Competitive Exams : PYQ Practice

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Q. A bag contains 25p, 10p and 5p coins in the ratio 1 : 2 : 3. If the total value of the coins is ₹30, how many 5-paise coins are there ?

(A) 50  (B) 100  (C) 150  (D) 200

Solution

Let the number of coins be: 25p coins = x, 10p coins = 2x, 5p coins = 3x

Formula : $$\text{Total Value }=(\text{No. of coins})\times (\text{Value of each coin})$$

Convert ₹30 into paise: $$₹30=3000\text{ paise}$$

Therefore,

$$25x+10(2x)+5(3x)=3000$$

$$25x+20x+15x=3000$$

$$60x=3000$$

$$x=50$$

Number of 5-paise coins: 3x = 3×50 = 150​

Ans: (C) 150

Trick: Ratio = 1 : 2 : 3 → value of one ratio set:

$$25(1)+10(2)+5(3)=60p$$

$$3000÷60=50$$

5p coins = 3×50 = 150​.

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Q. A person has notes of ₹1, ₹5 and ₹10 with a total value of ₹640. If the number of each type of note is the same, how many notes does the person have ?

(A) 120  (B) 124  (C) 126  (D) None

Solution

Let the number of each type of note be x.

Value of ₹1 notes: $$1x=x$$

Value of ₹5 notes: $$5x$$

Value of ₹10 notes: $$10x$$

Formula : $$\text{Total Value }=\text{Number of notes }\times \text{Value of each note}$$

Therefore,

$$\text{x + 5x + 10x = 640}$$

$$\text{16x = 640}$$

$$\text{x = 40}$$

So, each type has 40 notes.

There are 3 types of notes: $$\text{Total notes = 40 + 40 + 40 = 120}$$

Ans: (A) 120

Trick:

$$\text{(1 + 5 + 10) = 16}$$

$$\text{640 ÷ 16 = 40}$$

Total notes: $$\text{40 × 3 = 120}$$

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Q. A bag contains ₹1,50-paise and 25-paise coins in the ratio 2 : 3 : 4. If the total value is ₹216, find the number of 50-paise coins.

(A) 144  (B) 96  (C) 104  (D) 126

Solution

Let the numbers of ₹1,50p and 25p coins be: $$\text{2x, 3x, 4x}$$

Convert ₹216 into paise: $$\text{₹216 = 21600 paise}$$

Formula: $$\text{Total Value = ∑(Number of coins × Value of each coin)}$$

Therefore, $$\text{2x(100) + 3x(50) + 4x(25) = 21600}$$

$$\text{ 200x + 150x + 100x = 21600}$$

$$\text{ 450x = 21600}$$

$$\text{ x = 48}$$

Number of 50-paise coins: $$\text{3x = 3×48 = 144}$$

Ans: (A) 144

​Trick:

Value of one ratio group: $$\text{2(₹1) + 3(₹0.50) + 4(₹0.25) = 2 + 1.5 + 1 = ₹4.5}$$

$$\text{ 216 ÷ 4.5 = 48}$$

                                                                      50-paise coins: $$\text{3 × 48 = 144}$$

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Q. A bag contains 378 coins of ₹1, 50 paise and 25 paise. Their values are in the ratio 13 : 11 : 7. How many 50-paise coins are there ?

(A) 96  (B) 132  (C) 106  (D) None

Solution

Let the total values be: $$\text{13x, 11x, 7x}$$

For each type:

$$\text{Number of coins = Total value / Value of one coin}$$

So the number of coins are proportional to:

$$\text{13x/1 : 11x/0.5 : 7x/0.25 = 13 : 22 : 28}$$

Total coins = 378:

$$\text{13x + 22x + 28x = 378}$$

$$\text{63x = 378}$$

$$\text{x = 6}$$

Therefore, number of 50-paise coins: $$\text{22 × 6 = 132}$$

Ans: (B) 132

​Trick:

Value ratio: $13:11:7$

Coin-value ratio: $1:0.5:0.25$

Therefore, number ratio: $$\text{13 : 22 : 28}$$

$$\text{ 22/63 × 378 = 132}$$

$$\text{Competitive Exams : PYQ Practice 1 : Click Here}$$