UP TET Practice Set


1. Number System / āϏāĻ‚āĻ–ā§āϝāĻž āĻĒāĻĻā§āϧāϤāĻŋ


Q. What is the place value of 5 in 345678 ? āĻĒā§ā§°āĻļā§āύ: 345678 āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ā§° 5-ā§° āĻ¸ā§āĻĨāĻžāύāĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?


(a) 5  (b) 50  (c) 500  (d) 5000


Ans / āωāĻ¤ā§āϤ⧰: (d) 5000


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: In the number 345678, the digit 5 is in the thousands place.


Therefore, Place Value = 5 × 1000 = 5000


āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: 345678 āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹āϤ 5 āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ āĻšāĻžāϜāĻžā§°ā§° āĻ¸ā§āĻĨāĻžāύāϤ āφāϛ⧇āĨ¤


āϏ⧇āϝāĻŧ⧇āĻšā§‡, āĻ¸ā§āĻĨāĻžāύāĻŽāĻžāύ = 5 × 1000 = 5000


Place Value of 5 = 5000 / 5-ā§° āĻ¸ā§āĻĨāĻžāύāĻŽāĻžāύ = 5000.


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4. Simplification / āϏāϰāϞ⧀āϕ⧰āĻŖ


Q. What is the value of 48 ÷ 6 + 3 × 2 − 5 ?  (āĻĒā§ā§°āĻļā§āύ: 48 ÷ 6 + 3 × 2 − 5-ā§° āĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 9  (b) 11  (c) 13  (d) 15


Ans / āωāĻ¤ā§āϤ⧰: (c) 9


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: Using the BODMAS rule: (BODMAS āύāĻŋāϝāĻŧāĻŽ āĻ…āύ⧁āϏ⧰āĻŋ āĻĒā§ā§°āĻĨāĻŽā§‡ āĻ­āĻžāĻ— āφ⧰⧁ āϗ⧁āĻŖ āϕ⧰āĻŋāĻŦ āϞāĻžāϗ⧇āĨ¤)


48 ÷ 6 + 3 × 2 − 5 = 8 + 6 − 5 = 14 − 5 = 9


Ans / āωāĻ¤ā§āϤ⧰: (a) 9.


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7. Simple Interest / āϏ⧰āϞ āϏ⧁āϤ


Q. â‚š240 simple interest is earned on ₹1500 in 2 years. What is the annual rate of interest ? (āĻĒā§ā§°āĻļā§āύ: ₹1500 āϟāĻ•āĻžā§° āĻ“āĻĒā§°āϤ 2 āĻŦāϛ⧰āϤ ₹240 āϏ⧰āϞ āϏ⧁āϤ āĻĒā§‹ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤ āĻŦāĻžā§°ā§āώāĻŋāĻ• āϏ⧁āϤ⧰ āĻšāĻžā§° āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 6%  (b) 7%  (c) 8%  (d) 9%


Ans / āωāĻ¤ā§āϤ⧰: (c) 8%


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


Formula of Simple Interest: SI = (P × R × T) / 100


Given: SI = ₹240, P = ₹1500, T = 2 years


240 = 1500 × R × 2 / 100


240 = 30R


R = 240/30 = 8


Therefore, Rate of Interest = 8% per annum.


Short Tricks: Rate = (1 Year's Interest ÷ Principal) × 100 = 120 ÷ 1500 × 100 = 8%


2 āĻŦāϛ⧰āϤ āϏ⧁āϤ = ₹240


⇒ 1 āĻŦāϛ⧰āϤ āϏ⧁āϤ = ₹120


Now,


 120 / 1500 × 100


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10. Ratio and Proportion / āĻ…āύ⧁āĻĒāĻžāϤ āφ⧰⧁ āϏāĻŽāĻžāύ⧁āĻĒāĻžāϤ


Q / āĻĒā§ā§°āĻļā§āύ: If a : b = 3 : 5 and b : c = 4 : 7 then what is a : c ? / āϝāĻĻāĻŋ a : b = 3 : 5 āφ⧰⧁ b : c = 4 : 7, āϤ⧇āĻ¨ā§āϤ⧇ a : c āĻ•āĻŋāĻŽāĻžāύ āĻš'āĻŦ ?


(a) 6:7  (b) 3:7  (c) 5:7  (d) 12:35


Ans / āωāĻ¤ā§āϤ⧰: 12 : 35


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:
Given / āĻĻāĻŋāϝāĻŧāĻž āφāϛ⧇:


a : b = 3 : 5, b : c = 4 : 7


Therefore / āϏ⧇āϝāĻŧ⧇āĻšā§‡,


a : c = a : b × b : c = 3 / 5 × 4 / 7 = 12 / 35


So, a : c = 12 : 35.


āĻ…ā§°ā§āĻĨāĻžā§Ž, a : c = 12 : 35


Short Tricks:


"Top × Top : Bottom × Bottom" ("āĻ“āĻĒā§°ā§° āϏāĻ‚āĻ–ā§āϝāĻž āϗ⧁āĻŖ : āϤāϞ⧰ āϏāĻ‚āĻ–ā§āϝāĻž āϗ⧁āĻŖ")


Example:


= 3:5 and 4:7 



= 12 : 35 


Ans = 12 : 35


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Fractions / āĻ­āĻ—ā§āύāĻžāĻ‚āĻļ


Q/ āĻĒā§ā§°āĻļā§āύ: What is the value of 3/4 + 2/5 ? āĻĒā§ā§°āĻļā§āύ: 3/4 + 2/5-ā§° āĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?


(a) 23/20  (b) 17/20  (c) 11/20  (d) 13/20


Ans / āωāĻ¤ā§āϤ⧰: (a) 23/20


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


LCM of 4 and 5 = 20 (4 āφ⧰⧁ 5-ā§° LCM = 20)


3 / 4 = 15 / 20 


 2 / 5 = 8 / 20


Now add / āĻāϤāĻŋāϝāĻŧāĻž āϝ⧋āĻ— āϕ⧰āĻ•: 15 / 20 + 8 / 20 = 23 / 20


Therefore (āϏ⧇āϝāĻŧ⧇āĻšā§‡,), 3/4 + 2/5 = 23/20


Ans / āωāĻ¤ā§āϤ⧰: (a) 23/20.


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Percentage / āĻļāϤāϕ⧰āĻž


Q / āĻĒā§ā§°āĻļā§āύ: What is 15% of 200 ? / 200-ā§° 15% āĻ•āĻŋāĻŽāĻžāύ ?


(a) 25  (b) 30  (c) 5  (d) 40


Ans / āωāĻ¤ā§āϤ⧰: (b) 30


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


15% of 200 = 15/100 × 200 = 30


So (āĻ…ā§°ā§āĻĨāĻžā§Ž,), 15% of 200 = 30.


Ans / āωāĻ¤ā§āϤ⧰: (b) 30.


Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ


15% = 10% + 5%



  • 10% of 200 = 20

  • 5% of 200 = 10


So, 20 + 10 = 30


Ans = 30


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Q. A can complete a work in 15 days and B can complete the same work in 20 days. In how many days will they complete the work together ? (A āĻ āϕ⧋āύ⧋ āĻāϟāĻž āĻ•āĻžāĻŽ 15 āĻĻāĻŋāύāϤ āφ⧰⧁ B-āĻ āĻāϕ⧇ āĻ•āĻžāĻŽ 20 āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§‚ā§°ā§āĻŖ āϕ⧰āĻŋāĻŦ āĻĒāĻžā§°ā§‡āĨ¤ āĻĻ⧁āϝāĻŧā§‹āϜāύ⧇ āĻāϕ⧇āϞāϗ⧇ āĻ•āĻžāĻŽāĻŸā§‹ āĻ•āĻŋāĻŽāĻžāύ āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§‚ā§°ā§āĻŖ āϕ⧰āĻŋāĻŦ ?)


(a) 8 days / āĻĻāĻŋāύ  (b) 10 days / āĻĻāĻŋāύ  (c) 12 days / āĻĻāĻŋāύ  (d) 15 days / āĻĻāĻŋāύ


Ans / āωāĻ¤ā§āϤ⧰: (c) 12 days / 12 āĻĻāĻŋāύ


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž: Together Time = Product ÷ Sum


Work done by A in 1 day / A-āĻ ā§§ āĻĻāĻŋāύāϤ āϕ⧰āĻž āĻ•āĻžāĻŽ : 1/15


Work done by B in 1 day / B-āĻ ā§§ āĻĻāĻŋāύāϤ āϕ⧰āĻž āĻ•āĻžāĻŽ : 1/20


Together in 1 day / āĻĻ⧁āϝāĻŧā§‹āϜāύ⧇ ā§§ āĻĻāĻŋāύāϤ āϕ⧰āĻž āĻ•āĻžāĻŽ : 1 / 15 + 1 / 20


LCM of 15 and 20 = 60


= 4 / 60 + 3 / 60 = 7/60


Therefore, time taken together: 60/7 = 8.57 days


Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ


When two persons take a and b days:


Time together = a×b / a+b


                         = 15 × 20 / 15+20 = 300 / 35 = 60/7 ≈ 8.57 days


Ans = 8 days


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Q. The average marks of 40 students in a class is 45. Find the total marks. (āĻāϟāĻž āĻļā§ā§°ā§‡āϪ⧀⧰ 40 āϜāύ āĻļāĻŋāĻ•ā§āώāĻžā§°ā§āĻĨ⧀⧰ āĻ—āĻĄāĻŧ āύāĻŽā§āĻŦā§° 45āĨ¤ āĻŽā§āĻ  āύāĻŽā§āĻŦā§° āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤)


(a) 1600 | (b) 1700 | (c) 1800 | (d) 1900


Ans / āωāĻ¤ā§āϤ⧰: (c) 1800


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


Formula / āϏ⧂āĻ¤ā§ā§°:  Average = Total Marks ÷ Number of Students (āĻ—āĻĄāĻŧ = āĻŽā§āĻ  āύāĻŽā§āĻŦā§° ÷ āĻļāĻŋāĻ•ā§āώāĻžā§°ā§āĻĨ⧀⧰ āϏāĻ‚āĻ–ā§āϝāĻž)


Therefore / āϏ⧇āϝāĻŧ⧇āĻšā§‡, Total Marks = Average × Number of Students (āĻŽā§āĻ  āύāĻŽā§āĻŦā§° = āĻ—āĻĄāĻŧ × āĻļāĻŋāĻ•ā§āώāĻžā§°ā§āĻĨ⧀⧰ āϏāĻ‚āĻ–ā§āϝāĻž)


=1800


Total Marks / āĻŽā§āĻ  āύāĻŽā§āĻŦā§° = 1800


Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ


Average × Number = Total (āĻ—āĻĄāĻŧ × āϏāĻ‚āĻ–ā§āϝāĻž = āĻŽā§āĻ )


45 × 40 = 45 × 4 × 10 = 180 × 10 = 


Ans = 1800


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Q. What is the value of 2.75 × 0.4 ? (2.75 × 0.4-ā§° āĻŽāĻžāύ āĻ•āĻŋāĻŽāĻžāύ ?)


(a) 1.10 | (b) 1.00 | (c) 1.01 | (d) 1.20


Ans / āωāĻ¤ā§āϤ⧰: (a) 1.10


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


2.75 × 0.4 = 275 /100 × 4 / 10 = 1100 / 1000 = 


Therefore / āϏ⧇āϝāĻŧ⧇āĻšā§‡, 2.75 × 0.4 = 1.10


Ans / āωāĻ¤ā§āϤ⧰: (a) 1.10


Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ


Ignore the decimal points first. / āĻĒā§ā§°āĻĨāĻŽā§‡ āĻĻāĻļāĻŽāĻŋāĻ• āϚāĻŋāĻšā§āύ āωāĻĒ⧇āĻ•ā§āώāĻž āϕ⧰āĻ•āĨ¤


275 × 4 = 1100


Now count decimal places: i. 2.75 → 2 decimal places, ii. 0.4 → 1 decimal place


Total = 3 decimal places


1100 → 1.100


Ans = 1.10


Tip


Multiply first, place decimal later. (āφāĻ—āϤ⧇ āϗ⧁āĻŖ āϕ⧰āĻ•, āĻĒāĻŋāĻ›āϤ āĻĻāĻļāĻŽāĻŋāĻ• āĻŦāĻšā§ā§ąāĻžāĻ“āĻ•āĨ¤)


275 × 4 = 1100


3 decimal places ⇒ 1.100 = 1.10


Ans / āωāĻ¤ā§āϤ⧰: (a) 1.10.


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Q. An article is sold for ₹800 at a loss of 20%. What is its Cost Price (CP) ? (āϕ⧋āύ⧋ āĻŦāĻ¸ā§āϤ⧁ ₹800 āϟāĻ•āĻžāϤ āĻŦāĻŋāĻ•ā§ā§°ā§€ āϕ⧰āĻŋāϞ⧇ 20% āĻ•ā§āώāϤāĻŋ āĻšāϝāĻŧāĨ¤ āχāϝāĻŧāĻžā§° āĻ•ā§ā§°āϝāĻŧ āĻŽā§‚āĻ˛ā§āϝ (CP) āĻ•āĻŋāĻŽāĻžāύ ?)


(a) ₹960 | (b) ₹1000 | (c) ₹1020 | (d) ₹1120


Ans / āωāĻ¤ā§āϤ⧰: (b) ₹1000


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


Loss = 20%


So, Selling Price (SP) = 80% of Cost Price (CP)


SP = 80% of CP 


800 = 80/100 × CP


CP = 800 × 100 / 80


CP = 1000


Cost Price (āĻ•ā§ā§°āϝāĻŧ āĻŽā§‚āĻ˛ā§āϝ) = ₹1000


Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ


20% Loss ⇒ SP = 80% of CP


CP = SP × 100 / 80  = 800 × 100 / 80 =


Ans = ₹1000


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Q. A person travels at a speed of 60 km/h for 3 hours. What distance does he cover ? (āĻāϜāύ āĻŦā§āϝāĻ•ā§āϤāĻŋāϝāĻŧ⧇ 60 āĻ•āĻŋāĻŽāĻŋ/āϘāĻŖā§āϟāĻž āĻŦ⧇āĻ—āϤ 3 āϘāĻŖā§āϟāĻž āĻ­ā§ā§°āĻŽāĻŖ āϕ⧰⧇āĨ¤ āϤ⧇āĻ“āρ āĻ•āĻŋāĻŽāĻžāύ āĻĻā§‚ā§°āĻ¤ā§āĻŦ āĻ…āϤāĻŋāĻ•ā§ā§°āĻŽ āϕ⧰⧇ ?)


(a) 150 km | (b) 160 km | (c) 170 km | (d) 180 km


Ans / āωāĻ¤ā§āϤ⧰: (d) 180 km


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


Formula / āϏ⧂āĻ¤ā§ā§°: Distance = Speed × Time = 60 × 3 = 1


Therefore / āϏ⧇āϝāĻŧ⧇āĻšā§‡, Distance = 180 km (āĻĻā§‚ā§°āĻ¤ā§āĻŦ = 180 āĻ•āĻŋāĻŽāĻŋ)


Ans / āωāĻ¤ā§āϤ⧰: (d) 180 km


Shortcut Trick / āĻĻā§ā§°ā§āϤ āĻ•ā§ŒāĻļāϞ


Distance = Speed × Time (āĻĻā§‚ā§°āĻ¤ā§āĻŦ = āĻŦ⧇āĻ— × āϏāĻŽāϝāĻŧ)


60 × 3 = 180


Ans = 180 km


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Q. The radius of a circle is 7 cm. What is its area (π = 22/7) āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 7 āĻšā§‡āĻŽāĻŋāĨ¤ āχāϝāĻŧāĻžā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ āĻ•āĻŋāĻŽāĻžāύ? (π = 22/7) 






(a) 132 cm² | (b) 154 cm² | (c) 176 cm² | (d) 196 cm²


Ans / āωāĻ¤ā§āϤ⧰: (b) 154 cm²


Explanation: / āĻŦā§āϝāĻžāĻ–ā§āϝāĻž:


Formula / āϏ⧂āĻ¤ā§ā§°:


Area of Circle = πr2 = 22/7 × 7 × 7 = 22 × 7 = 154


Therefore / āϏ⧇āϝāĻŧ⧇āĻšā§‡, Area = 154 cm² (āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ = 154 āĻŦā§°ā§āĻ— āĻšā§‡āĻŽāĻŋ)


Ans / āωāĻ¤ā§āϤ⧰: (b) 154 cm²


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Practice Set






10. Time and Work / āϏāĻŽāϝāĻŧ āφ⧰⧁ āĻ•āĻžāĻŽ


Q. A can complete a work in 15 days and B can complete the same work in 20 days. In how many days will they complete the work together ? (āĻĒā§ā§°āĻļā§āύ: A-āĻ āĻāϟāĻž āĻ•āĻžāĻŽ 15 āĻĻāĻŋāύāϤ āφ⧰⧁ B-āĻ āĻāϕ⧇ āĻ•āĻžāĻŽ 20 āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§‚ā§°ā§āĻŖ āϕ⧰āĻŋāĻŦ āĻĒāĻžā§°ā§‡āĨ¤ āĻĻ⧁āϝāĻŧā§‹āϜāύ⧇ āĻāϕ⧇āϞāϗ⧇ āĻ•āĻžāĻŽāĻŸā§‹ āĻ•āĻŋāĻŽāĻžāύ āĻĻāĻŋāύāϤ āϏāĻŽā§āĻĒā§‚ā§°ā§āĻŖ āϕ⧰āĻŋāĻŦ ?)


(a) 8 days / āĻĻāĻŋāύ | (b) 10 days / āĻĻāĻŋāύ | (c) 12 days / āĻĻāĻŋāύ | (d) 15 days / āĻĻāĻŋāύ


Trick:  Together Time (āĻāϕ⧇āϞāϗ⧇ āϏāĻŽāϝāĻŧ) = (A × B) ÷ (A + B)


11. Average / āĻ—āĻĄāĻŧ


Q. The average marks of 40 students in a class is 45. Find the total marks. (āĻĒā§ā§°āĻļā§āύ: āĻāϟāĻž āĻļā§ā§°ā§‡āϪ⧀⧰ 40 āϜāύ āĻļāĻŋāĻ•ā§āώāĻžā§°ā§āĻĨ⧀⧰ āĻ—āĻĄāĻŧ āύāĻŽā§āĻŦā§° 45āĨ¤ āĻŽā§āĻ  āύāĻŽā§āĻŦā§° āύāĻŋā§°ā§āĻŖāϝāĻŧ āϕ⧰āĻ•āĨ¤)


(a) 1600 | (b) 1700 | (c) 1800 | (d) 1900


Trick: Total Marks = Average × Number of Students (āĻŽā§āĻ  āύāĻŽā§āĻŦā§° = āĻ—āĻĄāĻŧ × āĻļāĻŋāĻ•ā§āώāĻžā§°ā§āĻĨ⧀⧰ āϏāĻ‚āĻ–ā§āϝāĻž)


12. Mensuration (2D) / āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻŽāĻŋāϤāĻŋ (2D)


Q. The radius of a circle is 7 cm. What is its area ? (π = 22/7)  āĻĒā§ā§°āĻļā§āύ: āĻāϟāĻž āĻŦ⧃āĻ¤ā§āϤ⧰ āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 7 āĻšā§‡āĻŽāĻŋāĨ¤ āχāϝāĻŧāĻžā§° āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ āĻ•āĻŋāĻŽāĻžāύ ? (π = 22/7)


(a) 132 cm² | (b) 154 cm² | (c) 176 cm² | (d) 196 cm²


Trick: Area of Circle = πr² (āĻŦ⧃āĻ¤ā§āϤ⧰ āĻ•ā§āώ⧇āĻ¤ā§ā§°āĻĢāϞ = πr²)


13. Time, Distance and Speed / āϏāĻŽāϝāĻŧ, āĻĻā§‚ā§°āĻ¤ā§āĻŦ āφ⧰⧁ āĻŦ⧇āĻ—


Q. A person travels at a speed of 60 km/h for 3 hours. What distance does he cover ? (āĻĒā§ā§°āĻļā§āύ: āĻāϜāύ āĻŦā§āϝāĻ•ā§āϤāĻŋāϝāĻŧ⧇ 60 āĻ•āĻŋāĻŽāĻŋ/āϘāĻŖā§āϟāĻž āĻŦ⧇āĻ—āϤ 3 āϘāĻŖā§āϟāĻž āϚāϞ⧇āĨ¤ āϤ⧇āĻ“āρ āĻ•āĻŋāĻŽāĻžāύ āĻĻā§‚ā§°āĻ¤ā§āĻŦ āĻ…āϤāĻŋāĻ•ā§ā§°āĻŽ āϕ⧰⧇ ?)


(a) 150 km | (b) 160 km | (c) 170 km | (d) 180 km