Find Father's Age and Son's Age


Q1. Father's Age and Son's Age


Q. A father's age is 6 times his son's age. After 4 years, the father's age will be 4 times the son's age. Find their present ages.


Solution:


Let the son's present age = x years


Father's present age:


After 4 years: Son's age: Father's age:


According to the question:







Therefore,


Son's present age = 6 years


Father's present age:


Ans: Son = 6 years. Father = 36 years


Short Trick: Age Problem


Father : Son = 6 : 1


After 4 years:


Father : Son = 4 : 1


Difference in ratio:


The 2 parts = 4 years



So, Son's present age:


Father's present age:


Ans: Son = 6 years, Father = 36 years


Trick:



Q. The present ages of A and B are in the ratio 4 : 5. After 6 years, their ages will be in the ratio 5 : 6. What is B's present age ?


(A) 24 years  (B) 30 years  (C) 36 years  (D) 40 years


Solution:


Let the present ages of A and B be 4x and 5x.


After 6 years:



Cross-multiply:





Therefore,



Ans: (B) 30 years



Q. The present ages of A and B are in the ratio 3 : 4. After 5 years, their ages will be in the ratio 4 : 5. What is B's present age ?


(A) 15 years  (B) 20 years  (C) 25 years  (D) 30 years


Solution:


Let present ages be 3x and 4x.


After 5 years:


Cross-multiply:




Therefore,



Ans: (B) 20 years


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Q. The sum of the ages of a father and son is 60 years. The father is 4 times as old as his son. Find their ages.


Solution


1st: Assume son's age = x


Father's age = 4x


2nd: Form the equation


4x + x = 60 


5x = 60


x = 12


3rd: Find their ages


Son's age: x=12 years


Father's age: 4x = 4×12 = 48 years 


Ans: Father = 48 years, Son = 12 years


Trick


Ratio = Father : Son = 4 : 1


Total parts = 5


60 ÷ 5 = 12 


So: Son = 12 years, Father = 48 years.


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