Work Done : Numerical Problems
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Work Done
Q1. A force of 50 N is used to push a box to a distance of 4 m. Calculate the work done.
āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻž āĻŦāĻžāĻāĻ ā§Ģā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ ā§Ē āĻŽāĻŋāĻāĻžā§° āĻĻā§ā§°āĻ¤ā§āĻŦāĻ˛ā§ āĻ ā§āĻ˛āĻŋ āĻ¨āĻŋāĻ¯āĻŧāĻž āĻš’āĻ˛āĨ¤ āĻā§°āĻž āĻāĻžāĻŽ āĻāĻŋāĻŽāĻžāĻ¨?
Given / āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§: Force (F) = 50 N , Distance (d) = 4 m
Formula / āĻ¸ā§āĻ¤ā§ā§°: Work (W) = Force × Distance (āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ)
Calculation / āĻāĻŖāĻ¨āĻž: W = 50 × 4 = 200 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: Work done = 200 Joules (āĻā§°āĻž āĻāĻžāĻŽ = ā§¨ā§Ļā§Ļ āĻā§āĻ˛)
Q2. A man exerts a force of 120 N to push a cart through a distance of 15 m. Calculate the work done by him.
āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻ¨ āĻŽāĻžāĻ¨ā§āĻšā§ āĻāĻāĻž āĻāĻžāĻĄāĻŧā§ ā§§ā§¨ā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ ā§§ā§Ģ āĻŽāĻŋāĻāĻžā§° āĻĻā§ā§°āĻ¤ā§āĻŦāĻ˛ā§ āĻ ā§āĻ˛āĻŋ āĻ˛ā§ āĻ¯āĻžāĻ¯āĻŧāĨ¤ āĻ¤ā§āĻāĻā§° āĻĻā§āĻŦāĻžā§°āĻž āĻā§°āĻž āĻāĻžāĻŽ āĻāĻŋāĻŽāĻžāĻ¨?
Given / āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§: Force (F) = 120 N , Distance (d) = 15 m
Formula / āĻ¸ā§āĻ¤ā§ā§°: Work (W) = Force × Distance (āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ)
Calculation / āĻāĻŖāĻ¨āĻž: W = 120 × 15 = 1800 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: Work done = 1800 Joules (āĻā§°āĻž āĻāĻžāĻŽ = ā§§ā§Žā§Ļā§Ļ āĻā§āĻ˛)
Q3. A force of 75 N is applied to move a stone through a distance of 8 m. Calculate the work done.
āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻž āĻļāĻŋāĻ˛āĻ ā§ā§Ģ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ ā§Ž āĻŽāĻŋāĻāĻžā§° āĻĻā§ā§°āĻ¤ā§āĻŦāĻ˛ā§ āĻ¨āĻŋā§āĻž āĻš’āĻ˛āĨ¤ āĻā§°āĻž āĻāĻžāĻŽ āĻāĻŋāĻŽāĻžāĻ¨?
Given / āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§: Force (F) = 75 N , Distance (d) = 8 m
Formula / āĻ¸ā§āĻ¤ā§ā§°: Work (W) = Force × Distance (āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ)
Calculation / āĻāĻŖāĻ¨āĻž: W = 75 × 8 = 600 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: Work done = 600 Joules (āĻā§°āĻž āĻāĻžāĻŽ = ā§Ŧā§Ļā§Ļ āĻā§āĻ˛)
Q4. A force of 90 N is applied to push a box through a distance of 12 m. Find the work done. āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻž āĻŦāĻžāĻāĻāĻ¤ ā§¯ā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ ā§§ā§¨ āĻŽāĻŋāĻāĻžā§° āĻĻā§ā§°āĻ¤ā§āĻŦāĻ˛ā§ āĻ ā§āĻ˛āĻŋ āĻ¨āĻŋā§āĻž āĻš’āĻ˛āĨ¤ āĻā§°āĻž āĻāĻžāĻŽ āĻāĻŋāĻŽāĻžāĻ¨ ?
Given / āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§: Force (F) = 90 N , Distance (d) = 12 m
Formula / āĻ¸ā§āĻ¤ā§ā§°: Work (W) = Force × Distance (āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ)
Calculation / āĻāĻŖāĻ¨āĻž: W = 90 × 12 = 1080 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: Work done = 1080 Joules (āĻā§°āĻž āĻāĻžāĻŽ = ā§§ā§Ļā§Žā§Ļ āĻā§āĻ˛)
Q5. A force of 100 N is used to move a box through a distance of 5 m. Calculate the work done. āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻž āĻŦāĻžāĻāĻ ā§§ā§Ļā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ ā§Ģ āĻŽāĻŋāĻāĻžā§° āĻĻā§ā§°āĻ¤ā§āĻŦāĻ˛ā§ āĻ¨āĻŋā§āĻž āĻš’āĻ˛āĨ¤ āĻā§°āĻž āĻāĻžāĻŽ āĻāĻŋāĻŽāĻžāĻ¨?
Given / āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§: Force (F) = 100 N , Distance (d) = 5 m
Formula / āĻ¸ā§āĻ¤ā§ā§°: Work (W) = Force × Distance (āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ)
Calculation / āĻāĻŖāĻ¨āĻž: W = 100 × 5 = 500 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: Work done = 500 Joules (āĻā§°āĻž āĻāĻžāĻŽ = ā§Ģā§Ļā§Ļ āĻā§āĻ˛)
Q6. A force of 40 N moves an object through a distance of 6 m. Find the work done. āĻĒā§ā§°āĻļā§āĻ¨: ā§Ēā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ āĻāĻāĻž āĻŦāĻ¸ā§āĻ¤ā§ ā§Ŧ āĻŽāĻŋāĻāĻžā§° āĻ¸ā§°āĻžāĻ˛ā§āĨ¤ āĻā§°āĻž āĻāĻžāĻŽ āĻāĻŋāĻŽāĻžāĻ¨ ?
Given / āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§: F = 40 N, d = 6 m
Formula / āĻ¸ā§āĻ¤ā§ā§°: W = F × d (āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ)
Calculation / āĻāĻŖāĻ¨āĻž: W = 40 × 6 = 240 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: Work done = 240 Joules (āĻā§°āĻž āĻāĻžāĻŽ = ā§¨ā§Ēā§Ļ āĻā§āĻ˛)
Q7. A man pushes a cart with a force of 150 N through 10 m. āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻ¨ āĻŽāĻžāĻ¨ā§āĻšā§ ā§§ā§Ģā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ āĻāĻāĻž āĻāĻžāĻĄāĻŧā§ ā§§ā§Ļ āĻŽāĻŋāĻāĻžā§° āĻ ā§āĻ˛āĻŋāĻ˛ā§āĨ¤
Calculation: W = 150 × 10 = 1500 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: 1500 Joules / ā§§ā§Ģā§Ļā§Ļ āĻā§āĻ˛
Q8: A force of 25 N moves a body through 8 m. āĻĒā§ā§°āĻļā§āĻ¨: ā§¨ā§Ģ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ āĻāĻāĻž āĻŦāĻ¸ā§āĻ¤ā§ ā§Ž āĻŽāĻŋāĻāĻžā§° āĻ¸ā§°āĻžāĻ˛ā§āĨ¤
Calculation: W = 25 × 8 = 200 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: 200 Joules / ā§¨ā§Ļā§Ļ āĻā§āĻ˛
Q9: A box is pushed with a force of 60 N through 5 m. āĻĒā§ā§°āĻļā§āĻ¨: āĻāĻāĻž āĻŦāĻžāĻāĻ ā§Ŧā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ ā§Ģ āĻŽāĻŋāĻāĻžā§° āĻ ā§āĻ˛āĻŋāĻ˛ā§āĨ¤
Calculation: W = 60 × 5 = 300 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: 300 Joules / ā§Šā§Ļā§Ļ āĻā§āĻ˛
Q10. A force of 90 N acts on an object and moves it 4 m. āĻĒā§ā§°āĻļā§āĻ¨: ā§¯ā§Ļ N āĻŦāĻ˛ āĻĒā§ā§°āĻ¯āĻŧā§āĻ āĻā§°āĻŋ āĻāĻāĻž āĻŦāĻ¸ā§āĻ¤ā§ ā§Ē āĻŽāĻŋāĻāĻžā§° āĻ¸ā§°āĻžāĻ˛ā§āĨ¤
Calculation: W = 90 × 4 = 360 J
Ans / āĻāĻ¤ā§āĻ¤ā§°: 360 Joules / ā§Šā§Ŧā§Ļ āĻā§āĻ˛
Exam Tips :
- Always write: Given → Formula → Calculation → Answer
- Don’t forget units (J, N, m, kg)
- Steps clearly āĻĻā§āĻā§ā§ąāĻžāĻ˛ā§ full marks āĻĒā§ā§ąāĻž āĻ¯āĻžāĻ¯āĻŧ
- Always write Given, Formula, Calculation, Answer
- Use correct SI units
- Show full steps for full marks
- āĻ¸āĻĻāĻžāĻ¯āĻŧ : āĻĻāĻŋāĻ¯āĻŧāĻž āĻāĻā§ → āĻ¸ā§āĻ¤ā§ā§° → āĻāĻŖāĻ¨āĻž → āĻāĻ¤ā§āĻ¤ā§° āĻ˛āĻŋāĻāĻŋāĻŦ
- Work = Force × Distance → āĻāĻžāĻŽ = āĻŦāĻ˛ × āĻĻā§ā§°āĻ¤ā§āĻŦ
- Potential Energy = mgh → āĻ¸āĻŽā§āĻāĻžā§ąā§āĻ¯ āĻļāĻā§āĻ¤āĻŋ = mgh
- Kinetic Energy = ½ mv² → āĻāĻ¤āĻŋāĻļāĻā§āĻ¤āĻŋ = ½ mv²