Find Father's Age and Son's Age
Q1. Father's Age and Son's Age
Q. A father's age is 6 times his son's age. After 4 years, the father's age will be 4 times the son's age. Find their present ages.
Solution:
Let the son's present age = x years
Father's present age:
After 4 years: Son's age: Father's age:
According to the question:
Therefore,
Son's present age = 6 years
Father's present age:
Ans: Son = 6 years. Father = 36 years
Short Trick: Age Problem
Father : Son = 6 : 1
After 4 years:
Father : Son = 4 : 1
Difference in ratio:
The 2 parts = 4 years
So, Son's present age:
Father's present age:
Ans: Son = 6 years, Father = 36 years
Trick:
Q. The present ages of A and B are in the ratio 4 : 5. After 6 years, their ages will be in the ratio 5 : 6. What is B's present age ?
(A) 24 years (B) 30 years (C) 36 years (D) 40 years
Solution:
Let the present ages of A and B be 4x and 5x.
After 6 years:
Cross-multiply:
Therefore,
Ans: (B) 30 years
Q. The present ages of A and B are in the ratio 3 : 4. After 5 years, their ages will be in the ratio 4 : 5. What is B's present age ?
(A) 15 years (B) 20 years (C) 25 years (D) 30 years
Solution:
Let present ages be 3x and 4x.
After 5 years:
Cross-multiply:
Therefore,
Ans: (B) 20 years
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Q. The sum of the ages of a father and son is 60 years. The father is 4 times as old as his son. Find their ages.
Solution
1st: Assume son's age = x
Father's age = 4x
2nd: Form the equation
4x + x = 60
5x = 60
x = 12
3rd: Find their ages
Son's age: x=12 years
Father's age: 4x = 4×12 = 48 years
Ans: Father = 48 years, Son = 12 years
Trick
Ratio = Father : Son = 4 : 1
Total parts = 5
60 ÷ 5 = 12
So: Son = 12 years, Father = 48 years.
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