Find Profit & Cost 8

---

1.An article is bought for ₹1200 and sold for ₹1020. What is the loss percentage ?

A) 10%   B) 12%   C) 15%   D) 18%

Solution:

Cost Price (CP) = ₹1200
Selling Price (SP) = ₹1020

Loss = CP − SP

$$=1200-1020=₹180$$

Loss Percentage:

= Loss/CP​ × 100 = 180/1200​ × 100 $$=15\%$$

Ans: (C) 15%

=============================

2. What is the Simple Interest on ₹5,000 for 2 years at 8% per annum ?

A) ₹700  B) ₹800  C) ₹900  D) ₹1,000

Solution:

Principal (P) = ₹5,000
Rate (R) = 8% per annum
Time (T) = 2 years

For Simple Interest:

SI = P×R×T/100

​ SI = 5000 × 8 × 2​/100 $$=50\times 16$$ = ₹800​

Ans: (B) ₹800

===========================

Q. A manufacturer sells a transistor to a shopkeeper for ₹840 at a profit of 20%. The shopkeeper then sells it to a customer at a profit of 10%. What is the difference (in ₹) between the manufacturer's cost price and the customer's purchase price?

A. ₹200  B. ₹224  C. ₹250   D. ₹345

Solution:

Let the manufacturer's Cost Price (CP) = ₹x

He sells the transistor for ₹840 at 20% profit.

$$120\%\text{ of }x=840$$

              x = 840×100​/120 = ₹700

So, Manufacturer's CP = ₹700

Now, the shopkeeper sells it to the customer at 10% profit:

Customer′s CP = 840 × 110/100​ = ₹924

Therefore, the difference is: 924 − 700 = ₹224​

Ans: B. ₹224

Trick:

Manufacturer CP = 840 × 100​/120 = 700

Customer CP = 840 × 110​/100 = 924

Difference = 924 − 700 = ₹224

=========================================

Q. A shirt is sold for ₹720 at a profit of 20%. Find the Cost Price (CP).

Solution:

Profit = 20%

So,

$$SP=100\%+20\%=120\%$$

$$120\%=₹720$$

Therefore,

CP = 720×100/120​ = ₹600​

Ans: (B) ₹600

Shortcut: CP = SP × 100 ÷ (100 + Profit%)

========================================

Q. A pair of jeans is sold for ₹1,560 at a profit of 30%. Find the Cost Price (CP).

Solution:

30% Profit → SP = 130%

CP = 1560×100​/130

CP = ₹1200​

Ans: (C) ₹1,200

Shortcut: CP = SP × 100 ÷ (100 + Profit%)

=====================================@