What is a pattern ? (āĻā§°ā§āĻšāĻŋ) āĻāĻŋ ? // Introduction to Patterns (āĻā§°ā§āĻšāĻŋā§° āĻĒā§°āĻŋāĻāϝāĻŧ)
Chapter 1: Patterns in Mathematics (āĻāĻŖāĻŋāϤāϤ āĻā§°ā§āĻšāĻŋ)
Introduction to Patterns (āĻā§°ā§āĻšāĻŋā§° āĻĒā§°āĻŋāĻāϝāĻŧ)
Q1. What is a pattern ? āĻĒā§ā§°āĻļā§āύ ā§§: Pattern (āĻā§°ā§āĻšāĻŋ) āĻāĻŋ ?
Solution:
A pattern is an arrangement of numbers, shapes, letters, or objects that follows a particular rule. (āĻā§°ā§āĻšāĻŋ (Pattern) āĻš'āϞ āϏāĻāĻā§āϝāĻž, āĻāĻā§āϤāĻŋ, āĻāĻā§° āĻŦāĻž āĻŦāϏā§āϤā§ā§° āĻāύ⧠āĻāĻāĻž āĻŦāĻŋāύā§āϝāĻžāϏ, āϝāĻŋ āĻāĻāĻž āύāĻŋā§°ā§āĻĻāĻŋāώā§āĻ āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŖ āĻā§°ā§āĨ¤)
Key Point: A pattern always follows a fixed rule. / āĻŽā§āϞ āĻāĻĨāĻž: āĻĒā§ā§°āϤāĻŋāĻā§ āĻā§°ā§āĻšāĻŋāϝāĻŧā§ āĻāĻāĻž āύāĻŋā§°ā§āĻĻāĻŋāώā§āĻ āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŖ āĻā§°ā§āĨ¤
Ans / āĻāϤā§āϤ⧰: A pattern is an arrangement of numbers, shapes or objects that follows a particular rule. āĻā§°ā§āĻšāĻŋ āĻš'āϞ āϏāĻāĻā§āϝāĻž, āĻāĻā§āϤāĻŋ āĻŦāĻž āĻŦāϏā§āϤā§ā§° āĻāύ⧠āĻāĻāĻž āĻŦāĻŋāύā§āϝāĻžāϏ, āϝāĻŋ āĻāĻāĻž āύāĻŋā§°ā§āĻĻāĻŋāώā§āĻ āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŖ āĻā§°ā§āĨ¤
Q2. Complete the pattern: āĻĒā§ā§°āĻļā§āύ ⧍: āĻā§°ā§āĻšāĻŋāĻā§ āϏāĻŽā§āĻĒā§ā§°ā§āĻŖ āĻā§°āĻž:
2, 4, 6, 8, __, __
Solution: Each number is obtained by adding 2. (āĻĒā§ā§°āϤāĻŋāĻā§ āϏāĻāĻā§āϝāĻžāϤ 2 āϝā§āĻ āĻā§°āĻŋ āĻĒā§°ā§ąā§°ā§āϤ⧠āϏāĻāĻā§āϝāĻžāĻā§ āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤)
8 + 2 = 10
10 + 2 = 12
Therefore, the missing numbers are 10 and 12. (āϏā§āϝāĻŧā§ āĻāĻžāϞ⧠āϏā§āĻĨāĻžāύāϤ āĻĨāĻžāĻāĻŋāĻŦ 10 āĻā§°ā§ 12)
Ans / āĻāϤā§āϤ⧰: 10, 12
Q3. Find the rule of the pattern: āĻĒā§ā§°āĻļā§āύ ā§Š: āĻā§°ā§āĻšāĻŋāĻā§ā§° āύāĻŋāϝāĻŧāĻŽ āĻŦāĻŋāĻāĻžā§°āĻž:
5, 10, 15, 20, 25, ...
Solution: āϏāĻŽāĻžāϧāĻžāύ
Find the difference between consecutive numbers:(āĻāĻžāώ⧠āĻāĻžāώ⧠āĻĨāĻāĻž āϏāĻāĻā§āϝāĻžāĻŦā§ā§°ā§° āĻĒāĻžā§°ā§āĻĨāĻā§āϝ āĻāĻžāĻāĻ : , 10 − 5 = 5, 15 − 10 = 5, 20 − 15 = 5, 25 − 20 = 5
Since the difference is always 5, the rule is: āĻĒā§ā§°āϤāĻŋāĻŦāĻžā§°ā§āĻ āĻĒāĻžā§°ā§āĻĨāĻā§āϝ 5, āϏā§āϝāĻŧā§ āύāĻŋāϝāĻŧāĻŽāĻā§ āĻš'āϞ -
āύāĻŋāϝāĻŧāĻŽ: āĻĒā§°ā§ąā§°ā§āϤ⧠āϏāĻāĻā§āϝāĻž āĻĒāĻžāĻŦāϞ⧠5 āϝā§āĻ āĻā§°āĻŋāĻŦ āϞāĻžāĻāĻŋāĻŦāĨ¤
Rule: Add 5 to get the next number.
Ans / āĻāϤā§āϤ⧰: Add 5 to obtain the next number. (āĻĒā§°ā§ąā§°ā§āϤ⧠āϏāĻāĻā§āϝāĻž āĻĒāĻžāĻŦāϞ⧠5 āϝā§āĻ āĻā§°āĻŋāĻŦ āϞāĻžāĻā§āĨ¤)
Note: Pattern: Follows a fixed rule. (āĻāĻāĻž āύāĻŋā§°ā§āĻĻāĻŋāώā§āĻ āύāĻŋāϝāĻŧāĻŽ āĻ āύā§āϏ⧰āĻŖ āĻā§°ā§āĨ¤)
2, 4, 6, 8, 10, 12 → Rule: Add 2. āύāĻŋāϝāĻŧāĻŽ: 2 āϝā§āĻ āĻā§°āĻžāĨ¤
5, 10, 15, 20, 25 → Rule: Add 5. āύāĻŋāϝāĻŧāĻŽ: 5 āϝā§āĻ āĻā§°āĻžāĨ¤
Trick : Find the difference between consecutive numbers to identify the pattern. : āĻā§°ā§āĻšāĻŋā§° āύāĻŋāϝāĻŧāĻŽ āĻāĻžāύāĻŋāĻŦāϞ⧠āĻāĻžāώ⧠āĻāĻžāώ⧠āĻĨāĻāĻž āϏāĻāĻā§āϝāĻžāĻŦā§ā§°ā§° āĻĒāĻžā§°ā§āĻĨāĻā§āϝ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
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Relations among Sequence
Q1. Add consecutive triangular numbers. āĻĒā§ā§°āĻļā§āύ ā§§: āĻĒā§°āϏā§āĻĒā§° āĻā§ā§°āĻŽāĻžāĻāϤ āϤā§ā§°āĻŋāĻā§āĻā§āϝāĻŧ āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻžāĨ¤
1 + 3, 3 + 6, 6 + 10
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 3 = 4
3 + 6 = 9
6 + 10 = 16
Therefore, we obtain 4, 9, 16. These are square numbers. āϏā§āϝāĻŧā§ āĻāĻŽāĻŋ āĻĒāĻžāĻāĻ – 4, 9, 16āĨ¤ āĻāĻāĻŦā§ā§° āĻŦā§°ā§āĻ āϏāĻāĻā§āϝāĻž (Square Numbers)āĨ¤
Ans / āĻāϤā§āϤ⧰: 4, 9, 16
Key Point / āĻŽā§āϞ āĻāĻĨāĻž: Consecutive triangular numbers added together always form square numbers. (āĻĒā§°āϏā§āĻĒā§° āĻā§ā§°āĻŽāĻžāĻāϤ āϤā§ā§°āĻŋāĻā§āĻā§āϝāĻŧ āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻŋāϞ⧠āϏāĻĻāĻžāϝāĻŧ āĻŦā§°ā§āĻ āϏāĻāĻā§āϝāĻž āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤)
Q2. Add powers of 2. āĻĒā§ā§°āĻļā§āύ ⧍: 2-ā§° āĻāĻžāϤāϏāĻŽā§āĻš āϝā§āĻ āĻā§°āĻžāĨ¤
1 + 2 + 4 + 8
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 2 + 4 + 8 = 15
Adding 1:
15 + 1 = 16 = 2â´
1 + 2 + 4 + 8 = 15, āĻāϤāĻŋāϝāĻŧāĻž 1 āϝā§āĻ āĻā§°āĻŋāϞā§, 15 + 1 = 16 = 2â´
Ans / āĻāϤā§āϤ⧰: 15
Key Point / āĻŽā§āϞ āĻāĻĨāĻž: The sum of consecutive powers of 2, plus 1, gives the next power of 2. (2-ā§° āĻā§ā§°āĻŽāĻžāĻāϤ āĻāĻžāϤāϏāĻŽā§āĻšā§° āϝā§āĻāĻĢāϞāϤ 1 āϝā§āĻ āĻā§°āĻŋāϞ⧠āĻĒā§°ā§ąā§°ā§āϤ⧠2-ā§° āĻāĻžāϤ āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤)
Q3. Find the next number. āĻĒā§ā§°āĻļā§āύ ā§Š: āĻĒā§°ā§ąā§°ā§āϤ⧠āϏāĻāĻā§āϝāĻžāĻā§ āĻŦāĻŋāĻāĻžā§°āĻžāĨ¤
1, 7, 19, 37, ___
Solution / āϏāĻŽāĻžāϧāĻžāύ:
Find the differences / āĻĒāĻžā§°ā§āĻĨāĻā§āϝ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻ—
7 − 1 = 6
19 − 7 = 12
37 − 19 = 18
The differences increase by 6 each time. āĻĒā§ā§°āϤāĻŋāĻŦāĻžā§° āĻĒāĻžā§°ā§āĻĨāĻā§āϝ 6 āĻā§ āĻŦā§āĻĻā§āϧāĻŋ āĻĒāĻžāĻāĻā§āĨ¤
Next difference / āĻĒā§°ā§ąā§°ā§āϤ⧠āĻĒāĻžā§°ā§āĻĨāĻā§āϝ: 18 + 6 = 24, 37 + 24 = 61
Ans / āĻāϤā§āϤ⧰: 61
Note: When the differences follow a pattern, first find the next difference and then add it to the last number. (āϝāĻĻāĻŋ āĻĒāĻžā§°ā§āĻĨāĻā§āϝāϏāĻŽā§āĻšā§ āĻāĻāĻž āĻā§°ā§āĻšāĻŋ āĻ āύā§āϏ⧰āĻŖ āĻā§°ā§, āϤā§āύā§āϤ⧠āĻĒā§ā§°āĻĨāĻŽā§ āĻĒā§°ā§ąā§°ā§āϤ⧠āĻĒāĻžā§°ā§āĻĨāĻā§āϝ āĻāϞāĻŋāϝāĻŧāĻžāĻ āĻļā§āώ⧰ āϏāĻāĻā§āϝāĻžāϤ āϝā§āĻ āĻā§°āĻŋāĻŦ āϞāĻžāĻā§āĨ¤)
Trick / āĻā§āĻļāϞ : First find the difference between consecutive numbers. Most number patterns become easy to identify : āĻĒā§ā§°āĻĨāĻŽā§ āĻāĻžāώ⧠āĻāĻžāώ⧠āĻĨāĻāĻž āϏāĻāĻā§āϝāĻžāĻŦā§ā§°ā§° āĻĒāĻžā§°ā§āĻĨāĻā§āϝ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤ āĻŦā§āĻāĻŋāĻāĻžāĻ āϏāĻāĻā§āϝāĻž-āĻā§°ā§āĻšāĻŋ āĻāĻāĻĻā§°ā§āĻ āϏāĻšāĻā§ āĻāĻŋāύāĻžāĻā§āϤ āĻā§°āĻŋāĻŦ āĻĒāĻžā§°āĻŋāĨ¤
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Adding Numbers Up and Down (āĻāĻĒā§°āϞ⧠āĻā§°ā§ āϤāϞāϞ⧠āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻž)
Q1. Find: āĻĒā§ā§°āĻļā§āύ ā§§: āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
1 + 2 + 1
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 2 + 1 = 4
Since, āϝāĻŋāĻšā§āϤ⧠4 = 2²
Ans / āĻāϤā§āϤ⧰: 4 (= 2²)
Key Point / āĻŽā§āϞ āĻāĻĨāĻž: Adding numbers up to 2 and back to 1 gives the square of 2. (2 āϞā§āĻā§ āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻŋ āĻĒā§āύ⧰ 1āϞ⧠āĻāĻšāĻŋāϞ⧠2-ā§° āĻŦā§°ā§āĻ (2²) āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤)
Q2. Find: āĻĒā§ā§°āĻļā§āύ ⧍: āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
1 + 2 + 3 + 2 + 1
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 2 + 3 + 2 + 1 = 9
Since, āϝāĻŋāĻšā§āϤ⧠9 = 3²
Ans / āĻāϤā§āϤ⧰: 9 (= 3²)
Key Point / āĻŽā§āϞ āĻāĻĨāĻž: Adding numbers up to 3 and back to 1 gives the square of 3. (3 āϞā§āĻā§ āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻŋ āĻĒā§āύ⧰ 1āϞ⧠āĻāĻšāĻŋāϞ⧠3-ā§° āĻŦā§°ā§āĻ (3²) āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤)
Q3. Find: āĻĒā§ā§°āĻļā§āύ ā§Š: āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
1 + 2 + 3 + 4 + 3 + 2 + 1
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 2 + 3 + 4 + 3 + 2 + 1 = 16
Since, āϝāĻŋāĻšā§āϤ⧠16 = 4²
Ans / āĻāϤā§āϤ⧰: 16 (= 4²)
Note: Adding numbers up to 4 and back to 1 gives the square of 4. (4 āϞā§āĻā§ āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻŋ āĻĒā§āύ⧰ 1āϞ⧠āĻāĻšāĻŋāϞ⧠4-ā§° āĻŦā§°ā§āĻ (4²) āĻĒā§ā§ąāĻž āϝāĻžāϝāĻŧāĨ¤)
General Rule / āϏāĻžāϧāĻžā§°āĻŖ āύāĻŋāϝāĻŧāĻŽ : If you add numbers from 1 to n and then back down to 1, the sum is n².(āϝāĻĻāĻŋ 1ā§° āĻĒā§°āĻž nāϞ⧠āϏāĻāĻā§āϝāĻž āϝā§āĻ āĻā§°āĻŋ āĻĒā§āύ⧰ 1āϞ⧠āύāĻžāĻŽāĻŋ āĻāĻšā§, āϤā§āύā§āϤ⧠āĻŽā§āĻ āϝā§āĻāĻĢāϞ n² āĻšāϝāĻŧāĨ¤)
1 + 2 + ⯠+ n + (n − 1) + ⯠+ 2 + 1 = n2
Trick / āĻā§āĻļāϞ : Go up to n, come back to 1 → Answer = n². : āϏāĻāĻā§āϝāĻžāĻŦā§ā§° n āϞā§āĻā§ āĻāĻ āĻŋ āĻĒā§āύ⧰ 1āϞ⧠āύāĻžāĻŽāĻŋāϞ⧠→ āĻāϤā§āϤ⧰ = n².
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Sum of Odd Numbers (āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻžā§° āϝā§āĻāĻĢāϞ)
Q1. Find: āĻĒā§ā§°āĻļā§āύ ā§§: āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
1 + 3 + 5
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 3 + 5 = 9
Since, āϝāĻŋāĻšā§āϤ⧠9 = 3²
Ans / āĻāϤā§āϤ⧰: 9 (= 3²)
Note: The sum of the first 3 odd numbers is 3². (āĻĒā§ā§°āĻĨāĻŽ ā§ŠāĻāĻž āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻžā§° āϝā§āĻāĻĢāϞ = 3²āĨ¤)
Q2. Find: āĻĒā§ā§°āĻļā§āύ ⧍: āĻŽāĻžāύ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
1 + 3 + 5 + 7
Solution / āϏāĻŽāĻžāϧāĻžāύ:
1 + 3 + 5 + 7 = 16
Since, āϝāĻŋāĻšā§āϤ⧠16 = 4²
Ans / āĻāϤā§āϤ⧰: 16 (= 4²)
Note: The sum of the first 4 odd numbers is 4². āĻĒā§ā§°āĻĨāĻŽ ā§ĒāĻāĻž āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻžā§° āϝā§āĻāĻĢāϞ = 4²āĨ¤
Q3. Find the sum of the first 10 odd numbers. āĻĒā§ā§°āĻļā§āύ ā§Š: āĻĒā§ā§°āĻĨāĻŽ ā§§ā§ĻāĻāĻž āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻžā§° āϝā§āĻāĻĢāϞ āĻāϞāĻŋāϝāĻŧāĻžāĻāĻāĨ¤
Solution / āϏāĻŽāĻžāϧāĻžāύ:
Rule / āύāĻŋāϝāĻŧāĻŽ: The sum of the first n odd numbers is n². āĻĒā§ā§°āĻĨāĻŽ nāĻāĻž āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻžā§° āϝā§āĻāĻĢāϞ = n²āĨ¤
Here, n = 10
10² = 100
Ans / āĻāϤā§āϤ⧰: 100
General Rule / āϏāĻžāϧāĻžā§°āĻŖ āύāĻŋāϝāĻŧāĻŽ : The sum of the first n odd numbers is n². : āĻĒā§ā§°āĻĨāĻŽ nāĻāĻž āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻžā§° āϝā§āĻāĻĢāϞ = n²āĨ¤
Trick / āĻā§āĻļāϞ : Count the odd numbers, then square the count : āĻā§āĻāĻāĻž āĻŦāĻŋāĻā§āĻĄāĻŧ āϏāĻāĻā§āϝāĻž āĻāĻā§ āĻāĻŖāύāĻž āĻā§°āĻ, āϤāĻžā§° āĻĒāĻŋāĻāϤ āϏā§āĻ āϏāĻāĻā§āϝāĻžāĻā§ā§° āĻŦā§°ā§āĻ āĻā§°āĻāĨ¤
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