP)
SP = 80% of CP
800 = 80/100 × CP
CP = 800 × 100 / 80
CP = 1000
Cost Price (āĻā§ā§°āϝāĻŧ āĻŽā§āϞā§āϝ) = âš1000
Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ
20% Loss ⇒ SP = 80% of CP
CP = SP × 100 / 80 = 800 × 100 / 80 =
Ans = âš1000
=======================================================
Q. A person travels at a speed of 60 km/h for 3 hours. What distance does he cover ? (āĻāĻāύ āĻŦā§āϝāĻā§āϤāĻŋāϝāĻŧā§ 60 āĻāĻŋāĻŽāĻŋ/āĻāĻŖā§āĻāĻž āĻŦā§āĻāϤ 3 āĻāĻŖā§āĻāĻž āĻā§ā§°āĻŽāĻŖ āĻā§°ā§āĨ¤ āϤā§āĻāĻ āĻāĻŋāĻŽāĻžāύ āĻĻā§ā§°āϤā§āĻŦ āĻ āϤāĻŋāĻā§ā§°āĻŽ āĻā§°ā§ ?)
(a) 150 km | (b) 160 km | (c) 170 km | (d) 180 km
Ans / āĻāϤā§āϤ⧰: (d) 180 km
Explanation: / āĻŦā§āϝāĻžāĻā§āϝāĻž:
Formula / āϏā§āϤā§ā§°: Distance = Speed × Time = 60 × 3 = 1
Therefore / āϏā§āϝāĻŧā§āĻšā§, Distance = 180 km (āĻĻā§ā§°āϤā§āĻŦ = 180 āĻāĻŋāĻŽāĻŋ)
Ans / āĻāϤā§āϤ⧰: (d) 180 km
Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻā§āĻļāϞ
Distance = Speed × Time (āĻĻā§ā§°āϤā§āĻŦ = āĻŦā§āĻ × āϏāĻŽāϝāĻŧ)
60 × 3 = 180
Ans = 180 km
===============================================================
Q. The radius of a circle is 7 cm. What is its area ? (π = 22/7) āĻāĻāĻž āĻŦā§āϤā§āϤ⧰ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 7 āĻā§āĻŽāĻŋāĨ¤ āĻāϝāĻŧāĻžā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāĻŋāĻŽāĻžāύ? (π = 22/7)
10. Time and Work / āϏāĻŽāϝāĻŧ āĻā§°ā§ āĻāĻžāĻŽ
Q. A can complete a work in 15 days and B can complete the same work in 20 days. In how many days will they complete the work together ? (āĻĒā§ā§°āĻļā§āύ: A-āĻ āĻāĻāĻž āĻāĻžāĻŽ 15 āĻĻāĻŋāύāϤ āĻā§°ā§ B-āĻ āĻāĻā§ āĻāĻžāĻŽ 20 āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§°āĻŋāĻŦ āĻĒāĻžā§°ā§āĨ¤ āĻĻā§āϝāĻŧā§āĻāύ⧠āĻāĻā§āϞāĻā§ āĻāĻžāĻŽāĻā§ āĻāĻŋāĻŽāĻžāύ āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§°āĻŋāĻŦ ?)
(a) 8 days / āĻĻāĻŋāύ | (b) 10 days / āĻĻāĻŋāύ | (c) 12 days / āĻĻāĻŋāύ | (d) 15 days / āĻĻāĻŋāύ
Trick: Together Time (āĻāĻā§āϞāĻā§ āϏāĻŽāϝāĻŧ) = (A × B) ÷ (A + B)
11. Average / āĻāĻĄāĻŧ
Q. The average marks of 40 students in a class is 45. Find the total marks. (āĻĒā§ā§°āĻļā§āύ: āĻāĻāĻž āĻļā§ā§°ā§āĻŖā§ā§° 40 āĻāύ āĻļāĻŋāĻā§āώāĻžā§°ā§āĻĨā§ā§° āĻāĻĄāĻŧ āύāĻŽā§āĻŦā§° 45āĨ¤ āĻŽā§āĻ āύāĻŽā§āĻŦā§° āύāĻŋā§°ā§āĻŖāϝāĻŧ āĻā§°āĻāĨ¤)
(a) 1600 | (b) 1700 | (c) 1800 | (d) 1900
Trick: Total Marks = Average × Number of Students (āĻŽā§āĻ āύāĻŽā§āĻŦā§° = āĻāĻĄāĻŧ × āĻļāĻŋāĻā§āώāĻžā§°ā§āĻĨā§ā§° āϏāĻāĻā§āϝāĻž)
12. Mensuration (2D) / āĻā§āώā§āϤā§ā§°āĻŽāĻŋāϤāĻŋ (2D)
Q. The radius of a circle is 7 cm. What is its area ? (π = 22/7) āĻĒā§ā§°āĻļā§āύ: āĻāĻāĻž āĻŦā§āϤā§āϤ⧰ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 7 āĻā§āĻŽāĻŋāĨ¤ āĻāϝāĻŧāĻžā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāĻŋāĻŽāĻžāύ ? (π = 22/7)
(a) 132 cm² | (b) 154 cm² | (c) 176 cm² | (d) 196 cm²
Trick: Area of Circle = πr² (āĻŦā§āϤā§āϤ⧰ āĻā§āώā§āϤā§ā§°āĻĢāϞ = πr²)
13. Time, Distance and Speed / āϏāĻŽāϝāĻŧ, āĻĻā§ā§°āϤā§āĻŦ āĻā§°ā§ āĻŦā§āĻ
Q. A person travels at a speed of 60 km/h for 3 hours. What distance does he cover ? (āĻĒā§ā§°āĻļā§āύ: āĻāĻāύ āĻŦā§āϝāĻā§āϤāĻŋāϝāĻŧā§ 60 āĻāĻŋāĻŽāĻŋ/āĻāĻŖā§āĻāĻž āĻŦā§āĻāϤ 3 āĻāĻŖā§āĻāĻž āĻāϞā§āĨ¤ āϤā§āĻāĻ āĻāĻŋāĻŽāĻžāύ āĻĻā§ā§°āϤā§āĻŦ āĻ āϤāĻŋāĻā§ā§°āĻŽ āĻā§°ā§ ?)
(a) 150 km | (b) 160 km | (c) 170 km | (d) 180 km