Area of Different Shapes (Solved Examples) | āĻŦāĻŋāĻāĻŋāύā§āύ āĻāĻā§āϤāĻŋā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ (āϏāĻŽāĻžāϧāĻžāύ)
1. Area of a Rectangle | āĻāϝāĻŧāϤāĻā§āώā§āϤā§ā§°ā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ
Question | āĻĒā§ā§°āĻļā§āύ: A rectangular park is 25 m long and 18 m wide. Find its area. āĻāĻāĻž āĻāϝāĻŧāϤāĻā§āώā§āϤā§ā§°āĻžāĻāĻžā§° āĻāĻĻā§āϝāĻžāύ⧰ āĻĻā§ā§°ā§āĻā§āϝ 25 m āĻā§°ā§ āĻĒā§ā§°āϏā§āĻĨ 18 māĨ¤ āĻāϝāĻŧāĻžā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāϞāĻŋāϝāĻŧāĻžāĻāĨ¤
Formula | āϏā§āϤā§ā§°: Area = Length × Width (A = l × w) )(āĻā§āώā§āϤā§ā§°āĻĢāϞ = āĻĻā§ā§°ā§āĻā§āϝ × āĻĒā§ā§°āϏā§āĻĨ)
Calculation | āĻāĻŖāύāĻž: A = 25 × 18 = 450 m²
Ans | āĻāϤā§āϤ⧰: 450 m² (450 āĻŦā§°ā§āĻ āĻŽāĻŋāĻāĻžā§°)
2. Area of a Rectangle | āϤā§ā§°āĻŋāĻā§āĻā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ
Question | āĻĒā§ā§°āĻļā§āύ: Find the area of a triangle with base = 14 cm and height = 9 cm. (āĻāĻŋāϤā§āϤāĻŋ 14 cm āĻā§°ā§ āĻāĻā§āĻāϤāĻž 9 cm āĻĨāĻāĻž āĻāĻāĻž āϤā§ā§°āĻŋāĻā§āĻā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāϞāĻŋāϝāĻŧāĻžāĻāĨ¤)
Formula | āϏā§āϤā§ā§°: Area = ½ × Base × Height (A = ½ × b × h)
Calculation | āĻāĻŖāύāĻž: A = ½ × 14 × 9 = 7 × 9 = 63 cm²
Ans | āĻāϤā§āϤ⧰: 63 cm² (63 āĻŦā§°ā§āĻ āĻā§āĻŖā§āĻāĻŋāĻŽāĻŋāĻāĻžā§°)
3. Area of a Parallelogram | āϏāĻžāĻŽāĻžāύā§āϤ⧰āĻŋāĻā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ
Question | āĻĒā§ā§°āĻļā§āύ: Find the area of a parallelogram with base = 15 cm and height = 10 cm. (15 cm āĻā§°ā§ āĻāĻā§āĻāϤāĻž 10 cm āĻĨāĻāĻž āĻāĻāĻž āϏāĻžāĻŽāĻžāύā§āϤ⧰āĻŋāĻā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāϞāĻŋāϝāĻŧāĻžāĻāĨ¤)
Formula | āϏā§āϤā§ā§°: Area = Base × Height (A = b × h)
Calculation | āĻāĻŖāύāĻž: A = 15 × 10 = 150 cm²
Ans | āĻāϤā§āϤ⧰: 150 cm² (150 āĻŦā§°ā§āĻ āĻā§āĻŖā§āĻāĻŋāĻŽāĻŋāĻāĻžā§°)
4. Area of a Circle | āĻŦā§āϤā§āϤ⧰ āĻā§āώā§āϤā§ā§°āĻĢāϞ
Question | āĻĒā§ā§°āĻļā§āύ: Find the area of a circle with radius = 7 cm. (Use π = 22/7)
āĻŦā§āϝāĻžāϏāĻžā§°ā§āϧ 7 cm āĻĨāĻāĻž āĻāĻāĻž āĻŦā§āϤā§āϤ⧰ āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāϞāĻŋāϝāĻŧāĻžāĻāĨ¤ (π = 22/7 āĻŦā§āĻ¯ā§ąāĻšāĻžā§° āĻā§°āĻž)
Formula | āϏā§āϤā§ā§°: Area = πr²
Calculation | āĻāĻŖāύāĻž: A = (22/7) × 7² = (22/7) × 49 = 22 × 7 = 154 cm²
Ans| āĻāϤā§āϤ⧰: 154 cm² (154 āĻŦā§°ā§āĻ āĻā§āĻŖā§āĻāĻŋāĻŽāĻŋāĻāĻžā§°)
5. Area of a Trapezium | āϏāĻŽāϞāĻŽā§āĻŦ āĻāϤā§ā§°ā§āĻā§āĻā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ
Question | āĻĒā§ā§°āĻļā§āύ: Find the area of a trapezium with parallel sides 20 cm and 12 cm and height 9 cm. (āϏāĻŽāĻžāύā§āϤ⧰āĻžāϞ āĻŦāĻžāĻšā§ 20 cm āĻā§°ā§ 12 cm āĻā§°ā§ āĻāĻā§āĻāϤāĻž 9 cm āĻĨāĻāĻž āĻāĻāĻž āϏāĻŽāϞāĻŽā§āĻŦ āĻāϤā§ā§°ā§āĻā§āĻā§° āĻā§āώā§āϤā§ā§°āĻĢāϞ āĻāϞāĻŋāϝāĻŧāĻžāĻāĨ¤_
Formula | āϏā§āϤā§ā§°: Area = ½ × (a + b) × h
Calculation | āĻāĻŖāύāĻž: A = ½ × (20 + 12) × 9 = ½ × 32 × 9 = 16 × 9 = 144 cm²
Ans | āĻāϤā§āϤ⧰: 144 cm² (144 āĻŦā§°ā§āĻ āĻā§āĻŖā§āĻāĻŋāĻŽāĻŋāĻāĻžā§°)
Note: The value 141 cm² shown in the original is incorrect. The correct answer is 144 cm² because 16 × 9 = 144, not 141.