Competive Exam Math 14
Q. If 5n = 2, then 25 2n + 1 = ?
(A) 100 (B) 200 (C) 225 (D) 400
Soln
252n+1 = (52)2n+1 =54n+2 = 54n × 52
Since 5n = 2,
54n = (5n)4 = 24 = 16
Therefore, 16 × 25 = 400
Ans: (D) 400
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Q. The difference between two numbers is 7. If their product is 330, what is the sum of the two numbers ?
(A) 37 (B) 43 (C) 45 (D) 49
Solution:
Let the two numbers be x and y.
x – y = 7, xy = 330
Using the identity: (x+y)2 = (x−y)2 + 4xy = (7)2 + 4(330) = 49 + 1320 = 1369
Therefore,
x + y = √1369 = 37
Ans: (A) 37
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Q. How many prime factors are included in the factorization of 67×353×1110
Trick Method
- 6 = 2 × 3, Therefore, 67 contains 7 × 2 = 14 prime factors.
- 35 = 5×7, Therefore, 353 contains 3 × 2 = 6 prime factors.
- 1110 contains 10 prime factors.
Total = 14 + 6 + 10 = 30
Ans: C) 30
Trick: If a number has n prime factors, then its mmth power has n × m prime factors, counting multiplicity.
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