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Letter/Alphabet Analogy 2

Q. If PEN = 17717, then what is the code for CAP ?

A. 2319 B. 4319 C. 4219 D. 2320

Solution

Use the alphabet positions and add 1, 2, 3 respectively: P = 16 + 1 = 17, E = 5 + 2 = 7, N = 14 + 3 = 17

So, PEN = 17 7 17 = 17717

For CAP: C = 3 + 1 = 4, A = 1 + 2 = 3, P = 16 + 3 = 19

CAP = 4 3 19 = 4319

Ans: B. 4319

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Q. APPLE = 57, then BALL = ? Options: (a) 28 (b) 30 (c) 32 (d) 34

Solution | সমাধান

APPLE: A = 1, P = 16, P = 16, L = 12, E = 5
Sum = 50
Total letters = 5
Vowels = 2

So, 50 + 5 + 2 = 57

BALL: B = 2, A = 1, L = 12, L = 12
Sum = 27
Total letters = 4
Vowels = 1

Therefore, 27 + 4 + 1 = 32

Ans | উত্তৰ: (c) 32

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Question | প্ৰশ্ন : If 34 × 15 = 495 and 43 × 12 = 504, then 98 × 17 = ? (যদি 34 × 15 = 495 আৰু 43 × 12 = 504 হয়, তেন্তে 98 × 17 = ?)

Options | বিকল্প: A. 1649 B. 1683 C. 1763 D. 1751

Trick | কৌশল

Multiply the two numbers, then subtract the second number. (প্ৰথমে দুয়োটা সংখ্যাক গুণ কৰক, তাৰ পিছত দ্বিতীয় সংখ্যাটো বিয়োগ কৰক।)

Solution | সমাধান

So,

Ans | উত্তৰ: A. 1649

Question | প্ৰশ্ন : If (3)² @ 1 * 7 = 98, (4)² @ 2 * 16 = 178, then (5)² @ 3 * 9 = ? যদি (3)² @ 1 * 7 = 98, (4)² @ 2 * 16 = 178 হয়, তেন্তে (5)² @ 3 * 9 = ?

Options | বিকল্প: A. 218 B. 262 C. 253 D. 259

Trick | কৌশল

Observe the pattern:

(3)² = 9, 9 × 10 + 8 = 98 (where 8 = 1 + 7)

(4)² = 16, 16 × 10 + 18 = 178 (where 18 = 2 + 16)

So the rule is: [(5)² x 10] + (

Ans | উত্তৰ : B. 262

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Q. CE : 70 :: DE : ?

Options: A. 90 B. 60 C. 120 D. 210

Trick : Join the alphabet positions → Multiply by 2.

C = 3, E = 5 → 35 × 2 = 70

D = 4, E = 5 → 45 × 2 = 90

Ans: A. 90

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Q. 25 : ? :: 36 : 85

Options: (A) 84 (B) 41 (C) 53 (D) 61

Trick:

Notice that:

Here, 49 = 7², which is the next perfect square after 36 (which is 6²).

Applying the same rule:

Next perfect square = 6²

Therefore, 25 : 61 :: 36 : 85

Ans: (D) 61

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Q. AB : C² :: BC : E² :: GH : ?²

Options: (A) J² (B) K² (C) O² (D) R²

Solution | সমাধান

Find the alphabetical positions:

A = 1, B = 2

3rd letter = C ⇒ AB : C²

B = 2, C = 3

5th letter = E ⇒ BC : E²

G = 7, H = 8

15th letter = O ⇒ GH : O²

Trick | কৌশল

Add the alphabet positions of the two letters. দুটা আখৰৰ Alphabet Position যোগ কৰক।

A(1) + B(2) = 3 → C²

B(2) + C(3) = 5 → E²

G(7) + H(8) = 15 → O²

Ans / উত্তৰ: (C) O²

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Q. √AFI = M :: √ADD = L :: √ABA = ?

Option: A) F B) G C) H D) K

Solution | সমাধান

1st : Convert each letter into its alphabetical position and join the numbers (do not add them). (১: প্ৰতিটো আখৰক তাৰ বৰ্ণানুক্ৰমিক স্থানলৈ ৰূপান্তৰ কৰি সংখ্যাবোৰ একেলগে লিখক (যোগ নকৰিব)।)

AFI → A = 1, F = 6, I = 9 , AFI → 169

ADD → A = 1, D = 4, D = 4 , ADD → 144

ABA → A = 1, B = 2, A = 1 , ABA → 121

2nd : Find the square root and convert the result into the corresponding alphabet. (২: বৰ্গমূল (√) উলিয়াওক আৰু পোৱা সংখ্যাটোক সংশ্লিষ্ট আখৰলৈ ৰূপান্তৰ কৰক।)

$\Rightarrow$ M

$\Rightarrow$ L

$\Rightarrow$ K

Ans | উত্তৰ: D) K

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Q. Find the missing letter: B, G, N, W, ?

Pattern: B → G = +5, G → N = +7, N → W = +9, W → ? = +11

Now, W + 11 (cyclically) = H

Trick: +5, +7, +9, +11 → odd numbers increasing by 2.

Ans: (d) H

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