Letter/Alphabet Analogy 2


Question | āĻĒā§ā§°āĻļā§āύ : If 34 × 15 = 495 and 43 × 12 = 504, then 98 × 17 = ? (āϝāĻĻāĻŋ 34 × 15 = 495 āφ⧰⧁ 43 × 12 = 504 āĻšāϝāĻŧ, āϤ⧇āĻ¨ā§āϤ⧇ 98 × 17 = ?)


Options | āĻŦāĻŋāĻ•āĻ˛ā§āĻĒ: A. 1649  B. 1683  C. 1763  D. 1751


Trick | āĻ•ā§ŒāĻļāϞ


Multiply the two numbers, then subtract the second number. (āĻĒā§ā§°āĻĨāĻŽā§‡ āĻĻ⧁āϝāĻŧā§‹āϟāĻž āϏāĻ‚āĻ–ā§āϝāĻžāĻ• āϗ⧁āĻŖ āϕ⧰āĻ•, āϤāĻžā§° āĻĒāĻŋāĻ›āϤ āĻĻā§āĻŦāĻŋāϤ⧀āϝāĻŧ āϏāĻ‚āĻ–ā§āϝāĻžāĻŸā§‹ āĻŦāĻŋāϝāĻŧā§‹āĻ— āϕ⧰āĻ•āĨ¤)


Solution | āϏāĻŽāĻžāϧāĻžāύ


34 × 15 = 510, 510 − 15 = 495


43 × 12 = 516, 516 - 12 = 504 


So,


98 × 17 = 1666, 1666 − 17 = - 17 = 1649


Ans | āωāĻ¤ā§āϤ⧰: A. 1649


Question | āĻĒā§ā§°āĻļā§āύ : If (3)² @ 1 * 7 = 98, (4)² @ 2 * 16 = 178, then (5)² @ 3 * 9 = ?  āϝāĻĻāĻŋ (3)² @ 1 * 7 = 98, (4)² @ 2 * 16 = 178 āĻšāϝāĻŧ, āϤ⧇āĻ¨ā§āϤ⧇ (5)² @ 3 * 9 = ?


Options | āĻŦāĻŋāĻ•āĻ˛ā§āĻĒ: A. 218  B. 262  C. 253  D. 259


Trick | āĻ•ā§ŒāĻļāϞ


Observe the pattern:



  • (3)² = 9, 9 × 10 + 8 = 98 (where 8 = 1 + 7)



  • (4)² = 16, 16 × 10 + 18 = 178 (where 18 = 2 + 16)


So the rule is: (a2 × 10) + (b + c) = [(5)2 x 10] + (3 + 9) = 250 + 12 = 262


Ans | āωāĻ¤ā§āϤ⧰ : B. 262


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Q. CE : 70 :: DE : ?


Options: A. 90 B. 60 C. 120 D. 210


Trick : Join the alphabet positions → Multiply by 2.



  • C = 3, E = 5 → 35 × 2 = 70

  • D = 4, E = 5 → 45 × 2 = 90


Ans: A. 90


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Q. 25 : ? :: 36 : 85


Options: (A) 84  (B) 41  (C) 53  (D) 61


Trick:


Notice that: 36 + 49 = 85 


Here, 49 = 72, which is the next perfect square after 36 (which is 62).


Applying the same rule: 25 = 52 



  • Next perfect square = 62 = 36

  • 25 + 36 = 61


Therefore, 25 : 61 :: 36 : 85


Ans: (D) 61


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Q. AB : C² :: BC : E² :: GH : ?²


Options: (A) J² (B) K² (C) O² (D) R²


Solution | āϏāĻŽāĻžāϧāĻžāύ

Find the alphabetical positions:


A = 1, B = 2


1 + 2 = 3


3rd letter = C ⇒ AB : C²


B = 2, C = 3


2 + 3 = 5 


5th letter = E ⇒ BC : E²


G = 7, H = 8


7 + 8 = 15


15th letter = O ⇒ GH : O²


Trick | āĻ•ā§ŒāĻļāϞ

Add the alphabet positions of the two letters. āĻĻ⧁āϟāĻž āφāĻ–ā§°ā§° Alphabet Position āϝ⧋āĻ— āϕ⧰āĻ•āĨ¤



  • A(1) + B(2) = 3 → C²

  • B(2) + C(3) = 5 → E²

  • G(7) + H(8) = 15 → O²


Ans / āωāĻ¤ā§āϤ⧰: (C) O²






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