Competive Exam Math 3
Q. A Qatar Airways Airbus A380 landed at London Heathrow Airport at precisely 1:10 A.M., having flown for 16 hours 25 minutes from Doha. What was the departure time of the aircraft ? (Qatar Airways-ā§° āĻāĻāĻž Airbus A380 āĻŦāĻŋāĻŽāĻžāĻ¨ā§ Doha-ā§° āĻĒā§°āĻž ā§§ā§Ŧ āĻāĻŖā§āĻāĻž ā§¨ā§Ģ āĻŽāĻŋāĻ¨āĻŋāĻ āĻā§°āĻŋ āĻ āĻŋāĻ 1:10 A.M.-āĻ¤ London Heathrow Airport-āĻ¤ āĻ ā§ąāĻ¤ā§°āĻŖ āĻā§°āĻŋāĻ˛ā§āĨ¤ āĻŦāĻŋāĻŽāĻžāĻ¨āĻāĻ¨ āĻā§āĻ¤āĻŋāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¤ā§ā§°āĻž āĻā§°āĻŽā§āĻ āĻā§°āĻŋāĻāĻŋāĻ˛ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 06:45 P.M. B. 08:45 P.M. C. 06:35 P.M. D. 07:45 P.M.
SolnArrival Time (āĻĒā§āĻāĻāĻžā§° āĻ¸āĻŽāĻ¯āĻŧ) = 1:10 A.M.
Subtract 25 minutes (ā§¨ā§Ģ āĻŽāĻŋāĻ¨āĻŋāĻ āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°āĻ) from Arrival Time (āĻĒā§āĻāĻāĻžā§° āĻ¸āĻŽāĻ¯āĻŧ) = 1:10 A.M. − 25 min = 12:45 A.M. (ā§§:ā§§ā§Ļ A.M. − ā§¨ā§Ģ āĻŽāĻŋāĻ¨āĻŋāĻ = ā§§ā§¨:ā§Ēā§Ģ A.M.)
Now subtract 16 hours (āĻāĻ¤āĻŋāĻ¯āĻŧāĻž ā§§ā§Ŧ āĻāĻŖā§āĻāĻž āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°āĻ)
- 12:45 A.M. − 12 hr = 12:45 P.M. (Previous Day)
- 12:45 P.M. − 4 hr = 8:45 P.M. (Previous Day)
Ans (āĻāĻ¤ā§āĻ¤ā§°) : Departure Time = 08:45 P.M. (Previous Day) (āĻ¯āĻžāĻ¤ā§ā§°āĻž āĻā§°āĻŽā§āĻ āĻā§°āĻžā§° āĻ¸āĻŽāĻ¯āĻŧ = āĻāĻāĻĻāĻŋāĻ¨āĻž āĻ¸āĻ¨ā§āĻ§āĻŋāĻ¯āĻŧāĻž 8:45 āĻŦāĻāĻžāĻ¤)
Easy Exam Tip - āĻ¸āĻšāĻ āĻĒā§°ā§āĻā§āĻˇāĻžā§° āĻāĻŋāĻĒāĻā§: First subtract the minutes, then subtract the hours. (āĻāĻāĻ¤ā§ āĻŽāĻŋāĻ¨āĻŋāĻ āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°āĻ, āĻ¤āĻžā§° āĻĒāĻŋāĻāĻ¤ āĻāĻŖā§āĻāĻž āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°āĻāĨ¤) This avoids the confusing 24:70 method and is much easier to remember in exams.
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Q. What is the greatest number (H.C.F.) that can divide 14, 20, and 29, leaving a remainder of 2 in each case ? (ā§§ā§Ē, ā§¨ā§Ļ āĻā§°ā§ ā§¨ā§¯-āĻ ā§¨ āĻ ā§ąāĻļāĻŋāĻˇā§āĻ ā§°āĻžāĻāĻŋ āĻāĻžāĻ āĻā§°āĻŋāĻŦ āĻĒā§°āĻž āĻ¸ā§°ā§āĻŦāĻŦā§āĻšā§ āĻ¸āĻāĻā§āĻ¯āĻž (H.C.F.) āĻāĻŋāĻŽāĻžāĻ¨ ?) Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A) 3 B) 2 C) 5 D) 7
Soln
If the remainder is the same, subtract the remainder from each number and find the H.C.F. (āĻ¯āĻĻāĻŋ āĻ¸āĻāĻ˛ā§ āĻ¸āĻāĻā§āĻ¯āĻžāĻ¤ āĻāĻā§ āĻ ā§ąāĻļāĻŋāĻˇā§āĻ āĻĨāĻžāĻā§, āĻ¤ā§āĻ¨ā§āĻ¤ā§ āĻĒā§ā§°āĻ¤āĻŋāĻā§ āĻ¸āĻāĻā§āĻ¯āĻžā§° āĻĒā§°āĻž āĻ ā§ąāĻļāĻŋāĻˇā§āĻ āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°āĻŋ H.C.F. āĻāĻ˛āĻŋāĻ¯āĻŧāĻžāĻāĻāĨ¤)
Since the remainder is 2, subtract 2 from each number. (āĻ¯āĻŋāĻšā§āĻ¤ā§ āĻ ā§ąāĻļāĻŋāĻˇā§āĻ ā§¨, āĻ¸ā§āĻ¯āĻŧā§ āĻĒā§ā§°āĻ¤āĻŋāĻā§ āĻ¸āĻāĻā§āĻ¯āĻžā§° āĻĒā§°āĻž ā§¨ āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°ā§āĻāĨ¤)
- 14 − 2 = 12
- 20 − 2 = 18
- 29 − 2 = 27
Now find the H.C.F. of 12, 18, and 27. (āĻāĻ¤āĻŋāĻ¯āĻŧāĻž ā§§ā§¨, ā§§ā§Ž āĻā§°ā§ ā§¨ā§-ā§° H.C.F. āĻāĻ˛āĻŋāĻ¯āĻŧāĻžāĻāĻāĨ¤)
- Factors of 12 = 1, 2, 3, 4, 6, 12
- Factors of 18 = 1, 2, 3, 6, 9, 18
- Factors of 27 = 1, 3, 9, 27
The greatest common factor is 3. (āĻ¸āĻāĻ˛ā§ā§°ā§ āĻ¸ā§°ā§āĻŦāĻŦā§āĻšā§ āĻ¸āĻžāĻ§āĻžā§°āĻŖ āĻā§āĻŖāĻ¨ā§āĻ¯āĻŧāĻ = 3)
Ans: A. 3
Shortcut Trick (Exam Method)
Same Remainder ⇒ Subtract the Remainder ⇒ Find H.C.F.(āĻāĻā§ āĻ ā§ąāĻļāĻŋāĻˇā§āĻ ⇒ āĻ ā§ąāĻļāĻŋāĻˇā§āĻ āĻŦāĻŋāĻ¯āĻŧā§āĻ āĻā§°āĻ ⇒ H.C.F. āĻāĻ˛āĻŋāĻ¯āĻŧāĻžāĻāĻ)
14, 20, 29 (-2 Subtract the Remainder) 12, 18, 27, H.C.F. = 3 (The greatest common factor is 3. āĻ¸āĻāĻ˛ā§ā§°ā§ āĻ¸ā§°ā§āĻŦāĻŦā§āĻšā§ āĻ¸āĻžāĻ§āĻžā§°āĻŖ āĻā§āĻŖāĻ¨ā§āĻ¯āĻŧāĻ = 3)
Ans = 3
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Q. The difference between the largest five-digit number and the smallest three-digit number is: (āĻ¸ā§°ā§āĻŦāĻŦā§āĻšā§ āĻĒāĻžāĻāĻ āĻ āĻāĻā§° āĻ¸āĻāĻā§āĻ¯āĻž āĻā§°ā§ āĻ¸ā§°ā§āĻŦāĻ¸ā§°ā§ āĻ¤āĻŋāĻ¨āĻŋāĻ āĻāĻā§° āĻ¸āĻāĻā§āĻ¯āĻžā§° āĻĒāĻžā§°ā§āĻĨāĻā§āĻ¯ āĻāĻŋāĻŽāĻžāĻ¨ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 98999 B. 99899 C. 90989 D. 99888
Shortcut Trick (Exam Method)
- Largest 5-digit number = 99,999
- Smallest 3-digit number = 100
99,999 − 100 = 99,899
Ans = 99,899
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Q. The time is exactly 10:00 A.M. What will be the time when the hour hand rotates through an angle of 450° ? (āĻ¸āĻŽāĻ¯āĻŧ āĻ āĻŋāĻ 10:00 A.M.āĨ¤ āĻāĻŖā§āĻāĻžā§° āĻāĻžāĻāĻāĻŋāĻ¯āĻŧā§ 450° āĻā§āĻŖ āĻ āĻ¤āĻŋāĻā§ā§°āĻŽ āĻā§°āĻŋāĻ˛ā§ āĻ¸āĻŽāĻ¯āĻŧ āĻāĻŋāĻŽāĻžāĻ¨ āĻš'āĻŦ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 11:00 A.M. B. 1:00 A.M. C. 4:00 P.M. D. 9:00 A.M.
Soln
Fact (āĻŽāĻ¨āĻ¤ ā§°āĻžāĻāĻ): Hour hand rotates 30° in 1 hour. (āĻāĻŖā§āĻāĻžā§° āĻāĻžāĻāĻāĻŋāĻ¯āĻŧā§ ā§§ āĻāĻŖā§āĻāĻžāĻ¤ 30° āĻā§ā§°ā§āĨ¤)
1st: Find the time taken for 450°: 450â ÷ 30â = 15 hours (15 hours 450° āĻā§ā§°āĻŋāĻŦāĻ˛ā§ 15 āĻāĻŖā§āĻāĻž āĻ˛āĻžāĻā§āĨ¤)
2nd: Add 15 hours to 10:00 A.M. : 10:00 A.M.+15 hours = 1:00 A.M. (Next Day) (10:00 A.M. + 15 āĻāĻŖā§āĻāĻž = āĻĒāĻŋāĻāĻĻāĻŋāĻ¨āĻž 1:00 A.M.)
Ans: B. 1:00 A.M.
Shortcut Trick (Exam Method)
Hour Hand (āĻāĻŖā§āĻāĻžā§° āĻāĻžāĻāĻāĻž) : 30° = 1 hour
Q. The last month of the first quarter of the year and the first two months of the third quarter of the year have how many days in total ?(āĻŦāĻā§°ā§° āĻĒā§ā§°āĻĨāĻŽ āĻ¤ā§ā§°ā§āĻŽāĻžāĻ¸āĻŋāĻā§° āĻļā§āĻˇā§° āĻŽāĻžāĻš āĻā§°ā§ āĻ¤ā§āĻ¤ā§āĻ¯āĻŧ āĻ¤ā§ā§°ā§āĻŽāĻžāĻ¸āĻŋāĻā§° āĻĒā§ā§°āĻĨāĻŽ āĻĻā§āĻāĻž āĻŽāĻžāĻšāĻ¤ āĻŽā§āĻ āĻāĻŋāĻŽāĻžāĻ¨ āĻĻāĻŋāĻ¨ āĻĨāĻžāĻā§ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 92 B. 91 C. 93 D. 90
Soln
1st: First Quarter (āĻĒā§ā§°āĻĨāĻŽ āĻ¤ā§ā§°ā§āĻŽāĻžāĻ¸āĻŋāĻ)
First Quarter = January, February, March (āĻĒā§ā§°āĻĨāĻŽ āĻ¤ā§ā§°ā§āĻŽāĻžāĻ¸āĻŋāĻ = āĻāĻžāĻ¨ā§ā§ąāĻžā§°ā§, āĻĢā§āĻŦā§ā§°ā§ā§ąāĻžā§°ā§, āĻŽāĻžā§°ā§āĻ)
Last month = March = 31 days (āĻļā§āĻˇā§° āĻŽāĻžāĻš = āĻŽāĻžā§°ā§āĻ = 31 āĻĻāĻŋāĻ¨)
2nd: Third Quarter (āĻ¤ā§āĻ¤ā§āĻ¯āĻŧ āĻ¤ā§ā§°ā§āĻŽāĻžāĻ¸āĻŋāĻ)
Third Quarter = July, August, September (āĻ¤ā§āĻ¤ā§āĻ¯āĻŧ āĻ¤ā§ā§°ā§āĻŽāĻžāĻ¸āĻŋāĻ = āĻā§āĻ˛āĻžāĻ, āĻāĻāĻˇā§āĻ, āĻā§āĻĒā§āĻā§āĻŽā§āĻŦā§°)
First two months = July + August (āĻĒā§ā§°āĻĨāĻŽ āĻĻā§āĻāĻž āĻŽāĻžāĻš = āĻā§āĻ˛āĻžāĻ (31) + āĻāĻāĻˇā§āĻ (31)
- July = 31 days
- August = 31 days
3rd: Total Days (āĻŽā§āĻ āĻĻāĻŋāĻ¨) : 31 + 31 + 31 = 93 days
Ans: C. 93 days
Shortcut Trick (Exam Method)
- Last month of 1st Quarter = March = 31
- First two months of 3rd Quarter = July + August = 31 + 31
3rd: Total Days (āĻŽā§āĻ āĻĻāĻŋāĻ¨) : 31 + 31 + 31 = 93 days
Ans = C. 93 days
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Q. The average height of a barometer during one week was 30.84 inches. For the first 6 days of the same week, the average height was 30.18 inches. What was the height on Sunday ? (āĻāĻāĻž āĻ¸āĻĒā§āĻ¤āĻžāĻšāĻ¤ āĻŦā§ā§°ā§āĻŽāĻŋāĻāĻžā§°ā§° āĻāĻĄāĻŧ āĻāĻā§āĻāĻ¤āĻž 30.84 āĻāĻā§āĻāĻŋ āĻāĻāĻŋāĻ˛āĨ¤ āĻ¸ā§āĻ āĻ¸āĻĒā§āĻ¤āĻžāĻšā§° āĻĒā§ā§°āĻĨāĻŽ 6 āĻĻāĻŋāĻ¨ā§° āĻāĻĄāĻŧ āĻāĻā§āĻāĻ¤āĻž 30.18 āĻāĻā§āĻāĻŋ āĻāĻāĻŋāĻ˛āĨ¤ āĻ¤ā§āĻ¨ā§āĻ¤ā§ ā§°āĻŦāĻŋāĻŦāĻžā§°ā§ āĻŦā§ā§°ā§āĻŽāĻŋāĻāĻžā§°ā§° āĻāĻā§āĻāĻ¤āĻž āĻāĻŋāĻŽāĻžāĻ¨ āĻāĻāĻŋāĻ˛ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 32.80 inches B. 34.20 inches C. 34.80 inches D. 33.10 inches
Soln
Average × Number of Days = Total (āĻāĻĄāĻŧ × āĻĻāĻŋāĻ¨ā§° āĻ¸āĻāĻā§āĻ¯āĻž = āĻŽā§āĻ )
1st: Total for 7 days (ā§ āĻĻāĻŋāĻ¨ā§° āĻŽā§āĻ ) : 30.84 × 7 = 215.88 inches
2nd: Total for first 6 days (āĻĒā§ā§°āĻĨāĻŽ ā§Ŧ āĻĻāĻŋāĻ¨ā§° āĻŽā§āĻ ) : 30.18 × 6 = 181.08 inches
3rd: Sunday's height (ā§°āĻŦāĻŋāĻŦāĻžā§°ā§° āĻāĻā§āĻāĻ¤āĻž) : 215.88 − 181.08 = 34.80 inches
Ans: C. 34.80 inches
Easy Trick (Exam Shortcut)
Formulla (āĻ¸ā§āĻ¤ā§ā§°): Missing Value = (Overall Average × Total Items) − (Known Average × Known Items)
(30.84 × 7) − (30.18 × 6) = 215.88 - 181.08 = 34.80
Ans = 34.80 inches
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Q. Jones is now twice as old as he was 5 years ago, and his mother is now 4 times as old as Jones. How old is his mother ? (āĻ'āĻ¨ā§āĻ¸ā§° āĻŦā§°ā§āĻ¤āĻŽāĻžāĻ¨ āĻŦāĻ¯āĻŧāĻ¸ ā§Ģ āĻŦāĻā§°ā§° āĻāĻā§° āĻŦāĻ¯āĻŧāĻ¸ā§° āĻĻā§āĻā§āĻŖāĨ¤ āĻŦā§°ā§āĻ¤āĻŽāĻžāĻ¨ āĻ¤ā§āĻāĻā§° āĻŽāĻžāĻā§° āĻŦāĻ¯āĻŧāĻ¸ āĻ'āĻ¨ā§āĻ¸ā§° āĻŦāĻ¯āĻŧāĻ¸ā§° ā§Ē āĻā§āĻŖāĨ¤ āĻ¤ā§āĻ¨ā§āĻ¤ā§ āĻ¤ā§āĻāĻā§° āĻŽāĻžāĻā§° āĻŦāĻ¯āĻŧāĻ¸ āĻāĻŋāĻŽāĻžāĻ¨ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 80 years B. 72 years C. 120 years D. 40 years
Soln
Let Jones' present age = x years (āĻ§ā§°āĻŋ āĻ˛āĻāĻ, āĻ'āĻ¨ā§āĻ¸ā§° āĻŦā§°ā§āĻ¤āĻŽāĻžāĻ¨ āĻŦāĻ¯āĻŧāĻ¸ = x āĻŦāĻā§°)
According to the question:
x = 2(x - 5) = 2x - 10
2x - x - 10
x = 10
So, Jones' present age = 10 years (āĻ'āĻ¨ā§āĻ¸ā§° āĻŦā§°ā§āĻ¤āĻŽāĻžāĻ¨ āĻŦāĻ¯āĻŧāĻ¸ = ā§§ā§Ļ āĻŦāĻā§°)
Mother's age: 4×10 = 40 years (āĻŽāĻžāĻā§° āĻŦāĻ¯āĻŧāĻ¸ = ā§Ē × ā§§ā§Ļ = ā§Ēā§Ļ āĻŦāĻā§°)
Easy Trick (Exam Shortcut)
Jones = Twice of (5 years ago)
x = 2(x−5)
x = 10
Mother = 4 × Jones = 4 × 10 = 40
Ans = 40 years
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Q. A salesman's commission increases by 20% and then decreases by 10% due to poor sales. What is the overall change in his commission ?āĻāĻāĻ¨ āĻŦāĻŋāĻā§ā§°ā§āĻ¤āĻžā§° āĻāĻŽāĻŋāĻāĻ¨ āĻĒā§ā§°āĻĨāĻŽā§ ā§¨ā§Ļ% āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒāĻžāĻ¯āĻŧ āĻā§°ā§ āĻĒāĻŋāĻāĻ¤ āĻŦāĻŋāĻā§ā§°ā§ āĻāĻŽ āĻšā§ā§ąāĻžā§° āĻŦāĻžāĻŦā§ ā§§ā§Ļ% āĻšā§ā§°āĻžāĻ¸ āĻĒāĻžāĻ¯āĻŧāĨ¤ āĻ¤ā§āĻ¨ā§āĻ¤ā§ āĻāĻŽāĻŋāĻāĻ¨āĻ¤ āĻŽā§āĻ āĻāĻŋāĻŽāĻžāĻ¨ āĻļāĻ¤āĻžāĻāĻļ āĻĒā§°āĻŋāĻŦā§°ā§āĻ¤āĻ¨ āĻš'āĻ˛ ?
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 10% Increase B. 10% Decrease C. 8% Decrease D. 8% Increase
Soln
Assume the original commission = 100. (āĻ§ā§°āĻŋ āĻ˛āĻāĻ, āĻā§°āĻŽā§āĻāĻŖāĻŋā§° āĻāĻŽāĻŋāĻāĻ¨ = 100)
1st: Increase by 20%
100 + 20% = 120
2nd: Decrease by 10% = 120 × 90% = 120 × 0.90 = 108
3rd: Overall Change : 108−100=8108 - 100 = 8108−100=8
So, the commission increased by 8%. (āĻ ā§°ā§āĻĨāĻžā§ āĻāĻŽāĻŋāĻāĻ¨ ā§Ž% āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒāĻžāĻ˛ā§āĨ¤)
Ans: D. 8% Increase
Easy Trick (Exam Shortcut)
Original Commission = 100 → +20% = 120 → −10% = 108 → Overall Change = +8% (āĻā§°āĻŽā§āĻāĻŖāĻŋā§° āĻāĻŽāĻŋāĻāĻ¨ = 100 → ā§¨ā§Ļ% āĻŦā§āĻĻā§āĻ§āĻŋ = 120 → ā§§ā§Ļ% āĻšā§ā§°āĻžāĻ¸ = 108 → āĻŽā§āĻ āĻĒā§°āĻŋāĻŦā§°ā§āĻ¤āĻ¨ = +8%)
Ans: D. 8% Increase
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Q. A container half full contains 450 litres of water. What percentage more water is required to make the container completely full ? (āĻāĻāĻž āĻĒāĻžāĻ¤ā§ā§° āĻāĻ§āĻž āĻā§°ā§āĻ¤āĻŋ āĻ ā§ąāĻ¸ā§āĻĨāĻžāĻ¤ 450 āĻ˛āĻŋāĻāĻžā§° āĻĒāĻžāĻ¨ā§ āĻāĻā§āĨ¤ āĻĒāĻžāĻ¤ā§ā§°āĻā§ āĻ¸āĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§°ā§āĻ¤āĻŋ āĻā§°āĻŋāĻŦāĻ˛ā§ āĻā§°ā§ āĻāĻŋāĻŽāĻžāĻ¨ āĻļāĻ¤āĻžāĻāĻļ āĻĒāĻžāĻ¨ā§ āĻĒā§ā§°āĻ¯āĻŧā§āĻāĻ¨ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 100% B. 50% C. 25% D. 75%
Soln
Half-full water = 450 litres (āĻāĻ§āĻž āĻā§°ā§āĻ¤āĻŋ = 450 āĻ˛āĻŋāĻāĻžā§°)
So,
Full capacity = 450 × 2 = 900 litres (āĻ¸āĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§āĻˇāĻŽāĻ¤āĻž = 900 āĻ˛āĻŋāĻāĻžā§°)
More water required: 900 − 450 = 450 litres
Percentage more required: 450 / 450 × 100 = 100%
āĻ ā§°ā§āĻĨāĻžā§, āĻŦā§°ā§āĻ¤āĻŽāĻžāĻ¨ āĻĨāĻāĻž āĻĒāĻžāĻ¨ā§ā§° āĻ¸āĻŽāĻžāĻ¨ (100%) āĻĒāĻžāĻ¨ā§ āĻā§°ā§ āĻ˛āĻžāĻāĻŋāĻŦāĨ¤
Ans: A. 100%
Easy Trick (Exam Shortcut)
Half = 450 L → Full = 900 L → More Needed = 450 L → (450 ÷ 450) × 100 = 100% (āĻāĻ§āĻž = 450 L → āĻ¸āĻŽā§āĻĒā§ā§°ā§āĻŖ = 900 L → āĻā§°ā§ āĻ˛āĻžāĻā§ = 450 L → 100%)
Ans = A. 100%
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Q. A delivery van maintains an average speed of 24 km/h for the first three hours of its journey. How far did it travel in the first 2 hours 15 minutes ? (āĻāĻāĻž āĻĄā§āĻ˛āĻŋāĻāĻžā§°ā§ āĻā§āĻ¨ā§ āĻ¯āĻžāĻ¤ā§ā§°āĻžā§° āĻĒā§ā§°āĻĨāĻŽ ā§Š āĻāĻŖā§āĻāĻžāĻ¤ āĻāĻĄāĻŧ āĻŦā§āĻ 24 km/h āĻŦāĻāĻžāĻ ā§°āĻžāĻā§āĨ¤ āĻĒā§ā§°āĻĨāĻŽ 2 āĻāĻŖā§āĻāĻž 15 āĻŽāĻŋāĻ¨āĻŋāĻāĻ¤ āĻā§āĻ¨āĻāĻ¨ā§ āĻāĻŋāĻŽāĻžāĻ¨ āĻĻā§ā§°āĻ¤ā§āĻŦ āĻ āĻ¤āĻŋāĻā§ā§°āĻŽ āĻā§°āĻŋāĻ˛ā§ ?)
Options / āĻŦāĻŋāĻāĻ˛ā§āĻĒāĻ¸āĻŽā§āĻš: A. 54 km B. 60 km C. 48 km D. 72 km
Soln
Time = 2 hours 15 minutes (āĻ¸āĻŽāĻ¯āĻŧ = ā§¨ āĻāĻŖā§āĻāĻž ā§§ā§Ģ āĻŽāĻŋāĻ¨āĻŋāĻ)
Convert minutes into hours: 15 minutes = 15/60 = 0.25 hour
So, 2 hours 15 minutes = 2.25 hours
Use the formula : Distance = Speed × Time (āĻĻā§ā§°āĻ¤ā§āĻŦ = āĻŦā§āĻ × āĻ¸āĻŽāĻ¯āĻŧ)
= 24 × 2.25 = 54 km
Ans: A. 54 km
Easy Trick (Exam Shortcut)
2 h 15 min = 2.25 h → Distance = 24 × 2.25 = 54 km (ā§¨ āĻāĻŖā§āĻāĻž ā§§ā§Ģ āĻŽāĻŋāĻ¨āĻŋāĻ = ā§¨.ā§¨ā§Ģ āĻāĻŖā§āĻāĻž → āĻĻā§ā§°āĻ¤ā§āĻŦ = ā§¨ā§Ē × ā§¨.ā§¨ā§Ģ = ā§Ģā§Ē āĻāĻŋāĻŽāĻŋ)
Ans = A. 54 km
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Practice Set
1. Flight Time (Departure Time)
Q1. A flight lands at 6:20 A.M. after flying for 8 hours 35 minutes. What was the departure time ?
A. 9:45 P.M. B. 10:15 P.M. C. 9:55 P.M. D. 10:45 P.M.
Q2. A flight lands at 3:40 P.M. after flying for 5 hours 20 minutes. What was the departure time ?
A. 10:20 A.M. B. 10:40 A.M. C. 9:20 A.M. D. 11:20 A.M.
Q3. A flight lands at 12:15 A.M. after flying for 10 hours 45 minutes. What was the departure time ?
A. 1:30 P.M. B. 2:30 P.M. C. 1:45 P.M. D. 2:15 P.M.
2. H.C.F. (Same Remainder)
Q1. What is the H.C.F. that leaves a remainder 3 when dividing 18, 33 and 48 ?
A. 3 B. 5 C. 15 D. 9
Q2. What is the H.C.F. that leaves a remainder 4 when dividing 28, 40 and 52 ?
A. 8 B. 12 C. 6 D. 4
Q3. What is the H.C.F. that leaves a remainder 5 when dividing 35, 50 and 65 ?
A. 10 B. 15 C. 5 D. 20
3. Greatest & Smallest Numbers
Q1. Difference between the largest 4-digit and the smallest 2-digit number.
A. 9989 B. 9988 C. 9990 D. 9899
Q2. Difference between the largest 6-digit and the smallest 5-digit number.
A. 899999 B. 900000 C. 989999 D. 899998
Q3. Difference between the largest 5-digit and the smallest 4-digit number.
A. 90000 B. 89999 C. 90999 D. 89000
4. Clock (Hour Hand)
Q1. At 2:00 A.M., the hour hand rotates 90°. What is the time ?
A. 5:00 A.M. B. 4:00 A.M. C. 3:00 A.M. D. 6:00 A.M.
Q2. At 6:00 A.M., the hour hand rotates 180°. What is the time ?
A. 12:00 Noon B. 11:00 A.M. C. 10:00 A.M. D. 1:00 P.M.
Q3. At 4:00 P.M., the hour hand rotates 120°. What is the time ?
A. 7:00 P.M. B. 8:00 P.M. C. 6:00 P.M. D. 9:00 P.M.
5. Quarter & Months
Q1. First month of the 2nd quarter and last month of the 4th quarter together have how many days?
A. 60 B. 61 C. 62 D. 63
Q2. All the months of the 1st quarter together have how many days?
A. 90 B. 91 C. 92 D. 93
Q3. First month of the 3rd quarter and last month of the 1st quarter together have how many days?
A. 60 B. 61 C. 62 D. 63
6. Average
Q1. Average of 5 days = 18. First 4 days average = 16. Find the 5th day's value.
A. 26 B. 24 C. 20 D. 22
Q2. Average of 8 days = 22. First 7 days average = 20. Find the 8th day's value.
A. 34 B. 36 C. 38 D. 40
Q3. Average of 4 numbers = 25. First 3 numbers average = 20. Find the 4th number.
A. 35 B. 40 C. 30 D. 45
7. Age
Q1. A boy is twice as old as he was 6 years ago. His father is 3 times as old as the boy. How old is the father?
A. 36 B. 30 C. 42 D. 48
Q2. A girl is twice as old as she was 4 years ago. Her mother is 5 times as old as the girl. How old is the mother?
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